We express 198 as 200 – 2 and use the subtraction square identity with a = 200 and b = 2. Working out the arithmetic components gives the final plain text answer.
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We express 117 as 100 + 10 + 7 and apply the three-term identity. Squaring each number and adding all the double-product combinations yields the correct numerical total.
We transform 193 into 200 – 7 and apply the subtraction identity with a = 200 and b = 7. Evaluating these components together gives the correct final numerical answer of 37249.
We take out the common factor 1/5 from the entire expression. The remaining polynomial inside is 9s square + 30sv + 25v square, which condenses smoothly into (3s + 5v) square.
We apply the standard square identity to this expression. By recognizing that 49x square is (7x) square and 4y square is (2y) square, we can easily write the final factors as (7x + 2y) square.