We match this with the identity a square + 2ab + b square. Here, 64p square is (8p) square and 4/9 q square is (2/3 q) square, which simplifies cleanly to the factor (8p + 2/3 q) square.
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We apply the standard square identity to this expression. By recognizing that 49x square is (7x) square and 4y square is (2y) square, we can easily write the final factors as (7x + 2y) square.
We express 205 as 200 + 5 and use our identity where a = 200 and b = 5. Calculating the individual parts and adding them up gives the final numerical answer.
We rewrite 64 as 60 + 4 to use the identity with a = 60 and b = 4. Summing the squares of 60 and 4 with their double product yields 4096.
Ayushree
Asked: In: Class 9 Maths
We substitute a = 3/4 s and b = 8t into the square identity. Squaring the terms independently and simplifying the middle multiplication step gives the final plain algebraic text solution.