1. (-30) ÷10 = (-30)x1/10 = -30x1/10 = -3 Exercise 1.4 Question 1 for more answers vist to: https://www.tiwariacademy.com/ncert-solutions/class-7/maths/chapter-1/

    (-30) ÷10 = (-30)x1/10 = -30×1/10 = -3

    Exercise 1.4 Question 1

    for more answers vist to:
    https://www.tiwariacademy.com/ncert-solutions/class-7/maths/chapter-1/

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  2. (-3) x (-9) = 27 Class 7 Maths Exercise 1.3 Questions 6, 7, 8, 9 for more answers vist to: https://www.tiwariacademy.com/ncert-solutions/class-7/maths/chapter-1/

    (-3) x (-9) = 27

    Class 7 Maths Exercise 1.3 Questions 6, 7, 8, 9

    for more answers vist to:
    https://www.tiwariacademy.com/ncert-solutions/class-7/maths/chapter-1/

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  3. Given: Profit of 1 bag of white cement = ₹ 8 And Loss of 1 bag of grey cement = ₹ 5 (a) Profit on selling 3000 bags of white cement = 3000 x ₹ 8 = ₹ 24,000 Loss of selling 5000 bags of grey cement = 5000 x ₹ 5 = ₹ 25,000 Since Profit < Loss Therefore, his total loss on selling the grey cement bagRead more

    Given: Profit of 1 bag of white cement = ₹ 8
    And Loss of 1 bag of grey cement = ₹ 5
    (a) Profit on selling 3000 bags of white cement = 3000 x ₹ 8 = ₹ 24,000
    Loss of selling 5000 bags of grey cement = 5000 x ₹ 5 = ₹ 25,000
    Since Profit < Loss
    Therefore, his total loss on selling the grey cement bags = Loss – Profit
    = ₹ 25,000 – ₹ 24,000
    = ₹ 1,000
    Thus, he has lost of `₹1,000 on selling the grey cement bags.

    (b) Let the number of bags of white cement be x.
    According to question, Loss = Profit
    ∴ 5 x 6,400 = x X 8
    ⇒ x = 5×6400/8 = 5000 bags

    Thus, he must sell 4000 white cement bags to have neither profit nor loss.

    Class 7 Maths Exercise 1.3 Questions 6, 7, 8, 9

    for more answers vist to:
    https://www.tiwariacademy.com/ncert-solutions/class-7/maths/chapter-1/

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  4. (i) Mohan gets marks for four correct questions = 4 x 5 = 20 He gets marks for six incorrect questions = 6 x (–2) = –12 Therefore, total scores of Mohan = (4 x 5) + [6 x (–2)] = 20 – 12 = 8 Thus, Mohan gets 8 marks in a class test. (ii) Reshma gets marks for five correct questions = 5 x 5 = 25 She gRead more

    (i) Mohan gets marks for four correct questions = 4 x 5 = 20
    He gets marks for six incorrect questions = 6 x (–2) = –12
    Therefore, total scores of Mohan = (4 x 5) + [6 x (–2)]
    = 20 – 12 = 8
    Thus, Mohan gets 8 marks in a class test.

    (ii) Reshma gets marks for five correct questions = 5 x 5 = 25
    She gets marks for five incorrect questions = 5 x (–2) = –10
    Therefore, total score of Resham = 25 + (–10) = 15
    Thus, Reshma gets 15 marks in a class test.

    (iii) Heena gets marks for two correct questions = 2 x 5 = 10
    She gets marks for five incorrect questions = 5 x (–2) = –10
    Therefore, total score of Resham = 10 + (–10) = 0
    Thus, Reshma gets 0 marks in a class test.

    Class 7 Maths Exercise 1.3 Questions 6, 7, 8, 9

    for more answers vist to:
    https://www.tiwariacademy.com/ncert-solutions/class-7/maths/chapter-1/

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  5. Given: Present room temperature = 40°C Decreasing the temperature every hour = 5°C Room temperature after 10 hours = 40°C + 10 x (–5°C ) = 40°C – 50°C = – 10°C Thus, the room temperature after 10 hours is – 10°C after the process begins. Class 7 Maths Exercise 1.3 Questions 6, 7, 8, 9 for more answeRead more

    Given: Present room temperature = 40°C
    Decreasing the temperature every hour = 5°C
    Room temperature after 10 hours = 40°C + 10 x (–5°C )
    = 40°C – 50°C
    = – 10°C
    Thus, the room temperature after 10 hours is – 10°C after the process begins.

    Class 7 Maths Exercise 1.3 Questions 6, 7, 8, 9

    for more answers vist to:
    https://www.tiwariacademy.com/ncert-solutions/class-7/maths/chapter-1/

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