26 x (-48) + (-48) x (-36) ⇒ (-48)x[26+(-36)] [Distributive property] ⇒ (-48) x (-10) ⇒ 480 Class 7 Maths Exercise 1.3 Questions 4, 5 for more answers vist to: https://www.tiwariacademy.com/ncert-solutions/class-7/maths/chapter-1/
26 x (-48) + (-48) x (-36)
⇒ (-48)x[26+(-36)] [Distributive property]
⇒ (-48) x (-10)
⇒ 480
(i) (-1) x a = -a, where a is an integer. (ii) (a) (–1)x(-22) = 22 (b) (–1)x37=-37 (c) (–1)x0=0 Class 7 Maths Exercise 1.3 Questions 1, 2, 3 for more answers vist to: https://www.tiwariacademy.com/ncert-solutions/class-7/maths/chapter-1/
(i) (-1) x a = -a, where a is an integer.
(ii) (a) (–1)x(-22) = 22
(b) (–1)x37=-37
(c) (–1)x0=0
(a) 3 x (–1) = -3 (b) (–1) x 225 = -225 Class 7 Maths Exercise 1.3 Questions 1, 2, 3 for more answers vist to: https://www.tiwariacademy.com/ncert-solutions/class-7/maths/chapter-1/
Find the product, using suitable properties: 26 x (-48) + (-48) x (-36)
26 x (-48) + (-48) x (-36) ⇒ (-48)x[26+(-36)] [Distributive property] ⇒ (-48) x (-10) ⇒ 480 Class 7 Maths Exercise 1.3 Questions 4, 5 for more answers vist to: https://www.tiwariacademy.com/ncert-solutions/class-7/maths/chapter-1/
26 x (-48) + (-48) x (-36)
⇒ (-48)x[26+(-36)] [Distributive property]
⇒ (-48) x (-10)
⇒ 480
Class 7 Maths Exercise 1.3 Questions 4, 5
for more answers vist to:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-7/maths/chapter-1/
Starting from (-1) x5, write various products showing some patterns to show (-1) x (-1) = 1.
(-1)x5 = -5 (-1)x4 = -4 (-1)x3 = -3 (-1)x2 = -2 (-1)x1 = -1 (-1)x0 = 0 (-1)x(-1)=1 Class 7 Maths Exercise 1.3 Questions 4, 5 for more answers vist to: https://www.tiwariacademy.com/ncert-solutions/class-7/maths/chapter-1/
(-1)x5 = -5 (-1)x4 = -4
(-1)x3 = -3 (-1)x2 = -2
(-1)x1 = -1 (-1)x0 = 0
(-1)x(-1)=1
Class 7 Maths Exercise 1.3 Questions 4, 5
for more answers vist to:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-7/maths/chapter-1/
(i) For any integer a, what is (-1) x a equal to? (ii) Determine the integer whose product with(-1) is: (a) –22 (b) 37 (c) 0
(i) (-1) x a = -a, where a is an integer. (ii) (a) (–1)x(-22) = 22 (b) (–1)x37=-37 (c) (–1)x0=0 Class 7 Maths Exercise 1.3 Questions 1, 2, 3 for more answers vist to: https://www.tiwariacademy.com/ncert-solutions/class-7/maths/chapter-1/
(i) (-1) x a = -a, where a is an integer.
(ii) (a) (–1)x(-22) = 22
(b) (–1)x37=-37
(c) (–1)x0=0
Class 7 Maths Exercise 1.3 Questions 1, 2, 3
for more answers vist to:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-7/maths/chapter-1/
Verify the following: (a) 18 x [7 + (–3)] = [18 x 7] + [18 x (–3)] (b) (–21) x [(–4) + (–6)] = [(–21) x (-4)] + [(–21) x (–6)]
(a) 18 x [7 + (–3)] = [18 x 7] + [18 x (–3)] ⇒ 18 X 4 = 126+(-54) ⇒ 72 = 72 ⇒ L.H.S = R.H.S Hence verified. (b) (–21) x [(–4) + (–6)] = [(–21) x (-4)] + [(–21) x (–6)] ⇒ (–21) x (-10) = 84 + 126 ⇒ 210 = 210 ⇒ L.H.S = R.H.S Hence verified. Class 7 Maths Exercise 1.3 Questions 1, 2, 3 for more answersRead more
(a) 18 x [7 + (–3)] = [18 x 7] + [18 x (–3)]
⇒ 18 X 4 = 126+(-54)
⇒ 72 = 72
⇒ L.H.S = R.H.S
Hence verified.
(b) (–21) x [(–4) + (–6)] = [(–21) x (-4)] + [(–21) x (–6)]
⇒ (–21) x (-10) = 84 + 126
⇒ 210 = 210
⇒ L.H.S = R.H.S
Hence verified.
Class 7 Maths Exercise 1.3 Questions 1, 2, 3
for more answers vist to:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-7/maths/chapter-1/
Find the each of the following products: (a) 3 x (–1) (b) (–1) x 225
(a) 3 x (–1) = -3 (b) (–1) x 225 = -225 Class 7 Maths Exercise 1.3 Questions 1, 2, 3 for more answers vist to: https://www.tiwariacademy.com/ncert-solutions/class-7/maths/chapter-1/
(a) 3 x (–1) = -3
(b) (–1) x 225 = -225
Class 7 Maths Exercise 1.3 Questions 1, 2, 3
for more answers vist to:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-7/maths/chapter-1/