The correct answer is (a) spheres. At a large distance, a collection of charges with a nonzero total sum behaves like a point charge. The equipotential surfaces around a point charge are spherical, centered on the charge. This follows from the equation V= 1/4πϵ Q/r, which depends only on distance r.Read more
The correct answer is (a) spheres.
At a large distance, a collection of charges with a nonzero total sum behaves like a point charge. The equipotential surfaces around a point charge are spherical, centered on the charge. This follows from the equation V= 1/4πϵ Q/r, which depends only on distance r.
The correct answer is (c) Both force and torque. In a non-uniform electric field, an electric dipole experiences torque that aligns it with the field and force due to the field gradient. The force arises because the field strength differs at each dipole charge, causing a net translational motion. ToRead more
The correct answer is (c) Both force and torque.
In a non-uniform electric field, an electric dipole experiences torque that aligns it with the field and force due to the field gradient. The force arises because the field strength differs at each dipole charge, causing a net translational motion. Torque tends to rotate the dipole, aligning it with the field direction.
The correct answer is (c) neutral or positively charged. Since X is negatively charged and repelled by Y, object Y must also be negatively charged. Object Z is attracted to Y, meaning Z could be either positively charged (opposite charges attract) or neutral (since a charged object can attract a neuRead more
The correct answer is (c) neutral or positively charged.
Since X is negatively charged and repelled by Y, object Y must also be negatively charged. Object Z is attracted to Y, meaning Z could be either positively charged (opposite charges attract) or neutral (since a charged object can attract a neutral object due to polarization).
The correct answer is (a) no net charge is enclosed by the surface. According to Gauss's law, the net electric flux through a closed surface is given by Φ = Qenc/ϵ0 . If the flux is zero, the net charge enclosed (Qenc) must also be zero, meaning either no charge is inside or equal positive and negaRead more
The correct answer is (a) no net charge is enclosed by the surface.
According to Gauss’s law, the net electric flux through a closed surface is given by
Φ = Qenc/ϵ0
. If the flux is zero, the net charge enclosed (Qenc) must also be zero, meaning either no charge is inside or equal positive and negative charges cancel out.
The correct answer is (d) 1/2 µF. For capacitors in series, the equivalent capacitance is given by: 1/Ceq = 1/C₁ + 1/C₂ + 1/C₃ Substituting C1 = 2 pF, C₂ = 3 pF and C₃ = 6 pF, we get Ceq = 1 pF = 1/2 µF. For more visit here: https://www.tiwariacademy.com/ncert-solutions/class-12/physics/chapter-2/
The correct answer is (d) 1/2 µF.
For capacitors in series, the equivalent capacitance is given by:
1/Ceq = 1/C₁ + 1/C₂ + 1/C₃
Substituting C1 = 2 pF, C₂ = 3 pF and C₃ = 6 pF, we get Ceq = 1 pF = 1/2 µF.
The correct answer is (a) 1 µF. The energy stored in a capacitor is given by U = 1/2CV². The decrease in energy is: ΔU = 1/2(2 × 10⁻⁶ - X) (200)² = 2 × 10⁻²J Solving for X, we get 1 µF. For more visit here: https://www.tiwariacademy.com/ncert-solutions/class-12/physics/chapter-2/
The correct answer is (a) 1 µF.
The energy stored in a capacitor is given by
U = 1/2CV². The decrease in energy is:
ΔU = 1/2(2 × 10⁻⁶ – X) (200)² = 2 × 10⁻²J
Solving for X, we get 1 µF.
The correct answer is (c) actual transfer of electrons. Charging occurs due to the movement of electrons between objects. Protons and neutrons remain bound within the atomic nucleus, while electrons, being loosely bound in atoms, can be transferred through friction, conduction, or induction. This trRead more
The correct answer is (c) actual transfer of electrons.
Charging occurs due to the movement of electrons between objects. Protons and neutrons remain bound within the atomic nucleus, while electrons, being loosely bound in atoms, can be transferred through friction, conduction, or induction. This transfer creates an imbalance of charge, leading to electrostatic effects.
The correct answer is (d) Zero. On an equipotential surface, all points have the same electric potential. Since work done (W = qΔV) depends on the potential difference (ΔV) and ΔV = 0 on an equipotential surface, no work is required to move an electron between points. For more visit here: https://wwRead more
The correct answer is (d) Zero.
On an equipotential surface, all points have the same electric potential. Since work done (W = qΔV) depends on the potential difference (ΔV) and ΔV = 0 on an equipotential surface, no work is required to move an electron between points.
The correct answer is (c) Zero. The work done in moving a charge in an electric field is given by W = qΔV. Since the charge is at the center of the square, all corners are at the same potential. The potential difference (ΔV) between diagonally opposite corners is zero, making the work done also zeroRead more
The correct answer is (c) Zero.
The work done in moving a charge in an electric field is given by W = qΔV. Since the charge is at the center of the square, all corners are at the same potential. The potential difference (ΔV) between diagonally opposite corners is zero, making the work done also zero, regardless of the path taken.
(c) electric intensity The SI unit of electric field intensity (also called electric field strength) is newtons per coulomb (N/C). This represents the force per unit charge exerted on a small positive test charge placed in the field. For more visit here: https://www.tiwariacademy.com/ncert-solutionsRead more
(c) electric intensity
The SI unit of electric field intensity (also called electric field strength) is newtons per coulomb (N/C). This represents the force per unit charge exerted on a small positive test charge placed in the field.
Equipotentials at a large distance from a collection of charges, whose total sum is not zero are
The correct answer is (a) spheres. At a large distance, a collection of charges with a nonzero total sum behaves like a point charge. The equipotential surfaces around a point charge are spherical, centered on the charge. This follows from the equation V= 1/4πϵ Q/r, which depends only on distance r.Read more
The correct answer is (a) spheres.
At a large distance, a collection of charges with a nonzero total sum behaves like a point charge. The equipotential surfaces around a point charge are spherical, centered on the charge. This follows from the equation V= 1/4πϵ Q/r, which depends only on distance r.
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An electric dipole placed in a non-uniform electric field will experience
The correct answer is (c) Both force and torque. In a non-uniform electric field, an electric dipole experiences torque that aligns it with the field and force due to the field gradient. The force arises because the field strength differs at each dipole charge, causing a net translational motion. ToRead more
The correct answer is (c) Both force and torque.
In a non-uniform electric field, an electric dipole experiences torque that aligns it with the field and force due to the field gradient. The force arises because the field strength differs at each dipole charge, causing a net translational motion. Torque tends to rotate the dipole, aligning it with the field direction.
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A negatively charged object X is repelled by another charged object Y. However, an object Z is attracted to object Y. Which of the following is the most possibility for object Z?
The correct answer is (c) neutral or positively charged. Since X is negatively charged and repelled by Y, object Y must also be negatively charged. Object Z is attracted to Y, meaning Z could be either positively charged (opposite charges attract) or neutral (since a charged object can attract a neuRead more
The correct answer is (c) neutral or positively charged.
Since X is negatively charged and repelled by Y, object Y must also be negatively charged. Object Z is attracted to Y, meaning Z could be either positively charged (opposite charges attract) or neutral (since a charged object can attract a neutral object due to polarization).
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If net electric flux through a closed surface is zero, we can infer
The correct answer is (a) no net charge is enclosed by the surface. According to Gauss's law, the net electric flux through a closed surface is given by Φ = Qenc/ϵ0 . If the flux is zero, the net charge enclosed (Qenc) must also be zero, meaning either no charge is inside or equal positive and negaRead more
The correct answer is (a) no net charge is enclosed by the surface.
According to Gauss’s law, the net electric flux through a closed surface is given by
Φ = Qenc/ϵ0
. If the flux is zero, the net charge enclosed (Qenc) must also be zero, meaning either no charge is inside or equal positive and negative charges cancel out.
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Three capacitors 2 pF, 3 pF and 6 pF are joined in series with eachother. The equivalent capacitance is
The correct answer is (d) 1/2 µF. For capacitors in series, the equivalent capacitance is given by: 1/Ceq = 1/C₁ + 1/C₂ + 1/C₃ Substituting C1 = 2 pF, C₂ = 3 pF and C₃ = 6 pF, we get Ceq = 1 pF = 1/2 µF. For more visit here: https://www.tiwariacademy.com/ncert-solutions/class-12/physics/chapter-2/
The correct answer is (d) 1/2 µF.
For capacitors in series, the equivalent capacitance is given by:
1/Ceq = 1/C₁ + 1/C₂ + 1/C₃
Substituting C1 = 2 pF, C₂ = 3 pF and C₃ = 6 pF, we get Ceq = 1 pF = 1/2 µF.
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variable capacitor is connected to a 200 V battery. If its capacitance is changed from 2 µF to X µF, the decrease in energy of the capacitor is 2 X 10⁻² J. The value of X is
The correct answer is (a) 1 µF. The energy stored in a capacitor is given by U = 1/2CV². The decrease in energy is: ΔU = 1/2(2 × 10⁻⁶ - X) (200)² = 2 × 10⁻²J Solving for X, we get 1 µF. For more visit here: https://www.tiwariacademy.com/ncert-solutions/class-12/physics/chapter-2/
The correct answer is (a) 1 µF.
The energy stored in a capacitor is given by
U = 1/2CV². The decrease in energy is:
ΔU = 1/2(2 × 10⁻⁶ – X) (200)² = 2 × 10⁻²J
Solving for X, we get 1 µF.
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The basic couse of charging is
The correct answer is (c) actual transfer of electrons. Charging occurs due to the movement of electrons between objects. Protons and neutrons remain bound within the atomic nucleus, while electrons, being loosely bound in atoms, can be transferred through friction, conduction, or induction. This trRead more
The correct answer is (c) actual transfer of electrons.
Charging occurs due to the movement of electrons between objects. Protons and neutrons remain bound within the atomic nucleus, while electrons, being loosely bound in atoms, can be transferred through friction, conduction, or induction. This transfer creates an imbalance of charge, leading to electrostatic effects.
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Work done in carrying an electron from AxoB lying on an equipotential surface of one volt potential is
The correct answer is (d) Zero. On an equipotential surface, all points have the same electric potential. Since work done (W = qΔV) depends on the potential difference (ΔV) and ΔV = 0 on an equipotential surface, no work is required to move an electron between points. For more visit here: https://wwRead more
The correct answer is (d) Zero.
On an equipotential surface, all points have the same electric potential. Since work done (W = qΔV) depends on the potential difference (ΔV) and ΔV = 0 on an equipotential surface, no work is required to move an electron between points.
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A charge of 10 p. C lies at the centre of a square. Work done in carrying a charge of 2 p C from one comer of square to the diagonally opposite comer is
The correct answer is (c) Zero. The work done in moving a charge in an electric field is given by W = qΔV. Since the charge is at the center of the square, all corners are at the same potential. The potential difference (ΔV) between diagonally opposite corners is zero, making the work done also zeroRead more
The correct answer is (c) Zero.
The work done in moving a charge in an electric field is given by W = qΔV. Since the charge is at the center of the square, all corners are at the same potential. The potential difference (ΔV) between diagonally opposite corners is zero, making the work done also zero, regardless of the path taken.
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N/C is the SI unit of
(c) electric intensity The SI unit of electric field intensity (also called electric field strength) is newtons per coulomb (N/C). This represents the force per unit charge exerted on a small positive test charge placed in the field. For more visit here: https://www.tiwariacademy.com/ncert-solutionsRead more
(c) electric intensity
The SI unit of electric field intensity (also called electric field strength) is newtons per coulomb (N/C). This represents the force per unit charge exerted on a small positive test charge placed in the field.
For more visit here:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-12/physics/chapter-2/