1. The correct answer is (b) 4. The energy stored in a capacitor is given by U = (1/2) C V². When the potential V is doubled, the new energy becomes U' = (1/2) C (2V)² = (1/2) C × 4V² = 4U. Thus, the energy stored in the capacitor increases 4 times its initial value. For more visit here: https://www.tiRead more

    The correct answer is (b) 4.
    The energy stored in a capacitor is given by U = (1/2) C V². When the potential V is doubled, the new energy becomes U’ = (1/2) C (2V)² = (1/2) C × 4V² = 4U. Thus, the energy stored in the capacitor increases 4 times its initial value.

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  2. The correct answer is: (a) increases When capacitors are connected in parallel, their total capacitance is the sum of their individual capacitances: Ceq = C₁ + C₂ + C₃ +… This increases the overall capacitance, allowing the system to store more charge at the same voltage. For more visit here: https:Read more

    The correct answer is: (a) increases
    When capacitors are connected in parallel, their total capacitance is the sum of their individual capacitances: Ceq = C₁ + C₂ + C₃ +…
    This increases the overall capacitance, allowing the system to store more charge at the same voltage.

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  3. The correct answer is: (c) charge When capacitors are connected in series, the same charge flows through each capacitor. However, the potential difference across each capacitor may vary depending on its capacitance, while the total capacitance is less than the smallest individual capacitor in the seRead more

    The correct answer is:
    (c) charge
    When capacitors are connected in series, the same charge flows through each capacitor. However, the potential difference across each capacitor may vary depending on its capacitance, while the total capacitance is less than the smallest individual capacitor in the series.

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    https://www.tiwariacademy.com/ncert-solutions/class-12/physics/chapter-2/

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  4. When air is replaced by mica, which has a dielectric constant of 6, the capacitance of the capacitor increases by a factor of 6. This is because the capacitance is directly proportional to the dielectric constant of the material between the plates. Thus, replacing air with mica increases the capacitRead more

    When air is replaced by mica, which has a dielectric constant of 6, the capacitance of the capacitor increases by a factor of 6. This is because the capacitance is directly proportional to the dielectric constant of the material between the plates. Thus, replacing air with mica increases the capacitance sixfold.

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    https://www.tiwariacademy.com/ncert-solutions/class-12/physics/chapter-2/

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