The correct answer is (a) 1 µF. The energy stored in a capacitor is given by U = 1/2CV². The decrease in energy is: ΔU = 1/2(2 × 10⁻⁶ - X) (200)² = 2 × 10⁻²J Solving for X, we get 1 µF. For more visit here: https://www.tiwariacademy.com/ncert-solutions/class-12/physics/chapter-2/
The correct answer is (a) 1 µF.
The energy stored in a capacitor is given by
U = 1/2CV². The decrease in energy is:
ΔU = 1/2(2 × 10⁻⁶ – X) (200)² = 2 × 10⁻²J
Solving for X, we get 1 µF.
The correct answer is (c) actual transfer of electrons. Charging occurs due to the movement of electrons between objects. Protons and neutrons remain bound within the atomic nucleus, while electrons, being loosely bound in atoms, can be transferred through friction, conduction, or induction. This trRead more
The correct answer is (c) actual transfer of electrons.
Charging occurs due to the movement of electrons between objects. Protons and neutrons remain bound within the atomic nucleus, while electrons, being loosely bound in atoms, can be transferred through friction, conduction, or induction. This transfer creates an imbalance of charge, leading to electrostatic effects.
The correct answer is (d) Zero. On an equipotential surface, all points have the same electric potential. Since work done (W = qΔV) depends on the potential difference (ΔV) and ΔV = 0 on an equipotential surface, no work is required to move an electron between points. For more visit here: https://wwRead more
The correct answer is (d) Zero.
On an equipotential surface, all points have the same electric potential. Since work done (W = qΔV) depends on the potential difference (ΔV) and ΔV = 0 on an equipotential surface, no work is required to move an electron between points.
The correct answer is (c) Zero. The work done in moving a charge in an electric field is given by W = qΔV. Since the charge is at the center of the square, all corners are at the same potential. The potential difference (ΔV) between diagonally opposite corners is zero, making the work done also zeroRead more
The correct answer is (c) Zero.
The work done in moving a charge in an electric field is given by W = qΔV. Since the charge is at the center of the square, all corners are at the same potential. The potential difference (ΔV) between diagonally opposite corners is zero, making the work done also zero, regardless of the path taken.
(c) electric intensity The SI unit of electric field intensity (also called electric field strength) is newtons per coulomb (N/C). This represents the force per unit charge exerted on a small positive test charge placed in the field. For more visit here: https://www.tiwariacademy.com/ncert-solutionsRead more
(c) electric intensity
The SI unit of electric field intensity (also called electric field strength) is newtons per coulomb (N/C). This represents the force per unit charge exerted on a small positive test charge placed in the field.
variable capacitor is connected to a 200 V battery. If its capacitance is changed from 2 µF to X µF, the decrease in energy of the capacitor is 2 X 10⁻² J. The value of X is
The correct answer is (a) 1 µF. The energy stored in a capacitor is given by U = 1/2CV². The decrease in energy is: ΔU = 1/2(2 × 10⁻⁶ - X) (200)² = 2 × 10⁻²J Solving for X, we get 1 µF. For more visit here: https://www.tiwariacademy.com/ncert-solutions/class-12/physics/chapter-2/
The correct answer is (a) 1 µF.
The energy stored in a capacitor is given by
U = 1/2CV². The decrease in energy is:
ΔU = 1/2(2 × 10⁻⁶ – X) (200)² = 2 × 10⁻²J
Solving for X, we get 1 µF.
For more visit here:
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The basic couse of charging is
The correct answer is (c) actual transfer of electrons. Charging occurs due to the movement of electrons between objects. Protons and neutrons remain bound within the atomic nucleus, while electrons, being loosely bound in atoms, can be transferred through friction, conduction, or induction. This trRead more
The correct answer is (c) actual transfer of electrons.
Charging occurs due to the movement of electrons between objects. Protons and neutrons remain bound within the atomic nucleus, while electrons, being loosely bound in atoms, can be transferred through friction, conduction, or induction. This transfer creates an imbalance of charge, leading to electrostatic effects.
For more visit here:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-12/physics/chapter-2/
Work done in carrying an electron from AxoB lying on an equipotential surface of one volt potential is
The correct answer is (d) Zero. On an equipotential surface, all points have the same electric potential. Since work done (W = qΔV) depends on the potential difference (ΔV) and ΔV = 0 on an equipotential surface, no work is required to move an electron between points. For more visit here: https://wwRead more
The correct answer is (d) Zero.
On an equipotential surface, all points have the same electric potential. Since work done (W = qΔV) depends on the potential difference (ΔV) and ΔV = 0 on an equipotential surface, no work is required to move an electron between points.
For more visit here:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-12/physics/chapter-2/
A charge of 10 p. C lies at the centre of a square. Work done in carrying a charge of 2 p C from one comer of square to the diagonally opposite comer is
The correct answer is (c) Zero. The work done in moving a charge in an electric field is given by W = qΔV. Since the charge is at the center of the square, all corners are at the same potential. The potential difference (ΔV) between diagonally opposite corners is zero, making the work done also zeroRead more
The correct answer is (c) Zero.
The work done in moving a charge in an electric field is given by W = qΔV. Since the charge is at the center of the square, all corners are at the same potential. The potential difference (ΔV) between diagonally opposite corners is zero, making the work done also zero, regardless of the path taken.
For more visit here:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-12/physics/chapter-2/
N/C is the SI unit of
(c) electric intensity The SI unit of electric field intensity (also called electric field strength) is newtons per coulomb (N/C). This represents the force per unit charge exerted on a small positive test charge placed in the field. For more visit here: https://www.tiwariacademy.com/ncert-solutionsRead more
(c) electric intensity
The SI unit of electric field intensity (also called electric field strength) is newtons per coulomb (N/C). This represents the force per unit charge exerted on a small positive test charge placed in the field.
For more visit here:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-12/physics/chapter-2/