(i) Total mixture is 500 g. Sugar concentration is 15 percent, flour is 84 percent and sodium hydrogencarbonate is 1 percent by mass. (ii) Copper is 84 g and zinc is 36 g.
Discussion Forum Latest Questions
Kriti
Asked: In: Class 9 Science
For A, acceleration = 1 m s⁻² and displacement in 5 s = 12.5 m. For B, acceleration = 0.3 m s⁻² and displacement in 10 s = 15 m. Their velocity-time graphs are straight lines from the origin.
Kriti
Asked: In: Class 9 Science
For the first 120 s, displacement = 6 × 120 = 720 m. During the next 6 s, displacement = 6 × 6 + ½ × 1 × 6² = 54 m. Total displacement = 774 m.
a car continues to move with a constant velocity of 6 m s⁻¹a constant acceleration 1 m s⁻² for 6 secondsa state highwayclass 9 science chapter 4 describing motion around us solutionsexploration class 9 chapter 4 describing motion around us solutionsncert solutions for class 9 science exploration chapter 4
Kriti
Asked: In: Class 9 Science
The distance travelled is approximately equal to the area under the velocity-time graph. Estimating the areas of the trapeziums from the graph gives a total distance of approximately 45 km.
cbse released new book science exploration chapter 4 solved (2026-27)describing motion around us – class 9 science chapter 4 solutionsgirl is preparing for her first marathon by running on a straight roadncert solutions – describing motion around usthe graph (fig. 4.31) depicts her velocity versus time
Kriti
Asked: In: Class 9 Science
For constant velocity, the area from 20–100 s is a rectangle: 3 × 80 = 240 m. For decreasing velocity, area from 100–120 s = ½(3+2)×20 = 50 m. Total displacement = 320 m; average acceleration = (2−0)/120 = 0.0167 ...
calculate the displacement and average acceleration in the 120 s time interval.cbse class 9 science exploration chapter 4 describing motion around us solutionsclass 9 science exploration chapter 4 question answerclass 9 science exploration chapter 4 solutionsvelocity-time graph from 0 s to 120 s for a cyclist