Let’s factorise 500: 500 = 2² × 5³ For a number to be a cube, all prime factors must appear in triplets. Here, the factor 2 appears only twice, which cannot make a group of three. Therefore, 500 is not a perfect cube, as it cannot be written as the cube of any integer. For more NCERT SolutionRead more
Let’s factorise 500:
500 = 2² × 5³
For a number to be a cube, all prime factors must appear in triplets. Here, the factor 2 appears only twice, which cannot make a group of three. Therefore, 500 is not a perfect cube, as it cannot be written as the cube of any integer.
For more NCERT Solutions for Class 8 Mathematics Ganita Prakash Chapter 1 A Square and A Cube Extra Questions & Answer:
To check if 3375 is a cube, we do prime factorisation: 3375 = 3³ × 5³ We can group the factors as (3 × 5)³ = 15³ = 3375. Since the prime factors can be grouped into three equal parts, this confirms that 3375 is a perfect cube. Hence, the cube root of 3375 is 15. For more NCERT Solutions for CRead more
To check if 3375 is a cube, we do prime factorisation:
3375 = 3³ × 5³
We can group the factors as (3 × 5)³ = 15³ = 3375. Since the prime factors can be grouped into three equal parts, this confirms that 3375 is a perfect cube.
Hence, the cube root of 3375 is 15.
For more NCERT Solutions for Class 8 Mathematics Ganita Prakash Chapter 1 A Square and A Cube Extra Questions & Answer:
A taxicab number is a number expressible as a sum of two cubes in two ways. For 4104: → 2³ + 16³ = 8 + 4096 = 4104 → 9³ + 15³ = 729 + 3375 = 4104 For 13832: → 2³ + 24³ = 8 + 13824 = 13832 → 18³ + 20³ = 5832 + 8000 = 13832 Hence, both 4104 and 13832 are taxicab numbers. For more NCERT SolutionRead more
A taxicab number is a number expressible as a sum of two cubes in two ways.
For 4104:
→ 2³ + 16³ = 8 + 4096 = 4104
→ 9³ + 15³ = 729 + 3375 = 4104
For 13832:
→ 2³ + 24³ = 8 + 13824 = 13832
→ 18³ + 20³ = 5832 + 8000 = 13832
Hence, both 4104 and 13832 are taxicab numbers.
For more NCERT Solutions for Class 8 Mathematics Ganita Prakash Chapter 1 A Square and A Cube Extra Questions & Answer:
A number ending with two zeros is divisible by 100. When cubed, the number is multiplied by itself three times. That means 100 × 100 × 100 = 1,000,000, which has six zeros. So, even if a number ends in two zeros, its cube will have more than two. Hence, a cube cannot end in exactly two zeros. It musRead more
A number ending with two zeros is divisible by 100. When cubed, the number is multiplied by itself three times. That means 100 × 100 × 100 = 1,000,000, which has six zeros. So, even if a number ends in two zeros, its cube will have more than two. Hence, a cube cannot end in exactly two zeros. It must end in zero or at least three or more zeros.
For more NCERT Solutions for Class 8 Mathematics Ganita Prakash Chapter 1 A Square and A Cube Extra Questions & Answer:
Cubes with: • 1 digit → 1³ = 1, 2³ = 8 • 2 digits → 3³ = 27 to 4³ = 64 • 3 digits → 5³ = 125 to 9³ = 729 Only a few cubes lie in each range. There are fewer cube numbers than squares in low ranges. For example, there are only 2 cubes below 10 and only 4 or 5 in two-digit range. For more NCERTRead more
Cubes with:
• 1 digit → 1³ = 1, 2³ = 8
• 2 digits → 3³ = 27 to 4³ = 64
• 3 digits → 5³ = 125 to 9³ = 729
Only a few cubes lie in each range. There are fewer cube numbers than squares in low ranges. For example, there are only 2 cubes below 10 and only 4 or 5 in two-digit range.
For more NCERT Solutions for Class 8 Mathematics Ganita Prakash Chapter 1 A Square and A Cube Extra Questions & Answer:
Is 500 a perfect cube?
Let’s factorise 500: 500 = 2² × 5³ For a number to be a cube, all prime factors must appear in triplets. Here, the factor 2 appears only twice, which cannot make a group of three. Therefore, 500 is not a perfect cube, as it cannot be written as the cube of any integer. For more NCERT SolutionRead more
Let’s factorise 500:
500 = 2² × 5³
For a number to be a cube, all prime factors must appear in triplets. Here, the factor 2 appears only twice, which cannot make a group of three. Therefore, 500 is not a perfect cube, as it cannot be written as the cube of any integer.
For more NCERT Solutions for Class 8 Mathematics Ganita Prakash Chapter 1 A Square and A Cube Extra Questions & Answer:
https://www.tiwariacademy.com/ncert-solutions/class-8/maths/ganita-prakash-chapter-1/
See lessLet us check if 3375 is a perfect cube.
To check if 3375 is a cube, we do prime factorisation: 3375 = 3³ × 5³ We can group the factors as (3 × 5)³ = 15³ = 3375. Since the prime factors can be grouped into three equal parts, this confirms that 3375 is a perfect cube. Hence, the cube root of 3375 is 15. For more NCERT Solutions for CRead more
To check if 3375 is a cube, we do prime factorisation:
3375 = 3³ × 5³
We can group the factors as (3 × 5)³ = 15³ = 3375. Since the prime factors can be grouped into three equal parts, this confirms that 3375 is a perfect cube.
Hence, the cube root of 3375 is 15.
For more NCERT Solutions for Class 8 Mathematics Ganita Prakash Chapter 1 A Square and A Cube Extra Questions & Answer:
https://www.tiwariacademy.com/ncert-solutions/class-8/maths/ganita-prakash-chapter-1/
See lessThe next two taxicab numbers after 1729 are 4104 and 13832. Find the two ways in which each of these can be expressed as the sum of two positive cubes.
A taxicab number is a number expressible as a sum of two cubes in two ways. For 4104: → 2³ + 16³ = 8 + 4096 = 4104 → 9³ + 15³ = 729 + 3375 = 4104 For 13832: → 2³ + 24³ = 8 + 13824 = 13832 → 18³ + 20³ = 5832 + 8000 = 13832 Hence, both 4104 and 13832 are taxicab numbers. For more NCERT SolutionRead more
A taxicab number is a number expressible as a sum of two cubes in two ways.
For 4104:
→ 2³ + 16³ = 8 + 4096 = 4104
→ 9³ + 15³ = 729 + 3375 = 4104
For 13832:
→ 2³ + 24³ = 8 + 13824 = 13832
→ 18³ + 20³ = 5832 + 8000 = 13832
Hence, both 4104 and 13832 are taxicab numbers.
For more NCERT Solutions for Class 8 Mathematics Ganita Prakash Chapter 1 A Square and A Cube Extra Questions & Answer:
https://www.tiwariacademy.com/ncert-solutions/class-8/maths/ganita-prakash-chapter-1/
See lessCan a cube end with exactly two zeroes (00)? Explain.
A number ending with two zeros is divisible by 100. When cubed, the number is multiplied by itself three times. That means 100 × 100 × 100 = 1,000,000, which has six zeros. So, even if a number ends in two zeros, its cube will have more than two. Hence, a cube cannot end in exactly two zeros. It musRead more
A number ending with two zeros is divisible by 100. When cubed, the number is multiplied by itself three times. That means 100 × 100 × 100 = 1,000,000, which has six zeros. So, even if a number ends in two zeros, its cube will have more than two. Hence, a cube cannot end in exactly two zeros. It must end in zero or at least three or more zeros.
For more NCERT Solutions for Class 8 Mathematics Ganita Prakash Chapter 1 A Square and A Cube Extra Questions & Answer:
https://www.tiwariacademy.com/ncert-solutions/class-8/maths/ganita-prakash-chapter-1/
See lessSimilar to squares, can you find the number of cubes with 1 digit, 2 digits and 3 digits? What do you observe?
Cubes with: • 1 digit → 1³ = 1, 2³ = 8 • 2 digits → 3³ = 27 to 4³ = 64 • 3 digits → 5³ = 125 to 9³ = 729 Only a few cubes lie in each range. There are fewer cube numbers than squares in low ranges. For example, there are only 2 cubes below 10 and only 4 or 5 in two-digit range. For more NCERTRead more
Cubes with:
• 1 digit → 1³ = 1, 2³ = 8
• 2 digits → 3³ = 27 to 4³ = 64
• 3 digits → 5³ = 125 to 9³ = 729
Only a few cubes lie in each range. There are fewer cube numbers than squares in low ranges. For example, there are only 2 cubes below 10 and only 4 or 5 in two-digit range.
For more NCERT Solutions for Class 8 Mathematics Ganita Prakash Chapter 1 A Square and A Cube Extra Questions & Answer:
https://www.tiwariacademy.com/ncert-solutions/class-8/maths/ganita-prakash-chapter-1/
See less