The volume of the godown is calculated by multiplying its dimensions: 40 m × 25 m × 10 m = 10,000 m³. The volume of each cuboidal box is 2 m × 1.25 m × 1 m = 2.5 m³. Dividing the total volume of the godown by the volume of a single box yields 10,000 / 2.5 = 4,000 boxes that can be stored. ForRead more
The volume of the godown is calculated by multiplying its dimensions: 40 m × 25 m × 10 m = 10,000 m³. The volume of each cuboidal box is 2 m × 1.25 m × 1 m = 2.5 m³. Dividing the total volume of the godown by the volume of a single box yields 10,000 / 2.5 = 4,000 boxes that can be stored.
For more NCERT Solutions of Class 9 Maths Ganita Manjari Part 2 Chapter 14 Math of Space: Surface Area and Volume Question Answer (2026-27)
Since each cube has a volume of 125 cm³, the side length is the cube root of 125, which is 5 cm. Joining two cubes end-to-end forms a cuboid with length 10 cm, width 5 cm and height 5 cm. The total surface area is 2(lw + wh + hl) = 2(50 + 25 + 50) = 2 × 125 = 250 cm². For more NCERT SolutionsRead more
Since each cube has a volume of 125 cm³, the side length is the cube root of 125, which is 5 cm. Joining two cubes end-to-end forms a cuboid with length 10 cm, width 5 cm and height 5 cm. The total surface area is 2(lw + wh + hl) = 2(50 + 25 + 50) = 2 × 125 = 250 cm².
For more NCERT Solutions of Class 9 Maths Ganita Manjari Part 2 Chapter 14 Math of Space: Surface Area and Volume Question Answer (2026-27)
The surface area of the original cube of side 4 cm is 6 × 4² = 96 cm². Cutting it into 1 cm cubes produces 4³ = 64 small cubes. Each small cube has a surface area of 6 × 1² = 6 cm², making the total area 64 × 6 = 384 cm². Therefore, the ratio of their surface areas is 96 : 384 = 1 : 4. For moRead more
The surface area of the original cube of side 4 cm is 6 × 4² = 96 cm². Cutting it into 1 cm cubes produces 4³ = 64 small cubes. Each small cube has a surface area of 6 × 1² = 6 cm², making the total area 64 × 6 = 384 cm². Therefore, the ratio of their surface areas is 96 : 384 = 1 : 4.
For more NCERT Solutions of Class 9 Maths Ganita Manjari Part 2 Chapter 14 Math of Space: Surface Area and Volume Question Answer (2026-27)
Political organization progressed from kinship clans into territorial janapadas and vast centralized empires like the Mauryas and Guptas. The early administrative system was structured hierarchically, dividing the realm into provinces, districts and villages. The monarch governed with a council of mRead more
Political organization progressed from kinship clans into territorial janapadas and vast centralized empires like the Mauryas and Guptas. The early administrative system was structured hierarchically, dividing the realm into provinces, districts and villages. The monarch governed with a council of ministers (mantri-parishad), while provincial governors, specialized officers and largely self-reliant village assemblies managed local revenue and community infrastructure.
For more NCERT Solutions of Class 9 Social Science Chapter 5 State and Society up to 1000 CE Question Answer (2026-27)
(i) Role of the king: The monarch served as supreme protector, commander and judge, exercising authority guided by the welfare of subjects and ethical principles of dharma. (ii) Important officers: Key functionaries included ministerial counselors (amatyas), provincial governors (pradeshikas), treasRead more
(i) Role of the king: The monarch served as supreme protector, commander and judge, exercising authority guided by the welfare of subjects and ethical principles of dharma. (ii) Important officers: Key functionaries included ministerial counselors (amatyas), provincial governors (pradeshikas), treasurers, commanders-in-chief and village headmen (gramikas). (iii) Governance methods: Large territories were administered by subdividing realms into provinces, districts and self-governing villages.
For more NCERT Solutions of Class 9 Social Science Chapter 5 State and Society up to 1000 CE Question Answer (2026-27)
The dimensions of a godown are 40 m × 25 m × 10 m. If it is filled with cuboidal boxes, each of dimensions 2 m × 1.25 m × 1 m, then find the number of boxes.
The volume of the godown is calculated by multiplying its dimensions: 40 m × 25 m × 10 m = 10,000 m³. The volume of each cuboidal box is 2 m × 1.25 m × 1 m = 2.5 m³. Dividing the total volume of the godown by the volume of a single box yields 10,000 / 2.5 = 4,000 boxes that can be stored. ForRead more
The volume of the godown is calculated by multiplying its dimensions: 40 m × 25 m × 10 m = 10,000 m³. The volume of each cuboidal box is 2 m × 1.25 m × 1 m = 2.5 m³. Dividing the total volume of the godown by the volume of a single box yields 10,000 / 2.5 = 4,000 boxes that can be stored.
For more NCERT Solutions of Class 9 Maths Ganita Manjari Part 2 Chapter 14 Math of Space: Surface Area and Volume Question Answer (2026-27)
https://www.tiwariacademy.com/ncert-solutions/class-9/maths/ganita-manjari-chapter-14/
See lessTwo cubes each of volume 125 cm³ are joined end to end. Find the surface area of the resulting cuboid.
Since each cube has a volume of 125 cm³, the side length is the cube root of 125, which is 5 cm. Joining two cubes end-to-end forms a cuboid with length 10 cm, width 5 cm and height 5 cm. The total surface area is 2(lw + wh + hl) = 2(50 + 25 + 50) = 2 × 125 = 250 cm². For more NCERT SolutionsRead more
Since each cube has a volume of 125 cm³, the side length is the cube root of 125, which is 5 cm. Joining two cubes end-to-end forms a cuboid with length 10 cm, width 5 cm and height 5 cm. The total surface area is 2(lw + wh + hl) = 2(50 + 25 + 50) = 2 × 125 = 250 cm².
For more NCERT Solutions of Class 9 Maths Ganita Manjari Part 2 Chapter 14 Math of Space: Surface Area and Volume Question Answer (2026-27)
https://www.tiwariacademy.com/ncert-solutions/class-9/maths/ganita-manjari-chapter-14/
See lessA cube of side 4 cm is cut into cubes of side 1 cm. What is the ratio of the surface areas of the original cube and all the cut-out cubes?
The surface area of the original cube of side 4 cm is 6 × 4² = 96 cm². Cutting it into 1 cm cubes produces 4³ = 64 small cubes. Each small cube has a surface area of 6 × 1² = 6 cm², making the total area 64 × 6 = 384 cm². Therefore, the ratio of their surface areas is 96 : 384 = 1 : 4. For moRead more
The surface area of the original cube of side 4 cm is 6 × 4² = 96 cm². Cutting it into 1 cm cubes produces 4³ = 64 small cubes. Each small cube has a surface area of 6 × 1² = 6 cm², making the total area 64 × 6 = 384 cm². Therefore, the ratio of their surface areas is 96 : 384 = 1 : 4.
For more NCERT Solutions of Class 9 Maths Ganita Manjari Part 2 Chapter 14 Math of Space: Surface Area and Volume Question Answer (2026-27)
https://www.tiwariacademy.com/ncert-solutions/class-9/maths/ganita-manjari-chapter-14/
See lessHow did political organisation change from the Vedic period to the age of large empires such as the Mauryas and the Guptas? Explain the administrative system of the early Indian states.
Political organization progressed from kinship clans into territorial janapadas and vast centralized empires like the Mauryas and Guptas. The early administrative system was structured hierarchically, dividing the realm into provinces, districts and villages. The monarch governed with a council of mRead more
Political organization progressed from kinship clans into territorial janapadas and vast centralized empires like the Mauryas and Guptas. The early administrative system was structured hierarchically, dividing the realm into provinces, districts and villages. The monarch governed with a council of ministers (mantri-parishad), while provincial governors, specialized officers and largely self-reliant village assemblies managed local revenue and community infrastructure.
For more NCERT Solutions of Class 9 Social Science Chapter 5 State and Society up to 1000 CE Question Answer (2026-27)
https://www.tiwariacademy.com/ncert-solutions/class-9/social-science/
See lessDescribe the role of the king, important officers and the methods used to govern large territories.
(i) Role of the king: The monarch served as supreme protector, commander and judge, exercising authority guided by the welfare of subjects and ethical principles of dharma. (ii) Important officers: Key functionaries included ministerial counselors (amatyas), provincial governors (pradeshikas), treasRead more
(i) Role of the king: The monarch served as supreme protector, commander and judge, exercising authority guided by the welfare of subjects and ethical principles of dharma. (ii) Important officers: Key functionaries included ministerial counselors (amatyas), provincial governors (pradeshikas), treasurers, commanders-in-chief and village headmen (gramikas). (iii) Governance methods: Large territories were administered by subdividing realms into provinces, districts and self-governing villages.
For more NCERT Solutions of Class 9 Social Science Chapter 5 State and Society up to 1000 CE Question Answer (2026-27)
https://www.tiwariacademy.com/ncert-solutions/class-9/social-science/
See less