K.E = P²/2m sp p = √2mk Increase in K.E. = 300% of k = 3k Final K.E., k ′ = k + 3k = 4k Final momentum, p′= √2mk = √(2m X 4k) = √(2&2mk) = 2p % Increase in momentum = p' - p/p X 100 = 100%
K.E = P²/2m sp p = √2mk
Increase in K.E. = 300% of k = 3k
Final K.E., k ′ = k + 3k = 4k
Final momentum, p′= √2mk = √(2m X 4k) = √(2&2mk)
= 2p
% Increase in momentum = p’ – p/p X 100 = 100%
A light and a heavy body have same K.E., which of the two have more momentum and why?
Heavier body.
Heavier body.
See lessK.E. of a body is increased by 300 %. Find the % increase in its momentum?
K.E = P²/2m sp p = √2mk Increase in K.E. = 300% of k = 3k Final K.E., k ′ = k + 3k = 4k Final momentum, p′= √2mk = √(2m X 4k) = √(2&2mk) = 2p % Increase in momentum = p' - p/p X 100 = 100%
K.E = P²/2m sp p = √2mk
See lessIncrease in K.E. = 300% of k = 3k
Final K.E., k ′ = k + 3k = 4k
Final momentum, p′= √2mk = √(2m X 4k) = √(2&2mk)
= 2p
% Increase in momentum = p’ – p/p X 100 = 100%
How will the momentum of a body changes if its K.E. is doubled?
Momentum becomes √2 times.
Momentum becomes √2 times.
See lessState the two conditions under which a force does no work?
(i) Displacement is zero or it is perpendicular to force. (ii) Conservative force moves a body over a closed path.
(i) Displacement is zero or it is perpendicular to force.
(ii) Conservative force moves a body over a closed path.
See lessTwo bodies stick together after collision. What type of collision is in between these two bodies?
Inelastic collision.
Inelastic collision.
See less