Simplify: 2 x 10³ = = 2 x 10 x 10 x 10 = 2,000 Class 7 Maths Chapter 13 Exercise 13.1 for more answers vist to: https://www.tiwariacademy.com/ncert-solutions/class-7/maths/chapter-13/
4³ = 4 x 4 x 4 = 64 3⁴ = 3 x 3 x 3 x 3 = 81 Since 64 < 81 Thus, 3⁴ is greater than 4³. Class 7 Maths Chapter 13 Exercise 13.1 for more answers vist to: https://www.tiwariacademy.com/ncert-solutions/class-7/maths/chapter-13/
4³ = 4 x 4 x 4 = 64
3⁴ = 3 x 3 x 3 x 3 = 81
Since 64 < 81
Thus, 3⁴ is greater than 4³.
512 = 2 x 2 x 2 x 2 x 2 x 2 x 2 x 2 x 2 = 2⁹ Class 7 Maths Chapter 13 Exercise 13.1 for more answers vist to: https://www.tiwariacademy.com/ncert-solutions/class-7/maths/chapter-13/
6 x 6 x 6 x 6 = 6⁴ Class 7 Maths Chapter 13 Exercise 13.1 for more answers vist to: https://www.tiwariacademy.com/ncert-solutions/class-7/maths/chapter-13/
Simplify: 2 x 10³
Simplify: 2 x 10³ = = 2 x 10 x 10 x 10 = 2,000 Class 7 Maths Chapter 13 Exercise 13.1 for more answers vist to: https://www.tiwariacademy.com/ncert-solutions/class-7/maths/chapter-13/
Simplify: 2 x 10³ = = 2 x 10 x 10 x 10 = 2,000
Class 7 Maths Chapter 13 Exercise 13.1
for more answers vist to:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-7/maths/chapter-13/
Express each of the following as product of powers of their prime factors: 648
648 = 2³ x 3⁴ Class 7 Maths Chapter 13 Exercise 13.1 for more answers vist to: https://www.tiwariacademy.com/ncert-solutions/class-7/maths/chapter-13/
648 = 2³ x 3⁴
Class 7 Maths Chapter 13 Exercise 13.1
for more answers vist to:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-7/maths/chapter-13/
Identify the greater number, wherever possible, in each of the following: 4³ and 3⁴
4³ = 4 x 4 x 4 = 64 3⁴ = 3 x 3 x 3 x 3 = 81 Since 64 < 81 Thus, 3⁴ is greater than 4³. Class 7 Maths Chapter 13 Exercise 13.1 for more answers vist to: https://www.tiwariacademy.com/ncert-solutions/class-7/maths/chapter-13/
4³ = 4 x 4 x 4 = 64
3⁴ = 3 x 3 x 3 x 3 = 81
Since 64 < 81
Thus, 3⁴ is greater than 4³.
Class 7 Maths Chapter 13 Exercise 13.1
for more answers vist to:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-7/maths/chapter-13/
Express each of the following numbers using exponential notation: 512
512 = 2 x 2 x 2 x 2 x 2 x 2 x 2 x 2 x 2 = 2⁹ Class 7 Maths Chapter 13 Exercise 13.1 for more answers vist to: https://www.tiwariacademy.com/ncert-solutions/class-7/maths/chapter-13/
512 = 2 x 2 x 2 x 2 x 2 x 2 x 2 x 2 x 2 = 2⁹
Class 7 Maths Chapter 13 Exercise 13.1
for more answers vist to:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-7/maths/chapter-13/
Express the following in exponential form: 6 x 6 x 6 x 6
6 x 6 x 6 x 6 = 6⁴ Class 7 Maths Chapter 13 Exercise 13.1 for more answers vist to: https://www.tiwariacademy.com/ncert-solutions/class-7/maths/chapter-13/
6 x 6 x 6 x 6 = 6⁴
Class 7 Maths Chapter 13 Exercise 13.1
for more answers vist to:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-7/maths/chapter-13/