10×10¹¹=100¹¹ L.H.S. 10¹⁺¹¹ = 10¹² and R.H.S. (10²)¹¹ = 10²² Since, L.H.S. ≠ R.H.S. Therefore, it is false. Class 7 Maths Chapter 13 Exercise 13.2 for more answers vist to: https://www.tiwariacademy.com/ncert-solutions/class-7/maths/chapter-13/
10×10¹¹=100¹¹
L.H.S. 10¹⁺¹¹ = 10¹² and R.H.S. (10²)¹¹ = 10²²
Since, L.H.S. ≠ R.H.S.
Therefore, it is false.
3² x 3⁴ x 3⁸ = 3²⁺⁴⁺⁸ = 3¹⁴ Class 7 Maths Chapter 13 Exercise 13.2 for more answers vist to: https://www.tiwariacademy.com/ncert-solutions/class-7/maths/chapter-13/
2.7 x 10¹²; 1.5 x 10⁸ On comparing the exponents of base 10, 2.7 x 10¹² > 1.5 x 10⁸ Class 7 Maths Chapter 13 Exercise 13.1 for more answers vist to: https://www.tiwariacademy.com/ncert-solutions/class-7/maths/chapter-13/
2.7 x 10¹²; 1.5 x 10⁸
On comparing the exponents of base 10,
2.7 x 10¹² > 1.5 x 10⁸
(-4)³ = (-4) x (-4) x (-4) = -64 Class 7 Maths Chapter 13 Exercise 13.1 for more answers vist to: https://www.tiwariacademy.com/ncert-solutions/class-7/maths/chapter-13/
Say true or false and justify your answer: 10×10¹¹=100¹¹
10×10¹¹=100¹¹ L.H.S. 10¹⁺¹¹ = 10¹² and R.H.S. (10²)¹¹ = 10²² Since, L.H.S. ≠ R.H.S. Therefore, it is false. Class 7 Maths Chapter 13 Exercise 13.2 for more answers vist to: https://www.tiwariacademy.com/ncert-solutions/class-7/maths/chapter-13/
10×10¹¹=100¹¹
L.H.S. 10¹⁺¹¹ = 10¹² and R.H.S. (10²)¹¹ = 10²²
Since, L.H.S. ≠ R.H.S.
Therefore, it is false.
Class 7 Maths Chapter 13 Exercise 13.2
for more answers vist to:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-7/maths/chapter-13/
Simplify and express each of the following in exponential form: 2³x3⁴x4/3×32
2³x3⁴x4/3×32 = 2³x3⁴x2²/3×2⁵ = 2³⁺²X3⁴/3×2⁵ [∵ aᵐ x aⁿ = aᵐ⁺ⁿ] = 2⁵x3⁴/3x2⁵ = 2⁵⁻⁵ x 3⁴⁻³ [∵ aᵐ ÷ aⁿ = aᵐ⁻ⁿ] = 2⁰x3³ = 1x3³ = 3³ Class 7 Maths Chapter 13 Exercise 13.2 for more answers vist to: https://www.tiwariacademy.com/ncert-solutions/class-7/maths/chapter-13/
2³x3⁴x4/3×32 = 2³x3⁴x2²/3×2⁵ = 2³⁺²X3⁴/3×2⁵ [∵ aᵐ x aⁿ = aᵐ⁺ⁿ]
= 2⁵x3⁴/3×2⁵ = 2⁵⁻⁵ x 3⁴⁻³ [∵ aᵐ ÷ aⁿ = aᵐ⁻ⁿ]
= 2⁰x3³ = 1×3³ = 3³
Class 7 Maths Chapter 13 Exercise 13.2
for more answers vist to:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-7/maths/chapter-13/
Using laws of exponents, simplify and write the answer in exponential form: 3² x 3⁴ x 3⁸
3² x 3⁴ x 3⁸ = 3²⁺⁴⁺⁸ = 3¹⁴ Class 7 Maths Chapter 13 Exercise 13.2 for more answers vist to: https://www.tiwariacademy.com/ncert-solutions/class-7/maths/chapter-13/
3² x 3⁴ x 3⁸ = 3²⁺⁴⁺⁸ = 3¹⁴
Class 7 Maths Chapter 13 Exercise 13.2
for more answers vist to:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-7/maths/chapter-13/
Compare the following numbers: 2.7 x 10¹²; 1.5 x 10⁸
2.7 x 10¹²; 1.5 x 10⁸ On comparing the exponents of base 10, 2.7 x 10¹² > 1.5 x 10⁸ Class 7 Maths Chapter 13 Exercise 13.1 for more answers vist to: https://www.tiwariacademy.com/ncert-solutions/class-7/maths/chapter-13/
2.7 x 10¹²; 1.5 x 10⁸
On comparing the exponents of base 10,
2.7 x 10¹² > 1.5 x 10⁸
Class 7 Maths Chapter 13 Exercise 13.1
for more answers vist to:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-7/maths/chapter-13/
Simplify: (-4)³
(-4)³ = (-4) x (-4) x (-4) = -64 Class 7 Maths Chapter 13 Exercise 13.1 for more answers vist to: https://www.tiwariacademy.com/ncert-solutions/class-7/maths/chapter-13/
(-4)³ = (-4) x (-4) x (-4) = -64
Class 7 Maths Chapter 13 Exercise 13.1
for more answers vist to:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-7/maths/chapter-13/