(a) The distance between Earth and Moon = 384,000,000 m = 384 x 1000000 m = 3.84 x 100 x 1000000 = 3.84x10⁸ m (b) Speed of light in vacuum = 300,000,000 m/s = 3 x 100000000 m/s = 3 x 10⁸ m/s Class 7 Maths Chapter 13 Exercise 13.3 for more answers vist to: https://www.tiwariacademy.com/ncert-solutionRead more
(a) The distance between Earth and Moon = 384,000,000 m
= 384 x 1000000 m
= 3.84 x 100 x 1000000
= 3.84×10⁸ m
(b) Speed of light in vacuum = 300,000,000 m/s
= 3 x 100000000 m/s
= 3 x 10⁸ m/s
5,00,00,000 = 5 x 1,00,00,000 = 5 x 10⁷ Class 7 Maths Chapter 13 Exercise 13.3 for more answers vist to: https://www.tiwariacademy.com/ncert-solutions/class-7/maths/chapter-13/
10⁴ + 6 x 10³ + 0 x 10³ + 4 x 10¹ + 5 x 10⁰ = 8 x 10000 + 6 x 1000 + 0 x 100 + 4 x 10 + 5 x 1 = 80000 + 6000 + 0 + 40 + 5 = 86,045 Class 7 Maths Chapter 13 Exercise 13.3 for more answers vist to: https://www.tiwariacademy.com/ncert-solutions/class-7/maths/chapter-13/
10⁴ + 6 x 10³ + 0 x 10³ + 4 x 10¹ + 5 x 10⁰
= 8 x 10000 + 6 x 1000 + 0 x 100 + 4 x 10 + 5 x 1
= 80000 + 6000 + 0 + 40 + 5
= 86,045
(i) 2,79,404 = 2,00,000 + 70,000 + 9,000 + 400 + 00 + 4 = 2 x 100000 + 7 x 10000 + 9 x 1000 + 4 x 100 + 0 x 10 + 4 x 1 = 2x10⁵ + 7x10⁴ + 9 x 10³ + 4x10² + 0 x 10¹ + 4x10⁰ Class 7 Maths Chapter 13 Exercise 13.3 for more answers vist to: https://www.tiwariacademy.com/ncert-solutions/class-7/maths/chapRead more
(i) 2,79,404 = 2,00,000 + 70,000 + 9,000 + 400 + 00 + 4
= 2 x 100000 + 7 x 10000 + 9 x 1000 + 4 x 100 + 0 x 10 + 4 x 1
= 2×10⁵ + 7×10⁴ + 9 x 10³ + 4×10² + 0 x 10¹ + 4×10⁰
10×10¹¹=100¹¹ L.H.S. 10¹⁺¹¹ = 10¹² and R.H.S. (10²)¹¹ = 10²² Since, L.H.S. ≠ R.H.S. Therefore, it is false. Class 7 Maths Chapter 13 Exercise 13.2 for more answers vist to: https://www.tiwariacademy.com/ncert-solutions/class-7/maths/chapter-13/
10×10¹¹=100¹¹
L.H.S. 10¹⁺¹¹ = 10¹² and R.H.S. (10²)¹¹ = 10²²
Since, L.H.S. ≠ R.H.S.
Therefore, it is false.
3² x 3⁴ x 3⁸ = 3²⁺⁴⁺⁸ = 3¹⁴ Class 7 Maths Chapter 13 Exercise 13.2 for more answers vist to: https://www.tiwariacademy.com/ncert-solutions/class-7/maths/chapter-13/
2.7 x 10¹²; 1.5 x 10⁸ On comparing the exponents of base 10, 2.7 x 10¹² > 1.5 x 10⁸ Class 7 Maths Chapter 13 Exercise 13.1 for more answers vist to: https://www.tiwariacademy.com/ncert-solutions/class-7/maths/chapter-13/
2.7 x 10¹²; 1.5 x 10⁸
On comparing the exponents of base 10,
2.7 x 10¹² > 1.5 x 10⁸
(-4)³ = (-4) x (-4) x (-4) = -64 Class 7 Maths Chapter 13 Exercise 13.1 for more answers vist to: https://www.tiwariacademy.com/ncert-solutions/class-7/maths/chapter-13/
Express the number appearing in the following statements in standard form: (a) The distance between Earth and Moon is 384,000,000 m. (b) Speed of light in vacuum is 300,000,000 m/s.
(a) The distance between Earth and Moon = 384,000,000 m = 384 x 1000000 m = 3.84 x 100 x 1000000 = 3.84x10⁸ m (b) Speed of light in vacuum = 300,000,000 m/s = 3 x 100000000 m/s = 3 x 10⁸ m/s Class 7 Maths Chapter 13 Exercise 13.3 for more answers vist to: https://www.tiwariacademy.com/ncert-solutionRead more
(a) The distance between Earth and Moon = 384,000,000 m
= 384 x 1000000 m
= 3.84 x 100 x 1000000
= 3.84×10⁸ m
(b) Speed of light in vacuum = 300,000,000 m/s
= 3 x 100000000 m/s
= 3 x 10⁸ m/s
Class 7 Maths Chapter 13 Exercise 13.3
for more answers vist to:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-7/maths/chapter-13/
Express the following numbers in standard form: 5,00,00,000
5,00,00,000 = 5 x 1,00,00,000 = 5 x 10⁷ Class 7 Maths Chapter 13 Exercise 13.3 for more answers vist to: https://www.tiwariacademy.com/ncert-solutions/class-7/maths/chapter-13/
5,00,00,000 = 5 x 1,00,00,000 = 5 x 10⁷
Class 7 Maths Chapter 13 Exercise 13.3
for more answers vist to:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-7/maths/chapter-13/
Find the number from each of the following expanded forms: 8 x 10⁴ + 6 x 10³ + 0 x 10³ + 4 x 10¹ + 5 x 10⁰
10⁴ + 6 x 10³ + 0 x 10³ + 4 x 10¹ + 5 x 10⁰ = 8 x 10000 + 6 x 1000 + 0 x 100 + 4 x 10 + 5 x 1 = 80000 + 6000 + 0 + 40 + 5 = 86,045 Class 7 Maths Chapter 13 Exercise 13.3 for more answers vist to: https://www.tiwariacademy.com/ncert-solutions/class-7/maths/chapter-13/
10⁴ + 6 x 10³ + 0 x 10³ + 4 x 10¹ + 5 x 10⁰
= 8 x 10000 + 6 x 1000 + 0 x 100 + 4 x 10 + 5 x 1
= 80000 + 6000 + 0 + 40 + 5
= 86,045
Class 7 Maths Chapter 13 Exercise 13.3
for more answers vist to:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-7/maths/chapter-13/
Write the following numbers in the expanded form: 279404,
(i) 2,79,404 = 2,00,000 + 70,000 + 9,000 + 400 + 00 + 4 = 2 x 100000 + 7 x 10000 + 9 x 1000 + 4 x 100 + 0 x 10 + 4 x 1 = 2x10⁵ + 7x10⁴ + 9 x 10³ + 4x10² + 0 x 10¹ + 4x10⁰ Class 7 Maths Chapter 13 Exercise 13.3 for more answers vist to: https://www.tiwariacademy.com/ncert-solutions/class-7/maths/chapRead more
(i) 2,79,404 = 2,00,000 + 70,000 + 9,000 + 400 + 00 + 4
= 2 x 100000 + 7 x 10000 + 9 x 1000 + 4 x 100 + 0 x 10 + 4 x 1
= 2×10⁵ + 7×10⁴ + 9 x 10³ + 4×10² + 0 x 10¹ + 4×10⁰
Class 7 Maths Chapter 13 Exercise 13.3
for more answers vist to:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-7/maths/chapter-13/
Simplify: (2⁵)²x7³/8³x7
(2⁵)²x7³/8³x7 = 2⁵ ͯ ͯ²x7³/(2³)³ x7 = 2¹⁰x7³/2⁹x7 = 2¹⁰⁻⁹x7³⁻¹ = 2x7² = 2x49 = 98 Class 7 Maths Chapter 13 Exercise 13.2 for more answers vist to: https://www.tiwariacademy.com/ncert-solutions/class-7/maths/chapter-13/
(2⁵)²x7³/8³x7 = 2⁵ ͯ ͯ²x7³/(2³)³ x7
= 2¹⁰x7³/2⁹x7
= 2¹⁰⁻⁹x7³⁻¹ = 2×7²
= 2×49
= 98
Class 7 Maths Chapter 13 Exercise 13.2
for more answers vist to:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-7/maths/chapter-13/
Say true or false and justify your answer: 10×10¹¹=100¹¹
10×10¹¹=100¹¹ L.H.S. 10¹⁺¹¹ = 10¹² and R.H.S. (10²)¹¹ = 10²² Since, L.H.S. ≠ R.H.S. Therefore, it is false. Class 7 Maths Chapter 13 Exercise 13.2 for more answers vist to: https://www.tiwariacademy.com/ncert-solutions/class-7/maths/chapter-13/
10×10¹¹=100¹¹
L.H.S. 10¹⁺¹¹ = 10¹² and R.H.S. (10²)¹¹ = 10²²
Since, L.H.S. ≠ R.H.S.
Therefore, it is false.
Class 7 Maths Chapter 13 Exercise 13.2
for more answers vist to:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-7/maths/chapter-13/
Simplify and express each of the following in exponential form: 2³x3⁴x4/3×32
2³x3⁴x4/3×32 = 2³x3⁴x2²/3×2⁵ = 2³⁺²X3⁴/3×2⁵ [∵ aᵐ x aⁿ = aᵐ⁺ⁿ] = 2⁵x3⁴/3x2⁵ = 2⁵⁻⁵ x 3⁴⁻³ [∵ aᵐ ÷ aⁿ = aᵐ⁻ⁿ] = 2⁰x3³ = 1x3³ = 3³ Class 7 Maths Chapter 13 Exercise 13.2 for more answers vist to: https://www.tiwariacademy.com/ncert-solutions/class-7/maths/chapter-13/
2³x3⁴x4/3×32 = 2³x3⁴x2²/3×2⁵ = 2³⁺²X3⁴/3×2⁵ [∵ aᵐ x aⁿ = aᵐ⁺ⁿ]
= 2⁵x3⁴/3×2⁵ = 2⁵⁻⁵ x 3⁴⁻³ [∵ aᵐ ÷ aⁿ = aᵐ⁻ⁿ]
= 2⁰x3³ = 1×3³ = 3³
Class 7 Maths Chapter 13 Exercise 13.2
for more answers vist to:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-7/maths/chapter-13/
Using laws of exponents, simplify and write the answer in exponential form: 3² x 3⁴ x 3⁸
3² x 3⁴ x 3⁸ = 3²⁺⁴⁺⁸ = 3¹⁴ Class 7 Maths Chapter 13 Exercise 13.2 for more answers vist to: https://www.tiwariacademy.com/ncert-solutions/class-7/maths/chapter-13/
3² x 3⁴ x 3⁸ = 3²⁺⁴⁺⁸ = 3¹⁴
Class 7 Maths Chapter 13 Exercise 13.2
for more answers vist to:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-7/maths/chapter-13/
Compare the following numbers: 2.7 x 10¹²; 1.5 x 10⁸
2.7 x 10¹²; 1.5 x 10⁸ On comparing the exponents of base 10, 2.7 x 10¹² > 1.5 x 10⁸ Class 7 Maths Chapter 13 Exercise 13.1 for more answers vist to: https://www.tiwariacademy.com/ncert-solutions/class-7/maths/chapter-13/
2.7 x 10¹²; 1.5 x 10⁸
On comparing the exponents of base 10,
2.7 x 10¹² > 1.5 x 10⁸
Class 7 Maths Chapter 13 Exercise 13.1
for more answers vist to:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-7/maths/chapter-13/
Simplify: (-4)³
(-4)³ = (-4) x (-4) x (-4) = -64 Class 7 Maths Chapter 13 Exercise 13.1 for more answers vist to: https://www.tiwariacademy.com/ncert-solutions/class-7/maths/chapter-13/
(-4)³ = (-4) x (-4) x (-4) = -64
Class 7 Maths Chapter 13 Exercise 13.1
for more answers vist to:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-7/maths/chapter-13/