In the game, ‘idli’ is said for multiples of 3, which occur 30 times from 3 to 90. ‘Vada’ is said for multiples of 5, totaling 18 times. Numbers like 15, 30, 45, 60, 75, and 90 overlap both categories, so ‘idli-vada’ is said 6 times for these multiples. Since ‘idli’ and ‘vada’ overlap, the total uniRead more
In the game, ‘idli’ is said for multiples of 3, which occur 30 times from 3 to 90. ‘Vada’ is said for multiples of 5, totaling 18 times. Numbers like 15, 30, 45, 60, 75, and 90 overlap both categories, so ‘idli-vada’ is said 6 times for these multiples. Since ‘idli’ and ‘vada’ overlap, the total unique calls differ depending on whether these overlaps are included in both counts.
When playing till 900, ‘idli’ is called for multiples of 3, occurring 300 times (3 × 300 = 900). ‘Vada’ corresponds to multiples of 5, occurring 180 times (5 × 180 = 900). For ‘idli-vada,’ said for multiples of both 3 and 5 (LCM 15), there are 60 instances (15 × 60 = 900). The overlaps ensure no douRead more
When playing till 900, ‘idli’ is called for multiples of 3, occurring 300 times (3 × 300 = 900). ‘Vada’ corresponds to multiples of 5, occurring 180 times (5 × 180 = 900). For ‘idli-vada,’ said for multiples of both 3 and 5 (LCM 15), there are 60 instances (15 × 60 = 900). The overlaps ensure no double counting, and the counts follow the divisibility rules for these multiples within the range.
To reach both treasures at 14 and 36, the jump size must divide both numbers. The factors of 14 are 1, 2, 7, and 14; the factors of 36 are 1, 2, 3, 4, 6, 9, 12, 18, and 36. The common factors are 1 and 2, making these valid jump sizes. Since the GCD is 2, it guarantees the smallest successful jump tRead more
To reach both treasures at 14 and 36, the jump size must divide both numbers. The factors of 14 are 1, 2, 7, and 14; the factors of 36 are 1, 2, 3, 4, 6, 9, 12, 18, and 36. The common factors are 1 and 2, making these valid jump sizes. Since the GCD is 2, it guarantees the smallest successful jump that aligns perfectly with both treasures.
To find multiples of 40 between 310 and 410, divide the lower bound by 40 (310 ÷ 40 = 7.75) and round up to 8. Multiply 40 by 8 to get 320, the first multiple. Similarly, dividing the upper bound (410 ÷ 40 = 10.25) and rounding down to 10 gives 400 as the last multiple. The full sequence is 320, 360Read more
To find multiples of 40 between 310 and 410, divide the lower bound by 40 (310 ÷ 40 = 7.75) and round up to 8. Multiply 40 by 8 to get 320, the first multiple. Similarly, dividing the upper bound (410 ÷ 40 = 10.25) and rounding down to 10 gives 400 as the last multiple. The full sequence is 320, 360, and 400, as all are divisible by 40 and fall within the specified range.
The required number must meet three criteria: be less than 40, have 7 as a factor, and have a digit sum of 8. The multiples of 7 under 40 are 7, 14, 21, 28, and 35. Out of these, only 35 satisfies the digit sum condition (3 + 5 = 8). Its complete set of factors is 1, 5, 7, and 35. Thus, the answer iRead more
The required number must meet three criteria: be less than 40, have 7 as a factor, and have a digit sum of 8. The multiples of 7 under 40 are 7, 14, 21, 28, and 35. Out of these, only 35 satisfies the digit sum condition (3 + 5 = 8). Its complete set of factors is 1, 5, 7, and 35. Thus, the answer is 35, fulfilling all the stated conditions.
How many times would children say idli, vada, and idli-vada in a game played till 90?
In the game, ‘idli’ is said for multiples of 3, which occur 30 times from 3 to 90. ‘Vada’ is said for multiples of 5, totaling 18 times. Numbers like 15, 30, 45, 60, 75, and 90 overlap both categories, so ‘idli-vada’ is said 6 times for these multiples. Since ‘idli’ and ‘vada’ overlap, the total uniRead more
In the game, ‘idli’ is said for multiples of 3, which occur 30 times from 3 to 90. ‘Vada’ is said for multiples of 5, totaling 18 times. Numbers like 15, 30, 45, 60, 75, and 90 overlap both categories, so ‘idli-vada’ is said 6 times for these multiples. Since ‘idli’ and ‘vada’ overlap, the total unique calls differ depending on whether these overlaps are included in both counts.
For more NCERT Solutions for Class 6 Math Chapter 5 Prime Time Extra Questions and Answer:
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If the game is played till 900, how many times would children say idli, vada, and idli-vada?
When playing till 900, ‘idli’ is called for multiples of 3, occurring 300 times (3 × 300 = 900). ‘Vada’ corresponds to multiples of 5, occurring 180 times (5 × 180 = 900). For ‘idli-vada,’ said for multiples of both 3 and 5 (LCM 15), there are 60 instances (15 × 60 = 900). The overlaps ensure no douRead more
When playing till 900, ‘idli’ is called for multiples of 3, occurring 300 times (3 × 300 = 900). ‘Vada’ corresponds to multiples of 5, occurring 180 times (5 × 180 = 900). For ‘idli-vada,’ said for multiples of both 3 and 5 (LCM 15), there are 60 instances (15 × 60 = 900). The overlaps ensure no double counting, and the counts follow the divisibility rules for these multiples within the range.
For more NCERT Solutions for Class 6 Math Chapter 5 Prime Time Extra Questions and Answer:
See lesshttps://www.tiwariacademy.com/ncert-solutions-class-6-maths-ganita-prakash-chapter-5/
What are the jump sizes that will reach both treasures at 14 and 36?
To reach both treasures at 14 and 36, the jump size must divide both numbers. The factors of 14 are 1, 2, 7, and 14; the factors of 36 are 1, 2, 3, 4, 6, 9, 12, 18, and 36. The common factors are 1 and 2, making these valid jump sizes. Since the GCD is 2, it guarantees the smallest successful jump tRead more
To reach both treasures at 14 and 36, the jump size must divide both numbers. The factors of 14 are 1, 2, 7, and 14; the factors of 36 are 1, 2, 3, 4, 6, 9, 12, 18, and 36. The common factors are 1 and 2, making these valid jump sizes. Since the GCD is 2, it guarantees the smallest successful jump that aligns perfectly with both treasures.
For more NCERT Solutions for Class 6 Math Chapter 5 Prime Time Extra Questions and Answer:
See lesshttps://www.tiwariacademy.com/ncert-solutions-class-6-maths-ganita-prakash-chapter-5/
Find all multiples of 40 that lie between 310 and 410.
To find multiples of 40 between 310 and 410, divide the lower bound by 40 (310 ÷ 40 = 7.75) and round up to 8. Multiply 40 by 8 to get 320, the first multiple. Similarly, dividing the upper bound (410 ÷ 40 = 10.25) and rounding down to 10 gives 400 as the last multiple. The full sequence is 320, 360Read more
To find multiples of 40 between 310 and 410, divide the lower bound by 40 (310 ÷ 40 = 7.75) and round up to 8. Multiply 40 by 8 to get 320, the first multiple. Similarly, dividing the upper bound (410 ÷ 40 = 10.25) and rounding down to 10 gives 400 as the last multiple. The full sequence is 320, 360, and 400, as all are divisible by 40 and fall within the specified range.
For more NCERT Solutions for Class 6 Math Chapter 5 Prime Time Extra Questions and Answer:
See lesshttps://www.tiwariacademy.com/ncert-solutions-class-6-maths-ganita-prakash-chapter-5/
Who am I? a) I am a number less than 40. One of my factors is 7. The sum of my digits is 8.
The required number must meet three criteria: be less than 40, have 7 as a factor, and have a digit sum of 8. The multiples of 7 under 40 are 7, 14, 21, 28, and 35. Out of these, only 35 satisfies the digit sum condition (3 + 5 = 8). Its complete set of factors is 1, 5, 7, and 35. Thus, the answer iRead more
The required number must meet three criteria: be less than 40, have 7 as a factor, and have a digit sum of 8. The multiples of 7 under 40 are 7, 14, 21, 28, and 35. Out of these, only 35 satisfies the digit sum condition (3 + 5 = 8). Its complete set of factors is 1, 5, 7, and 35. Thus, the answer is 35, fulfilling all the stated conditions.
For more NCERT Solutions for Class 6 Math Chapter 5 Prime Time Extra Questions and Answer:
See lesshttps://www.tiwariacademy.com/ncert-solutions-class-6-maths-ganita-prakash-chapter-5/