Radius of cone r = 24/2 = 12 cm and slant height l = 21 cm Total surface area of cone = πr(r + l) = 22/7 × 12 × (12 + 21) = 22/7 × 12 × 33 = 1244.57 m² Hence, the total surface area of cone is 1244.57 m².
Radius of cone r = 24/2 = 12 cm and slant height l = 21 cm
Total surface area of cone = πr(r + l)
= 22/7 × 12 × (12 + 21)
= 22/7 × 12 × 33
= 1244.57 m²
Hence, the total surface area of cone is 1244.57 m².
(i) curved surface area of cone = 308 cm² and slant height l = 14 cm. Let, the radius of base of cone = r cm Curved surface area of cone = πrl ⇒ 308 = 22/7 × r × 14 ⇒ 308 = 44r ⇒ r = 308/44 = 7 cm Hence, the radius of base of cone is 7 cm. (ii) Total surface area of cone = πr(r + l) = 22/7 × 7 × (7Read more
(i) curved surface area of cone = 308 cm² and slant height l = 14 cm.
Let, the radius of base of cone = r cm
Curved surface area of cone = πrl
⇒ 308 = 22/7 × r × 14
⇒ 308 = 44r
⇒ r = 308/44 = 7 cm
Hence, the radius of base of cone is 7 cm.
(ii) Total surface area of cone = πr(r + l)
= 22/7 × 7 × (7 + 14)
= 22 × 21
= 462 cm²
Hence, the total surface area of cone is 462 cm².
Radius of cone r = 24 m and height h = 10 m Let, the slant height = l m We know that, l² = r² + h² ⇒ l² = 24² + 10² = 576 + 100 = 676 ⇒ l = √676 = 26 m
Radius of cone r = 24 m and height h = 10 m
Let, the slant height = l m
We know that, l² = r² + h²
⇒ l² = 24² + 10² = 576 + 100 = 676
⇒ l = √676 = 26 m
Radius of cone r = 6 m and height h = 8 m let, the slant height = l m We know that, l² = r² + h² ⇒ l² = 6² + 8² = 36 + 64 = 100 ⇒ l = √100 = 10 m Area of tarpaulin to make the tent = πrl = 3.14 × 6 × 10 = 188.40 m² Let, the length of 3 m wide tarpaulin = L Therefore, the area of tarpaulin required =Read more
Radius of cone r = 6 m and height h = 8 m
let, the slant height = l m
We know that, l² = r² + h²
⇒ l² = 6² + 8² = 36 + 64 = 100
⇒ l = √100 = 10 m
Area of tarpaulin to make the tent = πrl
= 3.14 × 6 × 10 = 188.40 m²
Let, the length of 3 m wide tarpaulin = L
Therefore, the area of tarpaulin required = 3 × L
According to question,
3 × L = 188.40
⇒ L = 188.40/3 = 62.80 m
Extra tarpaulin for stitching margins and wastage = 20 cm = 0.20 m
Therefore, the total lenght of tarpaulin = 62.80 + 0.20 = 63 m
Hence, the length of 3 m wide tarpaulin is 63 m to make the tent.
Total surface area of cylindrical Petrol storage tank = 2πr(r + h) = 2 × 22/7 × 2.1 × (2.1 + 4.5) = 2 × 22/7 × 2.1 × 6.6 = 87. 12 m² Let, the area of steel used to make this cylindrical petrol storage tank = x m² Steel get wasted in preparation of petrol storage tank = 1/12x m² Therefore, the totalRead more
Total surface area of cylindrical Petrol storage tank = 2πr(r + h)
= 2 × 22/7 × 2.1 × (2.1 + 4.5) = 2 × 22/7 × 2.1 × 6.6 = 87. 12 m²
Let, the area of steel used to make this cylindrical petrol storage tank = x m²
Steel get wasted in preparation of petrol storage tank = 1/12x m²
Therefore, the total steel used in cylindrical petrol storage tank = x – 1/12x = 11/12x m²
According to the questions: 11/12x = 87.12 ⇒ x = 87.12 × 12/11 = 95.04 m²
Hence, 95.04 m² steel is required to make this cylindrical petrol storage tank.
Find the total surface area of a cone, if its slant height is 21 m and diameter of its base is 24 m.
Radius of cone r = 24/2 = 12 cm and slant height l = 21 cm Total surface area of cone = πr(r + l) = 22/7 × 12 × (12 + 21) = 22/7 × 12 × 33 = 1244.57 m² Hence, the total surface area of cone is 1244.57 m².
Radius of cone r = 24/2 = 12 cm and slant height l = 21 cm
Total surface area of cone = πr(r + l)
= 22/7 × 12 × (12 + 21)
= 22/7 × 12 × 33
= 1244.57 m²
Hence, the total surface area of cone is 1244.57 m².
Curved surface area of a cone is 308 cm² and its slant height is 14 cm. Find (i) radius of the base and (ii) total surface area of the cone.
(i) curved surface area of cone = 308 cm² and slant height l = 14 cm. Let, the radius of base of cone = r cm Curved surface area of cone = πrl ⇒ 308 = 22/7 × r × 14 ⇒ 308 = 44r ⇒ r = 308/44 = 7 cm Hence, the radius of base of cone is 7 cm. (ii) Total surface area of cone = πr(r + l) = 22/7 × 7 × (7Read more
(i) curved surface area of cone = 308 cm² and slant height l = 14 cm.
Let, the radius of base of cone = r cm
Curved surface area of cone = πrl
⇒ 308 = 22/7 × r × 14
⇒ 308 = 44r
⇒ r = 308/44 = 7 cm
Hence, the radius of base of cone is 7 cm.
(ii) Total surface area of cone = πr(r + l)
= 22/7 × 7 × (7 + 14)
= 22 × 21
= 462 cm²
Hence, the total surface area of cone is 462 cm².
A conical tent is 10 m high and the radius of its base is 24 m. Find slant height of the tent.
Radius of cone r = 24 m and height h = 10 m Let, the slant height = l m We know that, l² = r² + h² ⇒ l² = 24² + 10² = 576 + 100 = 676 ⇒ l = √676 = 26 m
Radius of cone r = 24 m and height h = 10 m
Let, the slant height = l m
We know that, l² = r² + h²
⇒ l² = 24² + 10² = 576 + 100 = 676
⇒ l = √676 = 26 m
What length of tarpaulin 3 m wide will be required to make conical tent of height 8 m and base radius 6 m? Assume that the extra length of material that will be required for stitching margins and wastage in cutting is approximately 20 cm (Use π= 3.14).
Radius of cone r = 6 m and height h = 8 m let, the slant height = l m We know that, l² = r² + h² ⇒ l² = 6² + 8² = 36 + 64 = 100 ⇒ l = √100 = 10 m Area of tarpaulin to make the tent = πrl = 3.14 × 6 × 10 = 188.40 m² Let, the length of 3 m wide tarpaulin = L Therefore, the area of tarpaulin required =Read more
Radius of cone r = 6 m and height h = 8 m
let, the slant height = l m
We know that, l² = r² + h²
⇒ l² = 6² + 8² = 36 + 64 = 100
⇒ l = √100 = 10 m
Area of tarpaulin to make the tent = πrl
= 3.14 × 6 × 10 = 188.40 m²
Let, the length of 3 m wide tarpaulin = L
Therefore, the area of tarpaulin required = 3 × L
According to question,
3 × L = 188.40
⇒ L = 188.40/3 = 62.80 m
Extra tarpaulin for stitching margins and wastage = 20 cm = 0.20 m
Therefore, the total lenght of tarpaulin = 62.80 + 0.20 = 63 m
Hence, the length of 3 m wide tarpaulin is 63 m to make the tent.
Find how much steel was actually used, if 1/12 of the steel actually used was wasted in making the tank.
Total surface area of cylindrical Petrol storage tank = 2πr(r + h) = 2 × 22/7 × 2.1 × (2.1 + 4.5) = 2 × 22/7 × 2.1 × 6.6 = 87. 12 m² Let, the area of steel used to make this cylindrical petrol storage tank = x m² Steel get wasted in preparation of petrol storage tank = 1/12x m² Therefore, the totalRead more
Total surface area of cylindrical Petrol storage tank = 2πr(r + h)
= 2 × 22/7 × 2.1 × (2.1 + 4.5) = 2 × 22/7 × 2.1 × 6.6 = 87. 12 m²
Let, the area of steel used to make this cylindrical petrol storage tank = x m²
Steel get wasted in preparation of petrol storage tank = 1/12x m²
Therefore, the total steel used in cylindrical petrol storage tank = x – 1/12x = 11/12x m²
According to the questions: 11/12x = 87.12 ⇒ x = 87.12 × 12/11 = 95.04 m²
Hence, 95.04 m² steel is required to make this cylindrical petrol storage tank.