Radius of cone r = 40/2 = 20 cm = 0.2 m and height h = 1 m Let the slant height = lm We know that l² = r² + h² ⇒ l² = (0.2)² + 1² = 0.04 + 1 = 1.04 ⇒ l = √1.04 = 1.02 m Curved surface area of 50 cones = 50 × 6.4056 = 32.028 m² Cost of painting at the rate of Rs 12 per m² = Rs 12 × 32.028 = 384.34 (aRead more
Radius of cone r = 40/2 = 20 cm = 0.2 m and height h = 1 m
Let the slant height = lm
We know that l² = r² + h²
⇒ l² = (0.2)² + 1² = 0.04 + 1 = 1.04
⇒ l = √1.04 = 1.02 m
Curved surface area of 50 cones = 50 × 6.4056 = 32.028 m²
Cost of painting at the rate of Rs 12 per m² = Rs 12 × 32.028 = 384.34 (approx.)
Hence, the cost of painting the curved surface of 50 cones is Rs 384.34.
Radius of cone r = 24/2 = 12 cm and slant height l = 21 cm Total surface area of cone = πr(r + l) = 22/7 × 12 × (12 + 21) = 22/7 × 12 × 33 = 1244.57 m² Hence, the total surface area of cone is 1244.57 m².
Radius of cone r = 24/2 = 12 cm and slant height l = 21 cm
Total surface area of cone = πr(r + l)
= 22/7 × 12 × (12 + 21)
= 22/7 × 12 × 33
= 1244.57 m²
Hence, the total surface area of cone is 1244.57 m².
(i) curved surface area of cone = 308 cm² and slant height l = 14 cm. Let, the radius of base of cone = r cm Curved surface area of cone = πrl ⇒ 308 = 22/7 × r × 14 ⇒ 308 = 44r ⇒ r = 308/44 = 7 cm Hence, the radius of base of cone is 7 cm. (ii) Total surface area of cone = πr(r + l) = 22/7 × 7 × (7Read more
(i) curved surface area of cone = 308 cm² and slant height l = 14 cm.
Let, the radius of base of cone = r cm
Curved surface area of cone = πrl
⇒ 308 = 22/7 × r × 14
⇒ 308 = 44r
⇒ r = 308/44 = 7 cm
Hence, the radius of base of cone is 7 cm.
(ii) Total surface area of cone = πr(r + l)
= 22/7 × 7 × (7 + 14)
= 22 × 21
= 462 cm²
Hence, the total surface area of cone is 462 cm².
Radius of cone r = 24 m and height h = 10 m Let, the slant height = l m We know that, l² = r² + h² ⇒ l² = 24² + 10² = 576 + 100 = 676 ⇒ l = √676 = 26 m
Radius of cone r = 24 m and height h = 10 m
Let, the slant height = l m
We know that, l² = r² + h²
⇒ l² = 24² + 10² = 576 + 100 = 676
⇒ l = √676 = 26 m
Area of convas to make the tent = πrl = 22/7 × 24 × 26 m² cost of 1 m² convas = Rs 70 Therefore, the cost of 22/7 × 24 × 26 m² canvas = Rs 70 × 22/7 × 24 × 26 = Rs 137280 Hence, the cost of canvas to make the tent is 137280.
Area of convas to make the tent = πrl
= 22/7 × 24 × 26 m²
cost of 1 m² convas = Rs 70
Therefore, the cost of 22/7 × 24 × 26 m² canvas = Rs 70 × 22/7 × 24 × 26 = Rs 137280
Hence, the cost of canvas to make the tent is 137280.
A bus stop is barricaded from the remaining part of the road, by using 50 hollow cones made of recycled cardboard. Each cone has a base diameter of 40 cm and height 1 m. If the outer side of each of the cones is to be painted and the cost of painting is Rs 12 per m², what will be the cost of painting all these cones? (Use π= 3.14 and take √(1.04 )= 1.02)
Radius of cone r = 40/2 = 20 cm = 0.2 m and height h = 1 m Let the slant height = lm We know that l² = r² + h² ⇒ l² = (0.2)² + 1² = 0.04 + 1 = 1.04 ⇒ l = √1.04 = 1.02 m Curved surface area of 50 cones = 50 × 6.4056 = 32.028 m² Cost of painting at the rate of Rs 12 per m² = Rs 12 × 32.028 = 384.34 (aRead more
Radius of cone r = 40/2 = 20 cm = 0.2 m and height h = 1 m
See lessLet the slant height = lm
We know that l² = r² + h²
⇒ l² = (0.2)² + 1² = 0.04 + 1 = 1.04
⇒ l = √1.04 = 1.02 m
Curved surface area of 50 cones = 50 × 6.4056 = 32.028 m²
Cost of painting at the rate of Rs 12 per m² = Rs 12 × 32.028 = 384.34 (approx.)
Hence, the cost of painting the curved surface of 50 cones is Rs 384.34.
Find the total surface area of a cone, if its slant height is 21 m and diameter of its base is 24 m.
Radius of cone r = 24/2 = 12 cm and slant height l = 21 cm Total surface area of cone = πr(r + l) = 22/7 × 12 × (12 + 21) = 22/7 × 12 × 33 = 1244.57 m² Hence, the total surface area of cone is 1244.57 m².
Radius of cone r = 24/2 = 12 cm and slant height l = 21 cm
See lessTotal surface area of cone = πr(r + l)
= 22/7 × 12 × (12 + 21)
= 22/7 × 12 × 33
= 1244.57 m²
Hence, the total surface area of cone is 1244.57 m².
Curved surface area of a cone is 308 cm² and its slant height is 14 cm. Find (i) radius of the base and (ii) total surface area of the cone.
(i) curved surface area of cone = 308 cm² and slant height l = 14 cm. Let, the radius of base of cone = r cm Curved surface area of cone = πrl ⇒ 308 = 22/7 × r × 14 ⇒ 308 = 44r ⇒ r = 308/44 = 7 cm Hence, the radius of base of cone is 7 cm. (ii) Total surface area of cone = πr(r + l) = 22/7 × 7 × (7Read more
(i) curved surface area of cone = 308 cm² and slant height l = 14 cm.
Let, the radius of base of cone = r cm
Curved surface area of cone = πrl
⇒ 308 = 22/7 × r × 14
⇒ 308 = 44r
⇒ r = 308/44 = 7 cm
Hence, the radius of base of cone is 7 cm.
(ii) Total surface area of cone = πr(r + l)
See less= 22/7 × 7 × (7 + 14)
= 22 × 21
= 462 cm²
Hence, the total surface area of cone is 462 cm².
A conical tent is 10 m high and the radius of its base is 24 m. Find slant height of the tent.
Radius of cone r = 24 m and height h = 10 m Let, the slant height = l m We know that, l² = r² + h² ⇒ l² = 24² + 10² = 576 + 100 = 676 ⇒ l = √676 = 26 m
Radius of cone r = 24 m and height h = 10 m
See lessLet, the slant height = l m
We know that, l² = r² + h²
⇒ l² = 24² + 10² = 576 + 100 = 676
⇒ l = √676 = 26 m
A conical tent is 10 m high and the radius of its base is 24 m. Find cost of the canvas required to make the tent, if the cost of 1 m² canvas is Rs 70.
Area of convas to make the tent = πrl = 22/7 × 24 × 26 m² cost of 1 m² convas = Rs 70 Therefore, the cost of 22/7 × 24 × 26 m² canvas = Rs 70 × 22/7 × 24 × 26 = Rs 137280 Hence, the cost of canvas to make the tent is 137280.
Area of convas to make the tent = πrl
See less= 22/7 × 24 × 26 m²
cost of 1 m² convas = Rs 70
Therefore, the cost of 22/7 × 24 × 26 m² canvas = Rs 70 × 22/7 × 24 × 26 = Rs 137280
Hence, the cost of canvas to make the tent is 137280.