Radius of cone r = 6 m and height h = 8 m let, the slant height = l m We know that, l² = r² + h² ⇒ l² = 6² + 8² = 36 + 64 = 100 ⇒ l = √100 = 10 m Area of tarpaulin to make the tent = πrl = 3.14 × 6 × 10 = 188.40 m² Let, the length of 3 m wide tarpaulin = L Therefore, the area of tarpaulin required =Read more
Radius of cone r = 6 m and height h = 8 m
let, the slant height = l m
We know that, l² = r² + h²
⇒ l² = 6² + 8² = 36 + 64 = 100
⇒ l = √100 = 10 m
Area of tarpaulin to make the tent = πrl
= 3.14 × 6 × 10 = 188.40 m²
Let, the length of 3 m wide tarpaulin = L
Therefore, the area of tarpaulin required = 3 × L
According to question,
3 × L = 188.40
⇒ L = 188.40/3 = 62.80 m
Extra tarpaulin for stitching margins and wastage = 20 cm = 0.20 m
Therefore, the total lenght of tarpaulin = 62.80 + 0.20 = 63 m
Hence, the length of 3 m wide tarpaulin is 63 m to make the tent.
Radius of conical tomb r = 14/2 = 7 m and slant height l = 25 m Curved surface area of conical tomb = πrl = 22/7 × 7 × 25 = 550 m² Cost of white washing at the rate of Rs 210 per 100 m² = Rs 550 × 210/100 = Rs. 1155 Hence, the cost of white washing curved surface area is Rs 1155.
Radius of conical tomb r = 14/2 = 7 m and slant height l = 25 m
Curved surface area of conical tomb = πrl
= 22/7 × 7 × 25 = 550 m²
Cost of white washing at the rate of Rs 210 per 100 m² = Rs 550 × 210/100 = Rs. 1155
Hence, the cost of white washing curved surface area is Rs 1155.
Radius of right circular cone r = 7 cm and height h = 24 cm Let, the slant height = l m We know that l² = r² + h² ⇒ l² = 7² + 24² = 49 + 576 = 625 ⇒ l = √625 = 25 cm Area of sheet required to make 1 cap = πrl = 22/7 ×7 × 25 = 550 cm² Therefore, area of sheet required to make 10 such caps = 10 × 550Read more
Radius of right circular cone r = 7 cm and height h = 24 cm
Let, the slant height = l m
We know that l² = r² + h²
⇒ l² = 7² + 24² = 49 + 576 = 625
⇒ l = √625 = 25 cm
Area of sheet required to make 1 cap = πrl
= 22/7 ×7 × 25 = 550 cm²
Therefore, area of sheet required to make 10 such caps = 10 × 550 = 5500 cm²
Hence, area of sheet to make 10 such caps is 5500 cm²
Total surface area of cylindrical Petrol storage tank = 2πr(r + h) = 2 × 22/7 × 2.1 × (2.1 + 4.5) = 2 × 22/7 × 2.1 × 6.6 = 87. 12 m² Let, the area of steel used to make this cylindrical petrol storage tank = x m² Steel get wasted in preparation of petrol storage tank = 1/12x m² Therefore, the totalRead more
Total surface area of cylindrical Petrol storage tank = 2πr(r + h)
= 2 × 22/7 × 2.1 × (2.1 + 4.5) = 2 × 22/7 × 2.1 × 6.6 = 87. 12 m²
Let, the area of steel used to make this cylindrical petrol storage tank = x m²
Steel get wasted in preparation of petrol storage tank = 1/12x m²
Therefore, the total steel used in cylindrical petrol storage tank = x – 1/12x = 11/12x m²
According to the questions: 11/12x = 87.12 ⇒ x = 87.12 × 12/11 = 95.04 m²
Hence, 95.04 m² steel is required to make this cylindrical petrol storage tank.
What length of tarpaulin 3 m wide will be required to make conical tent of height 8 m and base radius 6 m? Assume that the extra length of material that will be required for stitching margins and wastage in cutting is approximately 20 cm (Use π= 3.14).
Radius of cone r = 6 m and height h = 8 m let, the slant height = l m We know that, l² = r² + h² ⇒ l² = 6² + 8² = 36 + 64 = 100 ⇒ l = √100 = 10 m Area of tarpaulin to make the tent = πrl = 3.14 × 6 × 10 = 188.40 m² Let, the length of 3 m wide tarpaulin = L Therefore, the area of tarpaulin required =Read more
Radius of cone r = 6 m and height h = 8 m
See lesslet, the slant height = l m
We know that, l² = r² + h²
⇒ l² = 6² + 8² = 36 + 64 = 100
⇒ l = √100 = 10 m
Area of tarpaulin to make the tent = πrl
= 3.14 × 6 × 10 = 188.40 m²
Let, the length of 3 m wide tarpaulin = L
Therefore, the area of tarpaulin required = 3 × L
According to question,
3 × L = 188.40
⇒ L = 188.40/3 = 62.80 m
Extra tarpaulin for stitching margins and wastage = 20 cm = 0.20 m
Therefore, the total lenght of tarpaulin = 62.80 + 0.20 = 63 m
Hence, the length of 3 m wide tarpaulin is 63 m to make the tent.
The slant height and base diameter of a conical tomb are 25 m and 14 m respectively. Find the cost of white-washing its curved surface at the rate of Rs 210 per 100 m².
Radius of conical tomb r = 14/2 = 7 m and slant height l = 25 m Curved surface area of conical tomb = πrl = 22/7 × 7 × 25 = 550 m² Cost of white washing at the rate of Rs 210 per 100 m² = Rs 550 × 210/100 = Rs. 1155 Hence, the cost of white washing curved surface area is Rs 1155.
Radius of conical tomb r = 14/2 = 7 m and slant height l = 25 m
See lessCurved surface area of conical tomb = πrl
= 22/7 × 7 × 25 = 550 m²
Cost of white washing at the rate of Rs 210 per 100 m² = Rs 550 × 210/100 = Rs. 1155
Hence, the cost of white washing curved surface area is Rs 1155.
A joker’s cap is in the form of a right circular cone of base radius 7 cm and height 24 cm. Find the area of the sheet required to make 10 such caps.
Radius of right circular cone r = 7 cm and height h = 24 cm Let, the slant height = l m We know that l² = r² + h² ⇒ l² = 7² + 24² = 49 + 576 = 625 ⇒ l = √625 = 25 cm Area of sheet required to make 1 cap = πrl = 22/7 ×7 × 25 = 550 cm² Therefore, area of sheet required to make 10 such caps = 10 × 550Read more
Radius of right circular cone r = 7 cm and height h = 24 cm
See lessLet, the slant height = l m
We know that l² = r² + h²
⇒ l² = 7² + 24² = 49 + 576 = 625
⇒ l = √625 = 25 cm
Area of sheet required to make 1 cap = πrl
= 22/7 ×7 × 25 = 550 cm²
Therefore, area of sheet required to make 10 such caps = 10 × 550 = 5500 cm²
Hence, area of sheet to make 10 such caps is 5500 cm²
A joker’s cap is in the form of a right circular cone of base radius 7 cm and height 24 cm. Find the area of the sheet required to make 10 such caps.
Find how much steel was actually used, if 1/12 of the steel actually used was wasted in making the tank.
Total surface area of cylindrical Petrol storage tank = 2πr(r + h) = 2 × 22/7 × 2.1 × (2.1 + 4.5) = 2 × 22/7 × 2.1 × 6.6 = 87. 12 m² Let, the area of steel used to make this cylindrical petrol storage tank = x m² Steel get wasted in preparation of petrol storage tank = 1/12x m² Therefore, the totalRead more
Total surface area of cylindrical Petrol storage tank = 2πr(r + h)
See less= 2 × 22/7 × 2.1 × (2.1 + 4.5) = 2 × 22/7 × 2.1 × 6.6 = 87. 12 m²
Let, the area of steel used to make this cylindrical petrol storage tank = x m²
Steel get wasted in preparation of petrol storage tank = 1/12x m²
Therefore, the total steel used in cylindrical petrol storage tank = x – 1/12x = 11/12x m²
According to the questions: 11/12x = 87.12 ⇒ x = 87.12 × 12/11 = 95.04 m²
Hence, 95.04 m² steel is required to make this cylindrical petrol storage tank.