3(t-3) =5(2t+1) ⟹ 3t-9=10t+5 ⟹ 3t-10t=5+9 ⟹-7t=14 ⟹ t=14/-7 ⟹ t=-2 To check: 3(t-3) =5(2t+1) ⟹ 3(-2-3)=5{2X(-2)+1} ⟹ 3X-5=5(-4+1) ⟹ -15=5X(-3) ⟹ -15=-15 ⟹ L.H.S. = R. H. S. Therefore, it is correct. Class 8 Maths Chapter 2 Exercise 2.5 Solution in Video for more answers vist to: https://www.tiwariacRead more
3(t-3) =5(2t+1)
⟹ 3t-9=10t+5 ⟹ 3t-10t=5+9 ⟹-7t=14
⟹ t=14/-7 ⟹ t=-2
To check:
3(t-3) =5(2t+1)
⟹ 3(-2-3)=5{2X(-2)+1} ⟹ 3X-5=5(-4+1) ⟹ -15=5X(-3)
⟹ -15=-15 ⟹ L.H.S. = R. H. S.
Therefore, it is correct.
Class 8 Maths Chapter 2 Exercise 2.5 Solution in Video
x-5/3 = x-3/5 ⟹ 5X(x-5) =3 (x-3) ⟹ 5x-25=3x-9 ⟹ 5x-3x= -9+25 ⟹ 2x=16 ⟹ x=16/2=8 To check: x-5/3 = x-3/5 ⟹ 8-5/3 = 8-3/5 ⟹ 3/3=5/5 ⟹ 1 = 1 ⟹ L.H.S. = R. H. S Therefore, it is correct. Class 8 Maths Chapter 2 Exercise 2.5 Solution in Video for more answers vist to: https://www.tiwariacademy.com/ncert-Read more
x-5/3 = x-3/5
⟹ 5X(x-5) =3 (x-3) ⟹ 5x-25=3x-9
⟹ 5x-3x= -9+25 ⟹ 2x=16 ⟹ x=16/2=8
To check:
x-5/3 = x-3/5
⟹ 8-5/3 = 8-3/5 ⟹ 3/3=5/5 ⟹ 1 = 1
⟹ L.H.S. = R. H. S
Therefore, it is correct.
Class 8 Maths Chapter 2 Exercise 2.5 Solution in Video
n/2 – 3n/4 + 5n/6 = 21 ⟹ 6n-9n+10n/12 =21 ⟹ 7n/12=21 ⟹ n=21x12/7 ⟹ n=36 To check: n/2 - 3n/4 + 5n/6 = 21 ⟹ 36/2 - 3x36/4 + 5x36/6 =21 ⟹ 18-27+30=21 ⟹ 21=21 ⟹ L.H.S. = R. H. S. Therefore, it is correct. Class 8 Maths Chapter 2 Exercise 2.5 Solution in Video for more answers vist to: https://www.tiwarRead more
n/2 – 3n/4 + 5n/6 = 21
⟹ 6n-9n+10n/12 =21 ⟹ 7n/12=21 ⟹ n=21×12/7 ⟹ n=36
To check:
n/2 – 3n/4 + 5n/6 = 21
⟹ 36/2 – 3×36/4 + 5×36/6 =21 ⟹ 18-27+30=21 ⟹ 21=21
⟹ L.H.S. = R. H. S.
Therefore, it is correct.
Class 8 Maths Chapter 2 Exercise 2.5 Solution in Video
Simplify and solve the following linear equation: 3(t-3) =5(2t+1)
3(t-3) =5(2t+1) ⟹ 3t-9=10t+5 ⟹ 3t-10t=5+9 ⟹-7t=14 ⟹ t=14/-7 ⟹ t=-2 To check: 3(t-3) =5(2t+1) ⟹ 3(-2-3)=5{2X(-2)+1} ⟹ 3X-5=5(-4+1) ⟹ -15=5X(-3) ⟹ -15=-15 ⟹ L.H.S. = R. H. S. Therefore, it is correct. Class 8 Maths Chapter 2 Exercise 2.5 Solution in Video for more answers vist to: https://www.tiwariacRead more
3(t-3) =5(2t+1)
⟹ 3t-9=10t+5 ⟹ 3t-10t=5+9 ⟹-7t=14
⟹ t=14/-7 ⟹ t=-2
To check:
3(t-3) =5(2t+1)
⟹ 3(-2-3)=5{2X(-2)+1} ⟹ 3X-5=5(-4+1) ⟹ -15=5X(-3)
⟹ -15=-15 ⟹ L.H.S. = R. H. S.
Therefore, it is correct.
Class 8 Maths Chapter 2 Exercise 2.5 Solution in Video
for more answers vist to:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-8/maths/chapter-2/
Solve the following linear equation: m – m-1/2 = (1)- m-2/3
m – m-1/2 = (1)- m-2/3 ⟹ m/1 - m-1/2 + m-2/3 = 1 ⟹ 6m-3(m-1)+2(m-2)/6 =1 ⟹ 6m-3m+3+2m-4/6 = 1 ⟹ 5m-1/6 =1 ⟹ 5m-1=6 ⟹ 5m+6+1 ⟹ 5m=7 ⟹ m=7/5 Class 8 Maths Chapter 2 Exercise 2.5 Solution in Video for more answers vist to: https://www.tiwariacademy.com/ncert-solutions/class-8/maths/chapter-2/
m – m-1/2 = (1)- m-2/3
⟹ m/1 – m-1/2 + m-2/3 = 1 ⟹ 6m-3(m-1)+2(m-2)/6 =1
⟹ 6m-3m+3+2m-4/6 = 1 ⟹ 5m-1/6 =1 ⟹ 5m-1=6
⟹ 5m+6+1 ⟹ 5m=7 ⟹ m=7/5
Class 8 Maths Chapter 2 Exercise 2.5 Solution in Video
for more answers vist to:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-8/maths/chapter-2/
Solve the following linear equation: 3t-2/4 – 2t+3/3 = 2/3 – t
3t-2/4 – 2t+3/3 = 2/3 – t ⟹ 3t-2/4 - 2t+3/3 + t=2/3 ⟹ 3(3t-2)-4(2t+3)+12t/12 = 2/3 ⟹ 9t-6-8t-12+12t/12 = 2/3 ⟹ 13t-18/12 = 2/3 ⟹ 3x(13t-18)=2 x 12 ⟹ 39t-54=24 ⟹ 39t=24+54 ⟹ 39t=78 ⟹ t=78/39=2 To check: 3t-2/4 – 2t+3/3 = 2/3 – t ⟹ 3X2-2/4 - 2x2+3/3 = 2/3 -2 ⟹ 6-2/4 - 4+3/3 = 2-6/3 ⟹ 4/4 - 7/3 = -4/3Read more
3t-2/4 – 2t+3/3 = 2/3 – t
⟹ 3t-2/4 – 2t+3/3 + t=2/3 ⟹ 3(3t-2)-4(2t+3)+12t/12 = 2/3
⟹ 9t-6-8t-12+12t/12 = 2/3 ⟹ 13t-18/12 = 2/3
⟹ 3x(13t-18)=2 x 12 ⟹ 39t-54=24 ⟹ 39t=24+54
⟹ 39t=78 ⟹ t=78/39=2
To check:
3t-2/4 – 2t+3/3 = 2/3 – t
⟹ 3X2-2/4 – 2×2+3/3 = 2/3 -2 ⟹ 6-2/4 – 4+3/3 = 2-6/3
⟹ 4/4 – 7/3 = -4/3 ⟹ 1/1-7/3=-4/3
⟹ 3-7/3 = -4/3 ⟹ -4/3 = -4/3
⟹ L.H.S. = R. H. S. Therefore, it is correct.
Class 8 Maths Chapter 2 Exercise 2.5 Solution in Video
for more answers vist to:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-8/maths/chapter-2/
Solve the following linear equation: x-5/3 = x-3/5
x-5/3 = x-3/5 ⟹ 5X(x-5) =3 (x-3) ⟹ 5x-25=3x-9 ⟹ 5x-3x= -9+25 ⟹ 2x=16 ⟹ x=16/2=8 To check: x-5/3 = x-3/5 ⟹ 8-5/3 = 8-3/5 ⟹ 3/3=5/5 ⟹ 1 = 1 ⟹ L.H.S. = R. H. S Therefore, it is correct. Class 8 Maths Chapter 2 Exercise 2.5 Solution in Video for more answers vist to: https://www.tiwariacademy.com/ncert-Read more
x-5/3 = x-3/5
⟹ 5X(x-5) =3 (x-3) ⟹ 5x-25=3x-9
⟹ 5x-3x= -9+25 ⟹ 2x=16 ⟹ x=16/2=8
To check:
x-5/3 = x-3/5
⟹ 8-5/3 = 8-3/5 ⟹ 3/3=5/5 ⟹ 1 = 1
⟹ L.H.S. = R. H. S
Therefore, it is correct.
Class 8 Maths Chapter 2 Exercise 2.5 Solution in Video
for more answers vist to:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-8/maths/chapter-2/
Solve the following linear equation: x+7 – 8x/3 = 17/6 – 5x/2
x+7 – 8x/3 = 17/6 – 5x/2 ⟹ x/1 - 8x/3 + 5x/2 = 17/6 - 7/1 ⟹ 6x-16x+15x/6 = 17-42/6 ⟹ 5x/6 = -25/6 ⟹ x= -25x6/6x5 ⟹ x=-5 To check: x+7 – 8x/3 = 17/6 – 5x/2 ⟹ -5+7- 8x(-5)/3 = 17/6 - 5x(-5)/2 ⟹ 2+ 40/3=17/6+25/2 ⟹ 6+40/3 = 17+75/6 ⟹ 46/3 = 92/6 ⟹ 46/3=46/3 ⟹ L.H.S. = R. H. S. Therefore, it is correct.Read more
x+7 – 8x/3 = 17/6 – 5x/2
⟹ x/1 – 8x/3 + 5x/2 = 17/6 – 7/1 ⟹ 6x-16x+15x/6 = 17-42/6
⟹ 5x/6 = -25/6 ⟹ x= -25×6/6×5 ⟹ x=-5
To check:
x+7 – 8x/3 = 17/6 – 5x/2
⟹ -5+7- 8x(-5)/3 = 17/6 – 5x(-5)/2 ⟹ 2+ 40/3=17/6+25/2
⟹ 6+40/3 = 17+75/6 ⟹ 46/3 = 92/6 ⟹ 46/3=46/3
⟹ L.H.S. = R. H. S.
Therefore, it is correct.
Class 8 Maths Chapter 2 Exercise 2.5 Solution in Video
for more answers vist to:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-8/maths/chapter-2/
Solve the following linear equation: n/2 – 3n/4 + 5n/6=21
n/2 – 3n/4 + 5n/6 = 21 ⟹ 6n-9n+10n/12 =21 ⟹ 7n/12=21 ⟹ n=21x12/7 ⟹ n=36 To check: n/2 - 3n/4 + 5n/6 = 21 ⟹ 36/2 - 3x36/4 + 5x36/6 =21 ⟹ 18-27+30=21 ⟹ 21=21 ⟹ L.H.S. = R. H. S. Therefore, it is correct. Class 8 Maths Chapter 2 Exercise 2.5 Solution in Video for more answers vist to: https://www.tiwarRead more
n/2 – 3n/4 + 5n/6 = 21
⟹ 6n-9n+10n/12 =21 ⟹ 7n/12=21 ⟹ n=21×12/7 ⟹ n=36
To check:
n/2 – 3n/4 + 5n/6 = 21
⟹ 36/2 – 3×36/4 + 5×36/6 =21 ⟹ 18-27+30=21 ⟹ 21=21
⟹ L.H.S. = R. H. S.
Therefore, it is correct.
Class 8 Maths Chapter 2 Exercise 2.5 Solution in Video
for more answers vist to:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-8/maths/chapter-2/
Solve the following linear equation: x/2 – 1/5 = x/3 + ¼
x/2 – 1/5 = x/3 + 1/4 ⟹ x/2-x/3 = 1/4+1/5 ⟹ 3x-2x/6 = 5+4/20 ⟹ x/6=9/20 ⟹ x=9x6/20=27/10 To check: x/2-1/5=x/3+1/4 ⟹ 27/10x2 - 1/5 = 27/10x3 + 1/4 ⟹ 27/20 - 1/5 = 9/10 + 1/4 ⟹ 27-4/20 = 18+5/20 ⟹ 23/20 = 23/20 ⟹ L.H.S. = R. H. S. Therefore, it is correct. Class 8 Maths Chapter 2 Exercise 2.5 SolutioRead more
x/2 – 1/5 = x/3 + 1/4
⟹ x/2-x/3 = 1/4+1/5 ⟹ 3x-2x/6 = 5+4/20 ⟹ x/6=9/20 ⟹ x=9×6/20=27/10
To check:
x/2-1/5=x/3+1/4
⟹ 27/10×2 – 1/5 = 27/10×3 + 1/4 ⟹ 27/20 – 1/5 = 9/10 + 1/4
⟹ 27-4/20 = 18+5/20 ⟹ 23/20 = 23/20
⟹ L.H.S. = R. H. S.
Therefore, it is correct.
Class 8 Maths Chapter 2 Exercise 2.5 Solution in Video
for more answers vist to:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-8/maths/chapter-2/