Let the numerator of a rational number be x, then the denominator is x+8. Therefore, Rational number = x/x+8 According to the question, x+17/x+8-1=3/2 ⟹ x+17/x+7 =3/2 ⟹ 2(x+17)=3(x+7) ⟹ 2x+34=3x+21 ⟹ 2x-3x=21-34 ⟹ -x=-13 ⟹ x=13 Hence, the required rational number = x/x+8 = 13/13+8 =13/21 Class 8 MatRead more
Let the numerator of a rational number be x, then the denominator is x+8.
Therefore, Rational number = x/x+8
According to the question, x+17/x+8-1=3/2
⟹ x+17/x+7 =3/2
⟹ 2(x+17)=3(x+7)
⟹ 2x+34=3x+21
⟹ 2x-3x=21-34
⟹ -x=-13 ⟹ x=13
Hence, the required rational number = x/x+8 = 13/13+8 =13/21
Class 8 Maths Chapter 2 Exercise 2.6 Solution in Video
Let the Ages of Hari and Harry be 5x years and 7x years. According to question, 5x+4/7x+4 = 3/4 ⟹ 4(5x+4) =3(7x+4) ⟹ 20x+16=21x+12 ⟹ 20x-21x=12-16 ⟹ -x=-4 ⟹ x=4 Hence, the age of Hari = 5x = 5 x 4 = 20 years and the age of Harry = 7x = 7 x 4 = 28 years. Class 8 Maths Chapter 2 Exercise 2.6 SolutionRead more
Let the Ages of Hari and Harry be 5x years and 7x years.
According to question, 5x+4/7x+4 = 3/4
⟹ 4(5x+4) =3(7x+4)
⟹ 20x+16=21x+12
⟹ 20x-21x=12-16
⟹ -x=-4
⟹ x=4
Hence, the age of Hari = 5x = 5 x 4 = 20 years and the age of Harry = 7x = 7 x 4 = 28 years.
Class 8 Maths Chapter 2 Exercise 2.6 Solution in Video
7y+4/y+2 = -4/3 ⟹ 3(7y+4)=-4(y+2) ⟹ 21y+12=-4y-8 ⟹ 21y+4y=-8-12 ⟹ 25y=-20 ⟹ y=-20/25 ⟹ y=-4/5 Class 8 Maths Chapter 2 Exercise 2.6 Solution in Video for more answers vist to: https://www.tiwariacademy.com/ncert-solutions/class-8/maths/chapter-2/
z/z+15 = 4/9 ⟹ zx9=4(z=15) ⟹ 9z=4z+60 ⟹ 9z-4z=60 ⟹ 5z=60 ⟹ z=60/5 ⟹ z=12 Class 8 Maths Chapter 2 Exercise 2.6 Solution in Video for more answers vist to: https://www.tiwariacademy.com/ncert-solutions/class-8/maths/chapter-2/
9x/7-6x = 15 ⟹ 9x=15(7-6x) ⟹ 9x=105-90x ⟹ 9x+90x=105 ⟹ 99x=105 ⟹ x=105/99 ⟹ x=35/33 Class 8 Maths Chapter 2 Exercise 2.6 Solution in Video for more answers vist to: https://www.tiwariacademy.com/ncert-solutions/class-8/maths/chapter-2/
8x-3/3x = 2 ⟹ 8x-3=2x3x ⟹ 8x-3=6x ⟹ 8x-6x=3 ⟹ 2x=3 ⟹ x=3/2 Class 8 Maths Chapter 2 Exercise 2.6 Solution in Video for more answers vist to: https://www.tiwariacademy.com/ncert-solutions/class-8/maths/chapter-2/
0.25(4f-3) =0.05(10f-9) ⟹ 1.00f-0.75=0.50f-0.45 ⟹ 1.00f-0.50f =-0.45+0.75 ⟹ 0.50f =0.3 ⟹ f = 0.3/0.50 ⟹ f=0.6 To check: 0.25(4f-3)=0.05(10f-9) ⟹ 0.25(4X0.6-3)=0.05(10x0.6-9) ⟹ 0.25(2.4-3)=0.05(6.0-9) ⟹ 0.25x(-0.6) =0.05X(-3) ⟹ -0.150=-0.150 ⟹ L.H.S. = R. H. S. Therefore, it is correct. Class 8 MathsRead more
0.25(4f-3) =0.05(10f-9)
⟹ 1.00f-0.75=0.50f-0.45 ⟹ 1.00f-0.50f =-0.45+0.75
⟹ 0.50f =0.3 ⟹ f = 0.3/0.50 ⟹ f=0.6
To check:
0.25(4f-3)=0.05(10f-9) ⟹ 0.25(4X0.6-3)=0.05(10×0.6-9)
⟹ 0.25(2.4-3)=0.05(6.0-9) ⟹ 0.25x(-0.6) =0.05X(-3)
⟹ -0.150=-0.150 ⟹ L.H.S. = R. H. S.
Therefore, it is correct.
Class 8 Maths Chapter 2 Exercise 2.5 Solution in Video
15(y-4) -2 (y-9) +5 (y+6) =0 ⟹ 15y-60-2y+18+5y+30=0 ⟹ 18y-12=0 ⟹ 18y=12 ⟹ y-12/18 ⟹ y=2/3 Class 8 Maths Chapter 2 Exercise 2.5 Solution in Video for more answers vist to: https://www.tiwariacademy.com/ncert-solutions/class-8/maths/chapter-2/
The denominator of a rational number is greater than its numerator by 8. If the numerator is increased by 17 and the denominator is decreased by 1, the number obtained is 3/2 Find the rational number.
Let the numerator of a rational number be x, then the denominator is x+8. Therefore, Rational number = x/x+8 According to the question, x+17/x+8-1=3/2 ⟹ x+17/x+7 =3/2 ⟹ 2(x+17)=3(x+7) ⟹ 2x+34=3x+21 ⟹ 2x-3x=21-34 ⟹ -x=-13 ⟹ x=13 Hence, the required rational number = x/x+8 = 13/13+8 =13/21 Class 8 MatRead more
Let the numerator of a rational number be x, then the denominator is x+8.
Therefore, Rational number = x/x+8
According to the question, x+17/x+8-1=3/2
⟹ x+17/x+7 =3/2
⟹ 2(x+17)=3(x+7)
⟹ 2x+34=3x+21
⟹ 2x-3x=21-34
⟹ -x=-13 ⟹ x=13
Hence, the required rational number = x/x+8 = 13/13+8 =13/21
Class 8 Maths Chapter 2 Exercise 2.6 Solution in Video
for more answers vist to:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-8/maths/chapter-2/
The ages of Hari and Harry are in the ratio 5:7. Four years from now the ratio of their ages will be 3:4. Find their present ages.
Let the Ages of Hari and Harry be 5x years and 7x years. According to question, 5x+4/7x+4 = 3/4 ⟹ 4(5x+4) =3(7x+4) ⟹ 20x+16=21x+12 ⟹ 20x-21x=12-16 ⟹ -x=-4 ⟹ x=4 Hence, the age of Hari = 5x = 5 x 4 = 20 years and the age of Harry = 7x = 7 x 4 = 28 years. Class 8 Maths Chapter 2 Exercise 2.6 SolutionRead more
Let the Ages of Hari and Harry be 5x years and 7x years.
According to question, 5x+4/7x+4 = 3/4
⟹ 4(5x+4) =3(7x+4)
⟹ 20x+16=21x+12
⟹ 20x-21x=12-16
⟹ -x=-4
⟹ x=4
Hence, the age of Hari = 5x = 5 x 4 = 20 years and the age of Harry = 7x = 7 x 4 = 28 years.
Class 8 Maths Chapter 2 Exercise 2.6 Solution in Video
for more answers vist to:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-8/maths/chapter-2/
Solve the following equation: 7y+4/y+2 = -4/3
7y+4/y+2 = -4/3 ⟹ 3(7y+4)=-4(y+2) ⟹ 21y+12=-4y-8 ⟹ 21y+4y=-8-12 ⟹ 25y=-20 ⟹ y=-20/25 ⟹ y=-4/5 Class 8 Maths Chapter 2 Exercise 2.6 Solution in Video for more answers vist to: https://www.tiwariacademy.com/ncert-solutions/class-8/maths/chapter-2/
7y+4/y+2 = -4/3
⟹ 3(7y+4)=-4(y+2) ⟹ 21y+12=-4y-8
⟹ 21y+4y=-8-12 ⟹ 25y=-20
⟹ y=-20/25 ⟹ y=-4/5
Class 8 Maths Chapter 2 Exercise 2.6 Solution in Video
for more answers vist to:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-8/maths/chapter-2/
Solve the following equation: 3y+4/2-6y = -2/5
3y+4/2-6y = -2/5 ⟹ 5(3y+4)=-2(2-6y) ⟹ 15y + 20 = -4+12y ⟹ 15y - 12y =-4-20 ⟹ 3y=-24 ⟹ y=-24/3 ⟹ y=-8 Class 8 Maths Chapter 2 Exercise 2.6 Solution in Video for more answers vist to: https://www.tiwariacademy.com/ncert-solutions/class-8/maths/chapter-2/
3y+4/2-6y = -2/5
⟹ 5(3y+4)=-2(2-6y)
⟹ 15y + 20 = -4+12y
⟹ 15y – 12y =-4-20
⟹ 3y=-24
⟹ y=-24/3
⟹ y=-8
Class 8 Maths Chapter 2 Exercise 2.6 Solution in Video
for more answers vist to:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-8/maths/chapter-2/
Solve the following equation: z/z+15 = 4/9
z/z+15 = 4/9 ⟹ zx9=4(z=15) ⟹ 9z=4z+60 ⟹ 9z-4z=60 ⟹ 5z=60 ⟹ z=60/5 ⟹ z=12 Class 8 Maths Chapter 2 Exercise 2.6 Solution in Video for more answers vist to: https://www.tiwariacademy.com/ncert-solutions/class-8/maths/chapter-2/
z/z+15 = 4/9
⟹ zx9=4(z=15) ⟹ 9z=4z+60 ⟹ 9z-4z=60
⟹ 5z=60 ⟹ z=60/5 ⟹ z=12
Class 8 Maths Chapter 2 Exercise 2.6 Solution in Video
for more answers vist to:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-8/maths/chapter-2/
Solve the following equation: 9x/7-6x = 15
9x/7-6x = 15 ⟹ 9x=15(7-6x) ⟹ 9x=105-90x ⟹ 9x+90x=105 ⟹ 99x=105 ⟹ x=105/99 ⟹ x=35/33 Class 8 Maths Chapter 2 Exercise 2.6 Solution in Video for more answers vist to: https://www.tiwariacademy.com/ncert-solutions/class-8/maths/chapter-2/
9x/7-6x = 15
⟹ 9x=15(7-6x) ⟹ 9x=105-90x ⟹ 9x+90x=105
⟹ 99x=105 ⟹ x=105/99 ⟹ x=35/33
Class 8 Maths Chapter 2 Exercise 2.6 Solution in Video
See lessfor more answers vist to:
https://www.tiwariacademy.com/ncert-solutions/class-8/maths/chapter-2/
Solve the following equation: 8x-3/3x = 2
8x-3/3x = 2 ⟹ 8x-3=2x3x ⟹ 8x-3=6x ⟹ 8x-6x=3 ⟹ 2x=3 ⟹ x=3/2 Class 8 Maths Chapter 2 Exercise 2.6 Solution in Video for more answers vist to: https://www.tiwariacademy.com/ncert-solutions/class-8/maths/chapter-2/
8x-3/3x = 2
⟹ 8x-3=2x3x ⟹ 8x-3=6x ⟹ 8x-6x=3 ⟹ 2x=3 ⟹ x=3/2
Class 8 Maths Chapter 2 Exercise 2.6 Solution in Video
for more answers vist to:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-8/maths/chapter-2/
Simplify and solve the following linear equation: 0.25(4f-3) =0.05(10f-9)
0.25(4f-3) =0.05(10f-9) ⟹ 1.00f-0.75=0.50f-0.45 ⟹ 1.00f-0.50f =-0.45+0.75 ⟹ 0.50f =0.3 ⟹ f = 0.3/0.50 ⟹ f=0.6 To check: 0.25(4f-3)=0.05(10f-9) ⟹ 0.25(4X0.6-3)=0.05(10x0.6-9) ⟹ 0.25(2.4-3)=0.05(6.0-9) ⟹ 0.25x(-0.6) =0.05X(-3) ⟹ -0.150=-0.150 ⟹ L.H.S. = R. H. S. Therefore, it is correct. Class 8 MathsRead more
0.25(4f-3) =0.05(10f-9)
⟹ 1.00f-0.75=0.50f-0.45 ⟹ 1.00f-0.50f =-0.45+0.75
⟹ 0.50f =0.3 ⟹ f = 0.3/0.50 ⟹ f=0.6
To check:
0.25(4f-3)=0.05(10f-9) ⟹ 0.25(4X0.6-3)=0.05(10×0.6-9)
⟹ 0.25(2.4-3)=0.05(6.0-9) ⟹ 0.25x(-0.6) =0.05X(-3)
⟹ -0.150=-0.150 ⟹ L.H.S. = R. H. S.
Therefore, it is correct.
Class 8 Maths Chapter 2 Exercise 2.5 Solution in Video
for more answers vist to:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-8/maths/chapter-2/
Simplify and solve the following linear equation: 3(5z-7)-2(9z-11) =4(8z-13)-17
3(5z-7)-2(9z-11) =4(8z-13)-17 ⟹ 15z-21-18z+22=32z-52-17 ⟹ -3z+1=32z-69 ⟹ -3z-32z=-69-1 ⟹ -35z=-70 ⟹ z=-70/-35=2 To check: 3(5z-7)-2(9z-11)=4(8z-13)-17 ⟹ 3(5X2-7)-2(9X2-11)=4(8X2-13)-17 ⟹ 3(10-7)-2(18-11)=4(16-13)-17 ⟹ 3x3-2x7=4x3-17 ⟹ 9-14=12-17 ⟹-5=-5 ⟹ L.H.S. = R. H. S. Therefore, it is correct. CRead more
3(5z-7)-2(9z-11) =4(8z-13)-17 ⟹ 15z-21-18z+22=32z-52-17
⟹ -3z+1=32z-69 ⟹ -3z-32z=-69-1 ⟹ -35z=-70 ⟹ z=-70/-35=2
To check:
3(5z-7)-2(9z-11)=4(8z-13)-17 ⟹ 3(5X2-7)-2(9X2-11)=4(8X2-13)-17
⟹ 3(10-7)-2(18-11)=4(16-13)-17 ⟹ 3×3-2×7=4×3-17
⟹ 9-14=12-17 ⟹-5=-5 ⟹ L.H.S. = R. H. S.
Therefore, it is correct.
Class 8 Maths Chapter 2 Exercise 2.5 Solution in Video
for more answers vist to:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-8/maths/chapter-2/
Simplify and solve the following linear equation: 15(y-4) -2 (y-9) +5 (y+6) =0
15(y-4) -2 (y-9) +5 (y+6) =0 ⟹ 15y-60-2y+18+5y+30=0 ⟹ 18y-12=0 ⟹ 18y=12 ⟹ y-12/18 ⟹ y=2/3 Class 8 Maths Chapter 2 Exercise 2.5 Solution in Video for more answers vist to: https://www.tiwariacademy.com/ncert-solutions/class-8/maths/chapter-2/
15(y-4) -2 (y-9) +5 (y+6) =0 ⟹ 15y-60-2y+18+5y+30=0
⟹ 18y-12=0
⟹ 18y=12
⟹ y-12/18
⟹ y=2/3
Class 8 Maths Chapter 2 Exercise 2.5 Solution in Video
for more answers vist to:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-8/maths/chapter-2/