NCERT Solutions for Class 8 Mathematics Chapter 2

Important NCERT Questions

Linear Equations in one Variable Chapter 2 Exercise 2.5

NCERT Books for Session 2022-2023

CBSE Board

Questions No: 10

# Simplify and solve the following linear equation: 0.25(4f-3) =0.05(10f-9)

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0.25(4f-3) =0.05(10f-9)

⟹ 1.00f-0.75=0.50f-0.45 ⟹ 1.00f-0.50f =-0.45+0.75

⟹ 0.50f =0.3 ⟹ f = 0.3/0.50 ⟹ f=0.6

To check:

0.25(4f-3)=0.05(10f-9) ⟹ 0.25(4X0.6-3)=0.05(10×0.6-9)

⟹ 0.25(2.4-3)=0.05(6.0-9) ⟹ 0.25x(-0.6) =0.05X(-3)

⟹ -0.150=-0.150 ⟹ L.H.S. = R. H. S.

Therefore, it is correct.

Class 8 Maths Chapter 2 Exercise 2.5 Solution in Video

for more answers vist to:

https://www.tiwariacademy.com/ncert-solutions/class-8/maths/chapter-2/