1. Explanation: The inner curved surface area (CSA) of a cylindrical pipe is given by the formula: CSA = 2πrh, where: - r is the inner radius of the circular base, - h is the height (or length) of the cylinder. From the problem: - The length (h) of the pipe is 77 cm, - The inner diameter of the cross-sRead more

    Explanation:
    The inner curved surface area (CSA) of a cylindrical pipe is given by the formula:
    CSA = 2πrh,
    where:
    – r is the inner radius of the circular base,
    – h is the height (or length) of the cylinder.

    From the problem:
    – The length (h) of the pipe is 77 cm,
    – The inner diameter of the cross-section is 4 cm, so the inner radius (r) is:
    r = Diameter / 2 = 4 / 2 = 2 cm.

    Substitute the values of r = 2 cm and h = 77 cm into the formula:
    CSA = 2πrh.

    Using π ≈ 22/7 for calculation:
    CSA = 2 × (22/7) × 2 × 77.

    Simplify step by step:
    CSA = 2 × (22/7) × 154,
    CSA = 2 × 22 × 22,
    CSA = 968 cm².

    Thus, the inner curved surface area of the metal pipe is 968 cm², which corresponds to option b) 968 cm².

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  2. Explanation: The curved surface area (CSA) of a cylinder is given by the formula: CSA = 2πrh, where: - r is the radius of the circular base, - h is the height of the cylinder. From the problem, the CSA is 88 cm² and the height (h) is 14 cm. Substituting these values into the formula: 88 = 2πr(14). SRead more

    Explanation:
    The curved surface area (CSA) of a cylinder is given by the formula:
    CSA = 2πrh,
    where:
    – r is the radius of the circular base,
    – h is the height of the cylinder.

    From the problem, the CSA is 88 cm² and the height (h) is 14 cm. Substituting these values into the formula:
    88 = 2πr(14).

    Simplify:
    88 = 28πr.

    Divide both sides by 28π to isolate r:
    r = 88 / (28π).

    Using π ≈ 22/7 for calculation:
    r = 88 / (28 × 22/7),
    r = 88 / (4 × 22),
    r = 88 / 88,
    r = 1 cm.

    The diameter (d) of the circular base is twice the radius:
    d = 2r = 2 × 1 = 2 cm.

    Thus, the diameter of the circular base is 2 cm, which corresponds to option d) 2 cm.

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  3. Explanation: Each cube has an edge length of 12 cm. When two such cubes are joined, they form a new cuboid. The dimensions of the new cuboid are as follows: - Length (l) = 12 + 12 = 24 cm (since the two cubes are joined along their edges), - Breadth (b) = 12 cm (same as the edge of one cube), - HeigRead more

    Explanation:
    Each cube has an edge length of 12 cm. When two such cubes are joined, they form a new cuboid. The dimensions of the new cuboid are as follows:
    – Length (l) = 12 + 12 = 24 cm (since the two cubes are joined along their edges),
    – Breadth (b) = 12 cm (same as the edge of one cube),
    – Height (h) = 12 cm (same as the edge of one cube).

    The surface area of a cuboid is given by:
    Surface Area = 2(lb + bh + lh).

    Substitute the values of l = 24 cm, b = 12 cm, and h = 12 cm:
    Surface Area = 2[(24 × 12) + (12 × 12) + (24 × 12)].

    Calculate each term:
    24 × 12 = 288,
    12 × 12 = 144,
    24 × 12 = 288.

    Add these values:
    288 + 144 + 288 = 720.

    Multiply by 2:
    Surface Area = 2 × 720 = 1440 cm².

    Thus, the surface area of the new cuboid is 1440 cm², which corresponds to option b) 1440 cm².

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  4. The perimeter of the floor of the rectangular hall is given as 250m. This means: Perimeter = 2(l + b) = 250m, where l is the length and b is the breadth of the floor. From this, we can calculate: l + b = 250 / 2 = 125m. The lateral surface area (LSA) of the four walls is given by: LSA = 2h(l + b), wRead more

    The perimeter of the floor of the rectangular hall is given as 250m. This means:
    Perimeter = 2(l + b) = 250m,
    where l is the length and b is the breadth of the floor.

    From this, we can calculate:
    l + b = 250 / 2 = 125m.

    The lateral surface area (LSA) of the four walls is given by:
    LSA = 2h(l + b),
    where h is the height of the room.

    Substituting l + b = 125 into the formula, we get:
    LSA = 2h(125) = 250h.

    The total cost of whitewashing is Rs. 15000, and the cost per square meter is assumed to be Rs. 10 (as it is a standard rate in such problems unless specified otherwise). Thus:
    Cost = LSA × Rate,
    15000 = 250h × 10.

    Simplify to find h:
    15000 = 2500h,
    h = 15000 / 2500 = 6m.

    Thus, the height of the room is 6m, which corresponds to option c) 6m.

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  5. The surface area of a cuboid is calculated by summing up the areas of all six rectangular faces. A cuboid has three pairs of opposite faces, and the area of each pair is as follows: 1. Two faces with area lb (length × breadth), 2. Two faces with area bh (breadth × height), 3. Two faces with area lhRead more

    The surface area of a cuboid is calculated by summing up the areas of all six rectangular faces. A cuboid has three pairs of opposite faces, and the area of each pair is as follows:
    1. Two faces with area lb (length × breadth),
    2. Two faces with area bh (breadth × height),
    3. Two faces with area lh (length × height).

    Thus, the total surface area is given by:
    Surface Area = 2(lb) + 2(bh) + 2(lh)

    Factoring out the common factor of 2, we get:
    Surface Area = 2(lb + bh + lh)

    This matches option a) 2(lb + bh + lh), which is the correct formula for the surface area of a cuboid.

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