Arrange the data in ascending order: 22, 34, 39, 45, 54, 54, 56, 68, 78, 84. Count the number of observations. There are 10 numbers (even count). Find the median. For an even number of observations, the median is the average of the two middle numbers. The two middle numbers are the 5th and 6th numbeRead more
Arrange the data in ascending order:
22, 34, 39, 45, 54, 54, 56, 68, 78, 84.
Count the number of observations.
There are 10 numbers (even count).
Find the median.
For an even number of observations, the median is the average of the two middle numbers. The two middle numbers are the 5th and 6th numbers:
5th number = 54,
6th number = 54.
Median = (54 + 54) / 2 = 54.
This question related to Chapter 12 Mathematics Class 9th NCERT. From the Chapter 12 Statistics. Probability. Give answer according to your understanding.
We are given the following information: - The mean of 5 numbers is 30. - When one number is excluded, the mean of the remaining 4 numbers becomes 28. Calculate the total sum of the 5 numbers. The formula for the mean is: Mean = (Sum of all observations) / (Number of observations). For the 5 numbers:Read more
We are given the following information:
– The mean of 5 numbers is 30.
– When one number is excluded, the mean of the remaining 4 numbers becomes 28.
Calculate the total sum of the 5 numbers.
The formula for the mean is:
Mean = (Sum of all observations) / (Number of observations).
For the 5 numbers:
Mean = 30,
Number of observations = 5.
Substitute into the formula:
30 = (Sum of all 5 numbers) / 5.
Multiply through by 5:
Sum of all 5 numbers = 30 × 5 = 150.
Calculate the total sum of the remaining 4 numbers.
When one number is excluded, the mean of the remaining 4 numbers is 28. Using the same formula:
Mean = (Sum of remaining 4 numbers) / (Number of observations).
For the 4 numbers:
Mean = 28,
Number of observations = 4.
Substitute into the formula:
28 = (Sum of remaining 4 numbers) / 4.
Multiply through by 4:
Sum of remaining 4 numbers = 28 × 4 = 112.
Find the excluded number.
The excluded number is the difference between the total sum of the 5 numbers and the sum of the remaining 4 numbers:
Excluded number = (Sum of all 5 numbers) – (Sum of remaining 4 numbers).
Substitute the values:
Excluded number = 150 – 112 = 38.
This question related to Chapter 12 Mathematics Class 9th NCERT. From the Chapter 12 Statistics. Probability. Give answer according to your understanding.
Ans. Correct Option a) 35 We are given the following information: - The width of each class in the frequency distribution is 5. - The lower class limit of the lowest class is 10. - There are 5 continuous classes. Determine the class intervals. Each class has a width of 5, so the class intervals canRead more
Ans. Correct Option a) 35
We are given the following information:
– The width of each class in the frequency distribution is 5.
– The lower class limit of the lowest class is 10.
– There are 5 continuous classes.
Determine the class intervals.
Each class has a width of 5, so the class intervals can be written as:
1. First class: 10 – 15 (lower limit = 10, upper limit = 10 + 5 = 15),
2. Second class: 15 – 20,
3. Third class: 20 – 25,
4. Fourth class: 25 – 30,
5. Fifth class: 30 – 35.
Identify the upper class limit of the highest class.
From the above intervals, the highest class is the fifth class, which has an upper class limit of 35.
The first 10 natural numbers are: 1, 2, 3, 4, 5, 6, 7, 8, 9, 10. To calculate the mean, use the formula: Mean = (Sum of all observations) / (Number of observations). Calculate the sum of the first 10 natural numbers. This is an arithmetic progression (AP) with: - First term (a) = 1, - Last term (l)Read more
The first 10 natural numbers are:
1, 2, 3, 4, 5, 6, 7, 8, 9, 10.
To calculate the mean, use the formula:
Mean = (Sum of all observations) / (Number of observations).
Calculate the sum of the first 10 natural numbers.
This is an arithmetic progression (AP) with:
– First term (a) = 1,
– Last term (l) = 10,
– Number of terms (n) = 10.
The sum of an AP is given by:
Sum = n/2 × (a + l).
Substitute the values:
Sum = 10/2 × (1 + 10),
Sum = 5 × 11,
Sum = 55.
Calculate the mean.
Mean = Sum / Number of observations,
Mean = 55 / 10,
Mean = 5.5.
To calculate the average of the numbers, use the formula: Average = (Sum of all observations) / (Number of observations). Calculate the sum of the numbers. The numbers are: 10, 8, 9, 7, 8. Sum = 10 + 8 + 9 + 7 + 8 = 42. Count the number of observations. There are 5 numbers in the list. Calculate theRead more
To calculate the average of the numbers, use the formula:
Average = (Sum of all observations) / (Number of observations).
Calculate the sum of the numbers.
The numbers are: 10, 8, 9, 7, 8.
Sum = 10 + 8 + 9 + 7 + 8 = 42.
Count the number of observations.
There are 5 numbers in the list.
Calculate the average.
Average = Sum / Number of observations,
Average = 42 / 5,
Average = 8.4.
The median of the data 78, 56, 22, 34, 45, 54, 39, 68, 54, 84 is
Arrange the data in ascending order: 22, 34, 39, 45, 54, 54, 56, 68, 78, 84. Count the number of observations. There are 10 numbers (even count). Find the median. For an even number of observations, the median is the average of the two middle numbers. The two middle numbers are the 5th and 6th numbeRead more
Arrange the data in ascending order:
22, 34, 39, 45, 54, 54, 56, 68, 78, 84.
Count the number of observations.
There are 10 numbers (even count).
Find the median.
For an even number of observations, the median is the average of the two middle numbers. The two middle numbers are the 5th and 6th numbers:
5th number = 54,
6th number = 54.
Median = (54 + 54) / 2 = 54.
This question related to Chapter 12 Mathematics Class 9th NCERT. From the Chapter 12 Statistics. Probability. Give answer according to your understanding.
For more please visit here:
See lesshttps://www.tiwariacademy.in/ncert-solutions/class-9/maths/
The mean of 5 numbers is 30. If one number is excluded, their mean becomes 28. The excluded number is
We are given the following information: - The mean of 5 numbers is 30. - When one number is excluded, the mean of the remaining 4 numbers becomes 28. Calculate the total sum of the 5 numbers. The formula for the mean is: Mean = (Sum of all observations) / (Number of observations). For the 5 numbers:Read more
We are given the following information:
– The mean of 5 numbers is 30.
– When one number is excluded, the mean of the remaining 4 numbers becomes 28.
Calculate the total sum of the 5 numbers.
The formula for the mean is:
Mean = (Sum of all observations) / (Number of observations).
For the 5 numbers:
Mean = 30,
Number of observations = 5.
Substitute into the formula:
30 = (Sum of all 5 numbers) / 5.
Multiply through by 5:
Sum of all 5 numbers = 30 × 5 = 150.
Calculate the total sum of the remaining 4 numbers.
When one number is excluded, the mean of the remaining 4 numbers is 28. Using the same formula:
Mean = (Sum of remaining 4 numbers) / (Number of observations).
For the 4 numbers:
Mean = 28,
Number of observations = 4.
Substitute into the formula:
28 = (Sum of remaining 4 numbers) / 4.
Multiply through by 4:
Sum of remaining 4 numbers = 28 × 4 = 112.
Find the excluded number.
The excluded number is the difference between the total sum of the 5 numbers and the sum of the remaining 4 numbers:
Excluded number = (Sum of all 5 numbers) – (Sum of remaining 4 numbers).
Substitute the values:
Excluded number = 150 – 112 = 38.
This question related to Chapter 12 Mathematics Class 9th NCERT. From the Chapter 12 Statistics. Probability. Give answer according to your understanding.
For more please visit here:
See lesshttps://www.tiwariacademy.in/ncert-solutions/class-9/maths/
The width of each of five continuous classes in a frequency distribution is 5 and the lower class limit of the lowest class limit of the lowest class is 10. The upper class limit of the highest class is:
Ans. Correct Option a) 35 We are given the following information: - The width of each class in the frequency distribution is 5. - The lower class limit of the lowest class is 10. - There are 5 continuous classes. Determine the class intervals. Each class has a width of 5, so the class intervals canRead more
Ans. Correct Option a) 35
We are given the following information:
– The width of each class in the frequency distribution is 5.
– The lower class limit of the lowest class is 10.
– There are 5 continuous classes.
Determine the class intervals.
Each class has a width of 5, so the class intervals can be written as:
1. First class: 10 – 15 (lower limit = 10, upper limit = 10 + 5 = 15),
2. Second class: 15 – 20,
3. Third class: 20 – 25,
4. Fourth class: 25 – 30,
5. Fifth class: 30 – 35.
Identify the upper class limit of the highest class.
From the above intervals, the highest class is the fifth class, which has an upper class limit of 35.
For more please visit here:
See lesshttps://www.tiwariacademy.in/ncert-solutions/class-9/maths/
Mean of first 10 natural numbers is
The first 10 natural numbers are: 1, 2, 3, 4, 5, 6, 7, 8, 9, 10. To calculate the mean, use the formula: Mean = (Sum of all observations) / (Number of observations). Calculate the sum of the first 10 natural numbers. This is an arithmetic progression (AP) with: - First term (a) = 1, - Last term (l)Read more
The first 10 natural numbers are:
1, 2, 3, 4, 5, 6, 7, 8, 9, 10.
To calculate the mean, use the formula:
Mean = (Sum of all observations) / (Number of observations).
Calculate the sum of the first 10 natural numbers.
This is an arithmetic progression (AP) with:
– First term (a) = 1,
– Last term (l) = 10,
– Number of terms (n) = 10.
The sum of an AP is given by:
Sum = n/2 × (a + l).
Substitute the values:
Sum = 10/2 × (1 + 10),
Sum = 5 × 11,
Sum = 55.
Calculate the mean.
Mean = Sum / Number of observations,
Mean = 55 / 10,
Mean = 5.5.
For more please visit here:
See lesshttps://www.tiwariacademy.in/ncert-solutions/class-9/maths/
Average of numbers: 10, 8, 9, 7, 8 is
To calculate the average of the numbers, use the formula: Average = (Sum of all observations) / (Number of observations). Calculate the sum of the numbers. The numbers are: 10, 8, 9, 7, 8. Sum = 10 + 8 + 9 + 7 + 8 = 42. Count the number of observations. There are 5 numbers in the list. Calculate theRead more
To calculate the average of the numbers, use the formula:
Average = (Sum of all observations) / (Number of observations).
Calculate the sum of the numbers.
The numbers are: 10, 8, 9, 7, 8.
Sum = 10 + 8 + 9 + 7 + 8 = 42.
Count the number of observations.
There are 5 numbers in the list.
Calculate the average.
See lessAverage = Sum / Number of observations,
Average = 42 / 5,
Average = 8.4.