1. Choice (b) is correct. If A = ∅, ∅ is only subset of A = ∅. P(∅) = {∅} = P(A) has only one element. This question related to Chapter 1 maths Class 11th NCERT. From the Chapter 1. Sets. Give answer according to your understanding. For more please visit here: https://www.tiwariacademy.com/ncert-solutiRead more

    Choice (b) is correct. If A = ∅, ∅ is only subset of A = ∅. P(∅) = {∅} = P(A) has only one element.
    This question related to Chapter 1 maths Class 11th NCERT. From the Chapter 1. Sets. Give answer according to your understanding.

    For more please visit here:
    https://www.tiwariacademy.com/ncert-solutions/class-11/maths/#chapter-1

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    • 21
  2. Choice (d) is correct. X ∩ (X ∪ Y)' = X ∩ ( X' ∩ Y') = (X ∩ X') ∩ Y' = ∅ ∩ Y' = ∅. This question related to Chapter 1 maths Class 11th NCERT. From the Chapter 1. Sets. Give answer according to your understanding. For more please visit here: https://www.tiwariacademy.com/ncert-solutions/class-11/mathRead more

    Choice (d) is correct. X ∩ (X ∪ Y)’ = X ∩ ( X’ ∩ Y’) = (X ∩ X’) ∩ Y’ = ∅ ∩ Y’ = ∅.
    This question related to Chapter 1 maths Class 11th NCERT. From the Chapter 1. Sets. Give answer according to your understanding.

    For more please visit here:
    https://www.tiwariacademy.com/ncert-solutions/class-11/maths/#chapter-1

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    • 16
  3. Choice (c) is correct. As A ∩ B⊊ A, so A ∩ (A ∩ B) = A ∩ B. This question related to Chapter 1 maths Class 11th NCERT. From the Chapter 1. Sets. Give answer according to your understanding. For more please visit here: https://www.tiwariacademy.com/ncert-solutions/class-11/maths/#chapter-1

    Choice (c) is correct. As A ∩ B⊊ A, so A ∩ (A ∩ B) = A ∩ B.
    This question related to Chapter 1 maths Class 11th NCERT. From the Chapter 1. Sets. Give answer according to your understanding.

    For more please visit here:
    https://www.tiwariacademy.com/ncert-solutions/class-11/maths/#chapter-1

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  4. Choice (c) is correct.  Let A and B the sets of students liking coffee and juice respectively.  n(A) = 500, n(B) = 300 and n(A ∩ B) = 120 Number of students liking coffee or juice = n (A ∪ B) = n(A) +n(B) - n(A ∩ B) = 500 + 300 - 120 = 680 This question related to Chapter 1 maths Class 11th NCERT. FRead more

    Choice (c) is correct. 
    Let A and B the sets of students liking coffee and juice respectively. 
    n(A) = 500, n(B) = 300 and n(A ∩ B) = 120
    Number of students liking coffee or juice = n (A ∪ B) = n(A) +n(B) – n(A ∩ B) = 500 + 300 – 120 = 680
    This question related to Chapter 1 maths Class 11th NCERT. From the Chapter 1. Sets. Give answer according to your understanding.

    For more please visit here:
    https://www.tiwariacademy.com/ncert-solutions/class-11/maths/#chapter-1

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  5. Choice (a). is correct. As A, B and C are disjoints sets. n(A ∪ B ∪ C) = n (A) +n(B) +n(C) = 10 + 6 + 5 = 21 This question related to Chapter 1 maths Class 11th NCERT. From the Chapter 1. Sets. Give answer according to your understanding. For more please visit here: https://www.tiwariacademy.com/nceRead more

    Choice (a). is correct. As A, B and C are disjoints sets. n(A ∪ B ∪ C) = n (A) +n(B) +n(C) = 10 + 6 + 5 = 21
    This question related to Chapter 1 maths Class 11th NCERT. From the Chapter 1. Sets. Give answer according to your understanding.

    For more please visit here:
    https://www.tiwariacademy.com/ncert-solutions/class-11/maths/#chapter-1

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    • 19