The degree of a polynomial is the highest power of the variable in the given expression. Given Expression: 3 Since 3 is a constant, it can be written as: 3 = 3x⁰ where x⁰ = 1. Step 1: Identify the Degree A constant term always has a degree of 0, because it does not contain a variable. Final Answer:Read more
The degree of a polynomial is the highest power of the variable in the given expression.
Given Expression: 3
Since 3 is a constant, it can be written as:
3 = 3x⁰
where x⁰ = 1.
Step 1: Identify the Degree
A constant term always has a degree of 0, because it does not contain a variable.
Final Answer: The degree of 3 is 0, so the correct option is : (a) zero.
This question related to Chapter 2 Mathematics Class 9th NCERT. From the Chapter 2 Polynomials. Give answer according to your understanding.
The degree of a polynomial is the highest power of the variable in the expression. Given polynomial: 5t - 7 Step 1: Identify the Degree The term 5t has t¹ (power of t is 1) The term -7 is a constant, meaning its power is 0. The highest exponent in the expression is 1. Final Answer: The degree of 5tRead more
The degree of a polynomial is the highest power of the variable in the expression.
Given polynomial: 5t – 7
Step 1: Identify the Degree
The term 5t has t¹ (power of t is 1)
The term -7 is a constant, meaning its power is 0.
The highest exponent in the expression is 1.
Final Answer: The degree of 5t – 7 is 1, so the correct option is (b) 1.
This question related to Chapter 2 Mathematics Class 9th NCERT. From the Chapter 2 Polynomials. Give answer according to your understanding.
We are given the repeating decimal 0.6666... and need to express it in the form p/q. Step 1: Let x = 0.6666... Step 2: Multiply by 10 to shift the decimal point 10x = 6.666... Step 3: Subtract the two equations 10x - x = 6.6666... - 0.6666.. 9x = 6 Step 4: Solve for x x = 6/9 Step 5: Simplify theRead more
We are given the repeating decimal 0.6666… and need to express it in the form p/q.
Step 1: Let x = 0.6666…
Step 2: Multiply by 10 to shift the decimal point
10x = 6.666…
Step 3: Subtract the two equations
10x – x = 6.6666… – 0.6666..
9x = 6
Step 4: Solve for x
x = 6/9
Step 5: Simplify the fraction 6/9 = 2/3
Conclusion: The correct answer is 2/3 (option b).
This question related to Chapter 1 Mathematics Class 9th NCERT. From the Chapter 1 Number System. Give answer according to your understanding.
A rational number is any number that can be expressed as p/q, where p and q are integers, and q ≠ 0. Now, let's check each option: (a). √3 The square root of 3 is irrational because it cannot be written as a fraction of two integers. (b). √2 The square root of 2 is also irrational because it has a nRead more
A rational number is any number that can be expressed as p/q, where p and q are integers, and q ≠ 0.
Now, let’s check each option:
(a). √3 The square root of 3 is irrational because it cannot be written as a fraction of two integers.
(b). √2 The square root of 2 is also irrational because it has a non-repeating , non-terminating decimal expansion.
(c). 0 Zero can be written as 0/1, which is in the form p/q where p = 0 and q = 1. Since it satisfies the definition of a rational number, 0 is rational.
(d). √5 The square root of 5 is irrational for the same reasons as √2 and √3.
Conclusion: The only rational number in the given option is 0 (option c).
This question related to Chapter 1 Mathematics Class 9th NCERT. From the Chapter 1 Number System. Give answer according to your understanding.
We are given the expression: (3 + √3) (3 - √3) Step 1: Apply the identity This follows the difference of squares identity: (a + b) (a - b) = a² - b² where a = 3 and b = √3. Step 2: Substitute and solve (3 + √3)(3 - √3) = 3² - (√3)² = 9 - 3 = 6 Conclusion: The correct answer is 6 (option b). This quRead more
We are given the expression: (3 + √3) (3 – √3)
Step 1: Apply the identity
This follows the difference of squares identity:
(a + b) (a – b) = a² – b²
where a = 3 and b = √3.
Step 2: Substitute and solve
(3 + √3)(3 – √3) = 3² – (√3)²
= 9 – 3
= 6
Conclusion: The correct answer is 6 (option b).
This question related to Chapter 1 Mathematics Class 9th NCERT. From the Chapter 1 Number System. Give answer according to your understanding.
The degree of 3 is:
The degree of a polynomial is the highest power of the variable in the given expression. Given Expression: 3 Since 3 is a constant, it can be written as: 3 = 3x⁰ where x⁰ = 1. Step 1: Identify the Degree A constant term always has a degree of 0, because it does not contain a variable. Final Answer:Read more
The degree of a polynomial is the highest power of the variable in the given expression.
Given Expression: 3
Since 3 is a constant, it can be written as:
3 = 3x⁰
where x⁰ = 1.
Step 1: Identify the Degree
A constant term always has a degree of 0, because it does not contain a variable.
Final Answer: The degree of 3 is 0, so the correct option is : (a) zero.
This question related to Chapter 2 Mathematics Class 9th NCERT. From the Chapter 2 Polynomials. Give answer according to your understanding.
For more please visit here:
See lesshttps://www.tiwariacademy.in/ncert-solutions/class-9/maths/
The degree of 5t – 7 is:
The degree of a polynomial is the highest power of the variable in the expression. Given polynomial: 5t - 7 Step 1: Identify the Degree The term 5t has t¹ (power of t is 1) The term -7 is a constant, meaning its power is 0. The highest exponent in the expression is 1. Final Answer: The degree of 5tRead more
The degree of a polynomial is the highest power of the variable in the expression.
Given polynomial: 5t – 7
Step 1: Identify the Degree
The term 5t has t¹ (power of t is 1)
The term -7 is a constant, meaning its power is 0.
The highest exponent in the expression is 1.
Final Answer: The degree of 5t – 7 is 1, so the correct option is (b) 1.
This question related to Chapter 2 Mathematics Class 9th NCERT. From the Chapter 2 Polynomials. Give answer according to your understanding.
For more please visit here:
See lesshttps://www.tiwariacademy.in/ncert-solutions/class-9/maths/
0.6666 in p/q form is:
We are given the repeating decimal 0.6666... and need to express it in the form p/q. Step 1: Let x = 0.6666... Step 2: Multiply by 10 to shift the decimal point 10x = 6.666... Step 3: Subtract the two equations 10x - x = 6.6666... - 0.6666.. 9x = 6 Step 4: Solve for x x = 6/9 Step 5: Simplify theRead more
We are given the repeating decimal 0.6666… and need to express it in the form p/q.
Step 1: Let x = 0.6666…
Step 2: Multiply by 10 to shift the decimal point
10x = 6.666…
Step 3: Subtract the two equations
10x – x = 6.6666… – 0.6666..
9x = 6
Step 4: Solve for x
x = 6/9
Step 5: Simplify the fraction 6/9 = 2/3
Conclusion: The correct answer is 2/3 (option b).
This question related to Chapter 1 Mathematics Class 9th NCERT. From the Chapter 1 Number System. Give answer according to your understanding.
For more please visit here:
See lesshttps://www.tiwariacademy.in/ncert-solutions/class-9/maths/
Which one of the following is a rational number:
A rational number is any number that can be expressed as p/q, where p and q are integers, and q ≠ 0. Now, let's check each option: (a). √3 The square root of 3 is irrational because it cannot be written as a fraction of two integers. (b). √2 The square root of 2 is also irrational because it has a nRead more
A rational number is any number that can be expressed as p/q, where p and q are integers, and q ≠ 0.
Now, let’s check each option:
(a). √3 The square root of 3 is irrational because it cannot be written as a fraction of two integers.
(b). √2 The square root of 2 is also irrational because it has a non-repeating , non-terminating decimal expansion.
(c). 0 Zero can be written as 0/1, which is in the form p/q where p = 0 and q = 1. Since it satisfies the definition of a rational number, 0 is rational.
(d). √5 The square root of 5 is irrational for the same reasons as √2 and √3.
Conclusion: The only rational number in the given option is 0 (option c).
This question related to Chapter 1 Mathematics Class 9th NCERT. From the Chapter 1 Number System. Give answer according to your understanding.
For more please visit here:
See lesshttps://www.tiwariacademy.in/ncert-solutions/class-9/maths/
The value of (3 + √3) (3 – √3) is:
We are given the expression: (3 + √3) (3 - √3) Step 1: Apply the identity This follows the difference of squares identity: (a + b) (a - b) = a² - b² where a = 3 and b = √3. Step 2: Substitute and solve (3 + √3)(3 - √3) = 3² - (√3)² = 9 - 3 = 6 Conclusion: The correct answer is 6 (option b). This quRead more
We are given the expression: (3 + √3) (3 – √3)
Step 1: Apply the identity
This follows the difference of squares identity:
(a + b) (a – b) = a² – b²
where a = 3 and b = √3.
Step 2: Substitute and solve
(3 + √3)(3 – √3) = 3² – (√3)²
= 9 – 3
= 6
Conclusion: The correct answer is 6 (option b).
This question related to Chapter 1 Mathematics Class 9th NCERT. From the Chapter 1 Number System. Give answer according to your understanding.
For more please visit here:
See lesshttps://www.tiwariacademy.in/ncert-solutions/class-9/maths/