Understanding the Sign of the X-Coordinate in the Third Quadrant A point (x, y) lies in a specific quadrant based on the signs of its coordinates: Quadrant I → (x > 0, y > 0) Quadrant II → (x 0) Quadrant III → (x < 0, y 0, y < 0) For a Point in the Third Quadrant (III): The x-coordinateRead more
Understanding the Sign of the X-Coordinate in the Third Quadrant
A point (x, y) lies in a specific quadrant based on the signs of its coordinates:
Quadrant I → (x > 0, y > 0)
Quadrant II → (x 0)
Quadrant III → (x < 0, y 0, y < 0)
For a Point in the Third Quadrant (III):
The x-coordinate is negative (x < 0).
The y-coordinate is also negative (y < 0).
Final Answer: (b) –
This question related to Chapter 3 Mathematics Class 9th NCERT. From the Chapter 3 Coordinate Geometry. Give answer according to your understanding.
Determining the Quadrant of Given Points A point (x, y) lies in a specific quadrant based on the signs of its coordinates: Quadrant I → (x > 0, y > 0) Quadrant II → (x 0) Quadrant III → (x < 0, y 0, y < 0) Analyzing Each Point 1. Point (1 , -2) x = 1 (positive), y = -2 (negative). LiesRead more
Determining the Quadrant of Given Points
A point (x, y) lies in a specific quadrant based on the signs of its coordinates:
Quadrant I → (x > 0, y > 0)
Quadrant II → (x 0)
Quadrant III → (x < 0, y 0, y < 0)
Analyzing Each Point
1. Point (1 , -2)
x = 1 (positive), y = -2 (negative). Lies in Quadrant IV
2. Point (2, -3)
x = 2 (positive), y = -3 (negative). Lies in Quadrant IV
3. Point (4, -6)
x = 4 (positive), y = -6(negative). Lies in Quadrant IV
4. Point (2, -7)
x = 2 (positive), y = -7 (negative). Lies in Quadrant IV
Conclusion: All four points lie in Quadrant IV.
Final Answer: (c) IV quadrant.
This question related to Chapter 3 Mathematics Class 9th NCERT. From the Chapter 3 Coordinate Geometry. Give answer according to your understanding.
The number of zeroes ( or roots) of a polynomial is determined by its degree. The degree of a polynomial is the highest exponent of the variable. Given Polynomial: x³ + x - 3 - 3x² Step 1: Arrange in Standard Form Rearrange the terms in descending order of powers of x: x³ - 3x² + x - 3 Step 2: IdentRead more
The number of zeroes ( or roots) of a polynomial is determined by its degree. The degree of a polynomial is the highest exponent of the variable.
Given Polynomial: x³ + x – 3 – 3x²
Step 1: Arrange in Standard Form
Rearrange the terms in descending order of powers of x:
x³ – 3x² + x – 3
Step 2: Identify the Degree
The highest power of x is 3.
A polynomial of degree n can have at most n zeroes.
Conclusion: Since the given polynomial is of degree 3, it has three zeroes ( real or complex). Thus the correct answer is (d) 3.
This question related to Chapter 2 Mathematics Class 9th NCERT. From the Chapter 2 Polynomials. Give answer according to your understanding.
Correct option (a) 2x A polynomial consists of terms where the variable has only non-negative integer exponents. Analyzing Each Option: (a). 2x - The exponent of x is 1, which is a non-negative integer. This is a valid term of a polynomial. (b). 3/x - This can be rewritten as 3x ⁻¹. Since the exponeRead more
Correct option (a) 2x
A polynomial consists of terms where the variable has only non-negative integer exponents.
Analyzing Each Option:
(a). 2x – The exponent of x is 1, which is a non-negative integer. This is a valid term of a polynomial.
(b). 3/x – This can be rewritten as 3x ⁻¹. Since the exponent is negative, this is not a polynomial term.
(c). x√x – We rewrite √x as x¹/², so:
x√x = x.x¹/² = x ³/² Since the exponent 3/2 is not an integer, this is not a polynomial terms.
(d). √x – since √x = x ¹/², and the exponent 1/2 is not a integer, this is not a polynomial term.
Final Answer: The correct answer is (a) 2x.
This question related to Chapter 2 Mathematics Class 9th NCERT. From the Chapter 2 Polynomials. Give answer according to your understanding.
We need to find the value of: 104 x 96 Step 1: Use the Difference of Squares Formula We rewrite the numbers as: 104 x 96 = (100 + 4) (100 - 4) Using the identify: (a + b) (a - b) = a² - b² where a = 100 and b = 4: 104 × 96 = 100² - 4² Step 2: Compute the Values 100² = 10000 4² = 16 10000 - 16 = 9984Read more
We need to find the value of: 104 x 96
Step 1: Use the Difference of Squares Formula
We rewrite the numbers as: 104 x 96 = (100 + 4) (100 – 4)
Using the identify: (a + b) (a – b) = a² – b²
where a = 100 and b = 4:
104 × 96 = 100² – 4²
Step 2: Compute the Values
100² = 10000
4² = 16
10000 – 16 = 9984
Final Answer: The correct option is: (a) 9984.
This question related to Chapter 2 Mathematics Class 9th NCERT. From the Chapter 2 Polynomials. Give answer according to your understanding.
The sign of x-coordinate of a point lying in third quadrant is
Understanding the Sign of the X-Coordinate in the Third Quadrant A point (x, y) lies in a specific quadrant based on the signs of its coordinates: Quadrant I → (x > 0, y > 0) Quadrant II → (x 0) Quadrant III → (x < 0, y 0, y < 0) For a Point in the Third Quadrant (III): The x-coordinateRead more
Understanding the Sign of the X-Coordinate in the Third Quadrant
A point (x, y) lies in a specific quadrant based on the signs of its coordinates:
Quadrant I → (x > 0, y > 0)
Quadrant II → (x 0)
Quadrant III → (x < 0, y 0, y < 0)
For a Point in the Third Quadrant (III):
The x-coordinate is negative (x < 0).
The y-coordinate is also negative (y < 0).
Final Answer: (b) –
This question related to Chapter 3 Mathematics Class 9th NCERT. From the Chapter 3 Coordinate Geometry. Give answer according to your understanding.
For more please visit here:
See lesshttps://www.tiwariacademy.in/ncert-solutions/class-9/maths/
The point (1, –2), (2, –3), (4, –6), (2,–7) lies in:
Determining the Quadrant of Given Points A point (x, y) lies in a specific quadrant based on the signs of its coordinates: Quadrant I → (x > 0, y > 0) Quadrant II → (x 0) Quadrant III → (x < 0, y 0, y < 0) Analyzing Each Point 1. Point (1 , -2) x = 1 (positive), y = -2 (negative). LiesRead more
Determining the Quadrant of Given Points
A point (x, y) lies in a specific quadrant based on the signs of its coordinates:
Quadrant I → (x > 0, y > 0)
Quadrant II → (x 0)
Quadrant III → (x < 0, y 0, y < 0)
Analyzing Each Point
1. Point (1 , -2)
x = 1 (positive), y = -2 (negative). Lies in Quadrant IV
2. Point (2, -3)
x = 2 (positive), y = -3 (negative). Lies in Quadrant IV
3. Point (4, -6)
x = 4 (positive), y = -6(negative). Lies in Quadrant IV
4. Point (2, -7)
x = 2 (positive), y = -7 (negative). Lies in Quadrant IV
Conclusion: All four points lie in Quadrant IV.
Final Answer: (c) IV quadrant.
This question related to Chapter 3 Mathematics Class 9th NCERT. From the Chapter 3 Coordinate Geometry. Give answer according to your understanding.
For more please visit here:
See lesshttps://www.tiwariacademy.in/ncert-solutions/class-9/maths/
The number of zeroes of the polynomial x³ + x – 3 – 3x² is
The number of zeroes ( or roots) of a polynomial is determined by its degree. The degree of a polynomial is the highest exponent of the variable. Given Polynomial: x³ + x - 3 - 3x² Step 1: Arrange in Standard Form Rearrange the terms in descending order of powers of x: x³ - 3x² + x - 3 Step 2: IdentRead more
The number of zeroes ( or roots) of a polynomial is determined by its degree. The degree of a polynomial is the highest exponent of the variable.
Given Polynomial: x³ + x – 3 – 3x²
Step 1: Arrange in Standard Form
Rearrange the terms in descending order of powers of x:
x³ – 3x² + x – 3
Step 2: Identify the Degree
The highest power of x is 3.
A polynomial of degree n can have at most n zeroes.
Conclusion: Since the given polynomial is of degree 3, it has three zeroes ( real or complex). Thus the correct answer is (d) 3.
This question related to Chapter 2 Mathematics Class 9th NCERT. From the Chapter 2 Polynomials. Give answer according to your understanding.
For more please visit here:
See lesshttps://www.tiwariacademy.in/ncert-solutions/class-9/maths/
Which of the following is a term of a polynomial?
Correct option (a) 2x A polynomial consists of terms where the variable has only non-negative integer exponents. Analyzing Each Option: (a). 2x - The exponent of x is 1, which is a non-negative integer. This is a valid term of a polynomial. (b). 3/x - This can be rewritten as 3x ⁻¹. Since the exponeRead more
Correct option (a) 2x
A polynomial consists of terms where the variable has only non-negative integer exponents.
Analyzing Each Option:
(a). 2x – The exponent of x is 1, which is a non-negative integer. This is a valid term of a polynomial.
(b). 3/x – This can be rewritten as 3x ⁻¹. Since the exponent is negative, this is not a polynomial term.
(c). x√x – We rewrite √x as x¹/², so:
x√x = x.x¹/² = x ³/² Since the exponent 3/2 is not an integer, this is not a polynomial terms.
(d). √x – since √x = x ¹/², and the exponent 1/2 is not a integer, this is not a polynomial term.
Final Answer: The correct answer is (a) 2x.
This question related to Chapter 2 Mathematics Class 9th NCERT. From the Chapter 2 Polynomials. Give answer according to your understanding.
For more please visit here:
See lesshttps://www.tiwariacademy.in/ncert-solutions/class-9/maths/
The value of 104 x 96 is:
We need to find the value of: 104 x 96 Step 1: Use the Difference of Squares Formula We rewrite the numbers as: 104 x 96 = (100 + 4) (100 - 4) Using the identify: (a + b) (a - b) = a² - b² where a = 100 and b = 4: 104 × 96 = 100² - 4² Step 2: Compute the Values 100² = 10000 4² = 16 10000 - 16 = 9984Read more
We need to find the value of: 104 x 96
Step 1: Use the Difference of Squares Formula
We rewrite the numbers as: 104 x 96 = (100 + 4) (100 – 4)
Using the identify: (a + b) (a – b) = a² – b²
where a = 100 and b = 4:
104 × 96 = 100² – 4²
Step 2: Compute the Values
100² = 10000
4² = 16
10000 – 16 = 9984
Final Answer: The correct option is: (a) 9984.
This question related to Chapter 2 Mathematics Class 9th NCERT. From the Chapter 2 Polynomials. Give answer according to your understanding.
For more please visit here:
See lesshttps://www.tiwariacademy.in/ncert-solutions/class-9/maths/