1. We are given the expression: 1/√2 To rationalize the denominator, we multiply both the numerator and denominator by √2 to eliminate the square root in the denominator  Step 1: Multiply by √2/√2 1/√2 × √2/√2 = √2/2 Conclusion: The correct answer is √2/2 (option d).  This question related to Chapter 1Read more

    We are given the expression: 1/√2
    To rationalize the denominator, we multiply both the numerator and denominator by √2 to eliminate the square root in the denominator 
    Step 1: Multiply by √2/√2
    1/√2 × √2/√2 = √2/2
    Conclusion: The correct answer is √2/2 (option d). 
    This question related to Chapter 1 Mathematics Class 9th NCERT. From the Chapter 1 Number System. Give answer according to your understanding.

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  2. A rational number p/q has a terminating decimal expansion if and only if the prime factorization of its denominator q (after simplify the fraction) contains only the prime factorization of its denominator q (after simplifying the fraction) contains only the prime factor 2 and/or 5. (a).  2 or 5  IfRead more

    A rational number p/q has a terminating decimal expansion if and only if the prime factorization of its denominator q (after simplify the fraction) contains only the prime factorization of its denominator q (after simplifying the fraction) contains only the prime factor 2 and/or 5.
    (a).  2 or 5 
    If the denominator has only 2, and 5, or both(e.g., 10, 20, 25, etc.), the decimal expansion terminates.
    (b). 3 or 5
    The presence of 3 in the denominator(e.g., 1/3 = 0.3333…) causes a non-terminating repeating decimal.
    (c). 9 or 11
    9 = 3³ and 11 are not factors that produce a terminating decimal. 
    (d) 3 or 7 
    Both 3 and 7 cause non-terminating repeating decimals.
    This question related to Chapter 1 Mathematics Class 9th NCERT. From the Chapter 1 Number System. Give answer according to your understanding.

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  3. Let's analyze each statement carefully: Option (a): Every whole number is a natural number Natural numbers (N): {1,2, 3, 4,...} Whole numbers (W): {0,1,2,3,4,...} Since whole number include 0, but natural number do not, this statement is false. Option (b): Every integer is a rational number IntegersRead more

    Let’s analyze each statement carefully:
    Option (a): Every whole number is a natural number
    Natural numbers (N): {1,2, 3, 4,…}
    Whole numbers (W): {0,1,2,3,4,…}
    Since whole number include 0, but natural number do not, this statement is false.
    Option (b): Every integer is a rational number
    Integers (Z): {…, -3, -2, -1, 0, 1,2,3,…)
    Rotational number (Q): Numbers that can be expressed as p/q, where p and q are integers, and q ≠ 0.
    Every integer x can be written as x/1, which is in the form of a rotational number.
    Thus this statement is true.
    Option (c): Every rational number is an integer.
    Example 1/2 is a rational number but not an integer.
    So, this statement is false.
    Option (d): Every integer is a whole number 
    Whole number do not include negative numbers, but integers do.
    Example: -1 is an integer but not a whole number.
    Thus, this statement is false.
    Final Answer: The correct answer is (b) Every integer is a rotational number. This question related to Chapter 1 Mathematics Class 9th NCERT. From the Chapter 1 Number System. Give answer according to your understanding.

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  4. We  are given that m and n are two natural numbers, and mⁿ = 32 We need to find the value of nᵐⁿ. Step 1: Find Possible Value of m and n Since 32 and 2⁵, we look for natural numbers m and n such that: mⁿ = 32 Possible values are: m = 2, n = 5( since 2⁵ = 32) Step 2: Compute nᵐⁿ  We substitute n = 5Read more

    We  are given that m and n are two natural numbers, and mⁿ = 32
    We need to find the value of nᵐⁿ.
    Step 1: Find Possible Value of m and n
    Since 32 and 2⁵, we look for natural numbers m and n such that: mⁿ = 32
    Possible values are:
    m = 2, n = 5( since 2⁵ = 32)
    Step 2: Compute nᵐⁿ 
    We substitute n = 5 and mⁿ = 32: 
    nᵐⁿ = 5³²
    Step 3: Identify the correct option
    None of the options match 5³² directly.
    Please verify if there was a misinterpretation in the problem statement or options. If you meant nᵐ*ⁿ instead of nᵐⁿ , let’s check:
    nᵐ*ⁿ = 5²×⁵ = 5¹⁰
    This matches option (c) 5¹⁰.
    This question related to Chapter 1 Mathematics Class 9th NCERT. From the Chapter 1 Number System. Give answer according to your understanding.

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  5. We need to find a rational number between 3/5 and 4/5 fom the given options.  Step 1: Convert to Decimal Form 3/5 = 0.6 4/5 = 0.8 Now, we check which given options lie in the range (0.6, 0.8). Step 2: Convert the Options to Decimal Form  (a). 7/5 = 1.4 (Not between 0.6 and 0.8) (b). 7/10 = 0.7 (BetwRead more

    We need to find a rational number between 3/5 and 4/5 fom the given options. 
    Step 1: Convert to Decimal Form
    3/5 = 0.6
    4/5 = 0.8
    Now, we check which given options lie in the range (0.6, 0.8).
    Step 2: Convert the Options to Decimal Form 
    (a). 7/5 = 1.4 (Not between 0.6 and 0.8)
    (b). 7/10 = 0.7 (Between 0.6 and 0.8)
    (c). 3/10 = 0.3 (Less than 0.6)
    (d). 4/10 = 0.4 ( Less than 0.6)
    Conclusion: The only rational number between 3/5 and 4/5 is 7/10 (option b).
    This question related to Chapter 1 Mathematics Class 9th NCERT. From the Chapter 1 Number System. Give answer according to your understanding.

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    https://www.tiwariacademy.in/ncert-solutions/class-9/maths/

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