To convert degrees to radians, multiply by 𝜋/180. Here, 360° × 𝜋/180 = 2𝜋 radians. Hence, the angular velocity is 2𝜋 rad/s. This question related to Chapter 6 physics Class 11th NCERT. From the Chapter 6 System of Particles and Rotational Motion. Give answer according to your understanding. For moreRead more
To convert degrees to radians, multiply by 𝜋/180. Here, 360° × 𝜋/180 = 2𝜋 radians. Hence, the angular velocity is 2𝜋 rad/s. This question related to Chapter 6 physics Class 11th NCERT. From the Chapter 6 System of Particles and Rotational Motion. Give answer according to your understanding.
The formula for the moment of inertia of a solid sphere about an axis through its diameter is 𝐼 = 2/5 𝑀𝑅². This is derived based on the sphere's uniform mass distribution and symmetry. This question related to Chapter 6 physics Class 11th NCERT. From the Chapter 6 System of Particles and RotationalRead more
The formula for the moment of inertia of a solid sphere about an axis through its diameter is 𝐼 = 2/5 𝑀𝑅². This is derived based on the sphere’s uniform mass distribution and symmetry. This question related to Chapter 6 physics Class 11th NCERT. From the Chapter 6 System of Particles and Rotational Motion. Give answer according to your understanding.
For a uniform rod, the mass distribution is symmetric, so the center of mass lies at the geometrical center. Therefore, the center of mass is at the midpoint of the rod. This question related to Chapter 6 physics Class 11th NCERT. From the Chapter 6 System of Particles and Rotational Motion. Give anRead more
For a uniform rod, the mass distribution is symmetric, so the center of mass lies at the geometrical center. Therefore, the center of mass is at the midpoint of the rod.
This question related to Chapter 6 physics Class 11th NCERT. From the Chapter 6 System of Particles and Rotational Motion. Give answer according to your understanding.
For rolling without slipping, v = Rω. Translational kinetic energy is 1/2Mv², and rotational kinetic energy is 1/2Iω². Using I = 2/5MR²(for a sphere), we find the ratio KEₜᵣₐₙₛₗₐₜᵢₒₙₐₗ : KEᵣₒₜₐₜᵢₒₙₐₗ = 2 : 1. This question related to Chapter 6 physics Class 11th NCERT. From the Chapter 6 System of PRead more
For rolling without slipping, v = Rω. Translational kinetic energy is 1/2Mv², and rotational kinetic energy is 1/2Iω². Using I = 2/5MR²(for a sphere), we find the ratio KEₜᵣₐₙₛₗₐₜᵢₒₙₐₗ : KEᵣₒₜₐₜᵢₒₙₐₗ = 2 : 1.
This question related to Chapter 6 physics Class 11th NCERT. From the Chapter 6 System of Particles and Rotational Motion. Give answer according to your understanding.
Angular momentum 𝐿 = 𝐼 𝜔, so it depends directly on the moment of inertia 𝐼 and angular velocity ω. This question related to Chapter 6 physics Class 11th NCERT. From the Chapter 6 System of Particles and Rotational Motion. Give answer according to your understanding. For more please visit here: httpRead more
Angular momentum 𝐿 = 𝐼 𝜔, so it depends directly on the moment of inertia 𝐼 and angular velocity ω. This question related to Chapter 6 physics Class 11th NCERT. From the Chapter 6 System of Particles and Rotational Motion. Give answer according to your understanding.
What is the angular velocity of a body rotating at 360° per second in radians per second?
To convert degrees to radians, multiply by 𝜋/180. Here, 360° × 𝜋/180 = 2𝜋 radians. Hence, the angular velocity is 2𝜋 rad/s. This question related to Chapter 6 physics Class 11th NCERT. From the Chapter 6 System of Particles and Rotational Motion. Give answer according to your understanding. For moreRead more
To convert degrees to radians, multiply by 𝜋/180. Here, 360° × 𝜋/180 = 2𝜋 radians. Hence, the angular velocity is 2𝜋 rad/s. This question related to Chapter 6 physics Class 11th NCERT. From the Chapter 6 System of Particles and Rotational Motion. Give answer according to your understanding.
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See lesshttps://www.tiwariacademy.com/ncert-solutions/class-11/physics/chapter-6/
What is the moment of inertia of a solid sphere of mass 𝑀 and radius 𝑅 about an axis passing through its diameter?
The formula for the moment of inertia of a solid sphere about an axis through its diameter is 𝐼 = 2/5 𝑀𝑅². This is derived based on the sphere's uniform mass distribution and symmetry. This question related to Chapter 6 physics Class 11th NCERT. From the Chapter 6 System of Particles and RotationalRead more
The formula for the moment of inertia of a solid sphere about an axis through its diameter is 𝐼 = 2/5 𝑀𝑅². This is derived based on the sphere’s uniform mass distribution and symmetry. This question related to Chapter 6 physics Class 11th NCERT. From the Chapter 6 System of Particles and Rotational Motion. Give answer according to your understanding.
For more please visit here:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-11/physics/chapter-6/
What is the position of the center of mass of a uniform rod of length 𝐿 and mass 𝑀?
For a uniform rod, the mass distribution is symmetric, so the center of mass lies at the geometrical center. Therefore, the center of mass is at the midpoint of the rod. This question related to Chapter 6 physics Class 11th NCERT. From the Chapter 6 System of Particles and Rotational Motion. Give anRead more
For a uniform rod, the mass distribution is symmetric, so the center of mass lies at the geometrical center. Therefore, the center of mass is at the midpoint of the rod.
This question related to Chapter 6 physics Class 11th NCERT. From the Chapter 6 System of Particles and Rotational Motion. Give answer according to your understanding.
For more please visit here:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-11/physics/chapter-6/
A body of mass 𝑀 and radius 𝑅 is rolling without slipping. What is the ratio of its translational kinetic energy to rotational kinetic energy?
For rolling without slipping, v = Rω. Translational kinetic energy is 1/2Mv², and rotational kinetic energy is 1/2Iω². Using I = 2/5MR²(for a sphere), we find the ratio KEₜᵣₐₙₛₗₐₜᵢₒₙₐₗ : KEᵣₒₜₐₜᵢₒₙₐₗ = 2 : 1. This question related to Chapter 6 physics Class 11th NCERT. From the Chapter 6 System of PRead more
For rolling without slipping, v = Rω. Translational kinetic energy is 1/2Mv², and rotational kinetic energy is 1/2Iω². Using I = 2/5MR²(for a sphere), we find the ratio KEₜᵣₐₙₛₗₐₜᵢₒₙₐₗ : KEᵣₒₜₐₜᵢₒₙₐₗ = 2 : 1.
This question related to Chapter 6 physics Class 11th NCERT. From the Chapter 6 System of Particles and Rotational Motion. Give answer according to your understanding.
For more please visit here:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-11/physics/chapter-6/
What does the angular momentum of a system depend on?
Angular momentum 𝐿 = 𝐼 𝜔, so it depends directly on the moment of inertia 𝐼 and angular velocity ω. This question related to Chapter 6 physics Class 11th NCERT. From the Chapter 6 System of Particles and Rotational Motion. Give answer according to your understanding. For more please visit here: httpRead more
Angular momentum 𝐿 = 𝐼 𝜔, so it depends directly on the moment of inertia 𝐼 and angular velocity ω. This question related to Chapter 6 physics Class 11th NCERT. From the Chapter 6 System of Particles and Rotational Motion. Give answer according to your understanding.
For more please visit here:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-11/physics/chapter-6/