Anish made in 6 overs = 42 runs, ∴ Anish made in 1 overs = 42/6= 7 runs Anup made in 7 overs = 63 runs ∴ Anup made in 1 overs = 63/7 = 9 runs Thus, Anup made more runs per over. https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-12/
Anish made in 6 overs = 42 runs, ∴ Anish made in 1 overs = 42/6= 7 runs
Anup made in 7 overs = 63 runs
∴ Anup made in 1 overs = 63/7 = 9 runs
Thus, Anup made more runs per over.
For covering 594 km, a truck will be required diesel = 108 litres ∴ For covering 1 km, a truck will be required diesel = 108/594 = 2/11 ∴ For covering 1650 km, a truck will be required diesel = 2/11x1650 = 300 litres Thus, 300 litres diesel required by the truck to cover a distance of 1650 km. httpsRead more
For covering 594 km, a truck will be required diesel = 108 litres
∴ For covering 1 km, a truck will be required diesel = 108/594 = 2/11
∴ For covering 1650 km, a truck will be required diesel = 2/11×1650 = 300 litres
Thus, 300 litres diesel required by the truck to cover a distance of 1650 km.
The weight of 72 books = 9 kg ∴ The weight of 1 book = 9/72 = 1/8 ∴ The weight of 40 books = 1/8x40=5kg Thus, the weight of 40 books is 5 kg. https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-12/
The weight of 72 books = 9 kg
∴ The weight of 1 book = 9/72 = 1/8
∴ The weight of 40 books = 1/8×40=5kg
Thus, the weight of 40 books is 5 kg.
Cost of 4 dozen bananas = ₹180 Cost of 48 bananas = ₹180 [4 dozen = 4 x 12 = 48] ∴ From ₹180, number of bananas can be purchased = 48 ∴ From ₹1, number of bananas can be purchased = 48/180=4/15 ∴ From ₹90, number of bananas can be purchased = 4/15x90=24 = 24 bananas Thus, 24 bananas can be purchasedRead more
Cost of 4 dozen bananas = ₹180
Cost of 48 bananas = ₹180 [4 dozen = 4 x 12 = 48]
∴ From ₹180, number of bananas can be purchased = 48
∴ From ₹1, number of bananas can be purchased = 48/180=4/15
∴ From ₹90, number of bananas can be purchased = 4/15×90=24
= 24 bananas
Thus, 24 bananas can be purchased for ₹90.
Rent paid for 3 months = ₹15000 ∴ Rent paid for 1 months = 15000/3=5000 ∴ Rent paid for 12 months = 5000 x 12 = ₹60,000 Thus, the total rent of one year is ₹60,000. https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-12/
Rent paid for 3 months = ₹15000
∴ Rent paid for 1 months = 15000/3=5000
∴ Rent paid for 12 months = 5000 x 12 = ₹60,000
Thus, the total rent of one year is ₹60,000.
Degree of temperature dropped in last 30 days = 15 degrees Degree of temperature dropped in last 1 day = 15/30 = 1/2 degrees Degree of temperature dropped in last 10 days = 1/2x10 = 5 degree Thus, 5 degree Celsius temperature dropped in 10 days. https://www.tiwariacademy.com/ncert-solutions/class-6/Read more
Degree of temperature dropped in last 30 days = 15 degrees
Degree of temperature dropped in last 1 day = 15/30 = 1/2 degrees
Degree of temperature dropped in last 10 days = 1/2×10 = 5 degree
Thus, 5 degree Celsius temperature dropped in 10 days.
(b) From ₹91.50, quantity of wheat can be purchased = 5 kg ∴ From ₹1, quantity of wheat can be purchased = 5/91.50 ∴ From ₹183, quantity of wheat can be purchased = 5/91.50x183 = 10 kg https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-12/
(b) From ₹91.50, quantity of wheat can be purchased = 5 kg
∴ From ₹1, quantity of wheat can be purchased = 5/91.50
∴ From ₹183, quantity of wheat can be purchased = 5/91.50×183
= 10 kg
(a) Cost of 5 kg of wheat = ₹91.50 ∴ Cost of 1 kg of wheat =91.50/5=₹18.30 ∴ Cost of 8 kg of wheat = ₹18.30 x 8 = ₹146.40 https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-12/
(a) Cost of 5 kg of wheat = ₹91.50
∴ Cost of 1 kg of wheat =91.50/5=₹18.30
∴ Cost of 8 kg of wheat = ₹18.30 x 8 = ₹146.40
Rain in 3 days = 276 mm ∴ Rain in 1 day = 276/3 = 92 mm ∴ Rain in 7 days = 92 x 7 = 644 mm Thus, the rain in 7 days is 644 mm. https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-12/
Rain in 3 days = 276 mm
∴ Rain in 1 day = 276/3 = 92 mm
∴ Rain in 7 days = 92 x 7 = 644 mm
Thus, the rain in 7 days is 644 mm.
Anish made 42 runs in 6 overs and Anup made 63 runs in 7 overs. Who made more runs per over?
Anish made in 6 overs = 42 runs, ∴ Anish made in 1 overs = 42/6= 7 runs Anup made in 7 overs = 63 runs ∴ Anup made in 1 overs = 63/7 = 9 runs Thus, Anup made more runs per over. https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-12/
Anish made in 6 overs = 42 runs, ∴ Anish made in 1 overs = 42/6= 7 runs
Anup made in 7 overs = 63 runs
∴ Anup made in 1 overs = 63/7 = 9 runs
Thus, Anup made more runs per over.
https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-12/
See lessRaju purchases 10 pens for ₹150 and Manish buys 7 pens for ₹84. Can you say who got the pen cheaper?
Raju purchase 10 pens for = ₹150 ∴ Raju purchases 1 pen for = 150/10 = ₹15 Manish purchases 7 pens for = ₹84 ∴ Manish purchases 1 pen for = 84/7= ₹12 Thus, Manish got the pens cheaper. https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-12/
Raju purchase 10 pens for = ₹150
∴ Raju purchases 1 pen for = 150/10 = ₹15
Manish purchases 7 pens for = ₹84
∴ Manish purchases 1 pen for = 84/7= ₹12
Thus, Manish got the pens cheaper.
https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-12/
See lessA truck requires 108 litres of diesel for covering a distance of 594 km. How much diesel will be required by the truck to cover a distance of 1650 km?
For covering 594 km, a truck will be required diesel = 108 litres ∴ For covering 1 km, a truck will be required diesel = 108/594 = 2/11 ∴ For covering 1650 km, a truck will be required diesel = 2/11x1650 = 300 litres Thus, 300 litres diesel required by the truck to cover a distance of 1650 km. httpsRead more
For covering 594 km, a truck will be required diesel = 108 litres
∴ For covering 1 km, a truck will be required diesel = 108/594 = 2/11
∴ For covering 1650 km, a truck will be required diesel = 2/11×1650 = 300 litres
Thus, 300 litres diesel required by the truck to cover a distance of 1650 km.
https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-12/
See lessThe weight of 72 books is 9 kg what is the weight of 40 such books?
The weight of 72 books = 9 kg ∴ The weight of 1 book = 9/72 = 1/8 ∴ The weight of 40 books = 1/8x40=5kg Thus, the weight of 40 books is 5 kg. https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-12/
The weight of 72 books = 9 kg
∴ The weight of 1 book = 9/72 = 1/8
∴ The weight of 40 books = 1/8×40=5kg
Thus, the weight of 40 books is 5 kg.
https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-12/
See lessCost of 4 dozens bananas is ₹180. How many bananas can be purchased for ₹90?
Cost of 4 dozen bananas = ₹180 Cost of 48 bananas = ₹180 [4 dozen = 4 x 12 = 48] ∴ From ₹180, number of bananas can be purchased = 48 ∴ From ₹1, number of bananas can be purchased = 48/180=4/15 ∴ From ₹90, number of bananas can be purchased = 4/15x90=24 = 24 bananas Thus, 24 bananas can be purchasedRead more
Cost of 4 dozen bananas = ₹180
Cost of 48 bananas = ₹180 [4 dozen = 4 x 12 = 48]
∴ From ₹180, number of bananas can be purchased = 48
∴ From ₹1, number of bananas can be purchased = 48/180=4/15
∴ From ₹90, number of bananas can be purchased = 4/15×90=24
= 24 bananas
Thus, 24 bananas can be purchased for ₹90.
https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-12/
See lessShaina pays ₹15000 as rent for 3 months. How much does she has to pay for a whole year, if the rent per month remains same?
Rent paid for 3 months = ₹15000 ∴ Rent paid for 1 months = 15000/3=5000 ∴ Rent paid for 12 months = 5000 x 12 = ₹60,000 Thus, the total rent of one year is ₹60,000. https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-12/
Rent paid for 3 months = ₹15000
∴ Rent paid for 1 months = 15000/3=5000
∴ Rent paid for 12 months = 5000 x 12 = ₹60,000
Thus, the total rent of one year is ₹60,000.
https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-12/
See lessThe temperature dropped 15 degree Celsius in the last 30 days. If the rate of temperature drop remains the same, how many degrees will the temperature drop in the next ten days?
Degree of temperature dropped in last 30 days = 15 degrees Degree of temperature dropped in last 1 day = 15/30 = 1/2 degrees Degree of temperature dropped in last 10 days = 1/2x10 = 5 degree Thus, 5 degree Celsius temperature dropped in 10 days. https://www.tiwariacademy.com/ncert-solutions/class-6/Read more
Degree of temperature dropped in last 30 days = 15 degrees
Degree of temperature dropped in last 1 day = 15/30 = 1/2 degrees
Degree of temperature dropped in last 10 days = 1/2×10 = 5 degree
Thus, 5 degree Celsius temperature dropped in 10 days.
https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-12/
See lessCost of 5 kg of wheat is ₹91.50. (a) What will be the cost of 8 kg of wheat? (b) What quantity of wheat can be purchased in ₹183?
(b) From ₹91.50, quantity of wheat can be purchased = 5 kg ∴ From ₹1, quantity of wheat can be purchased = 5/91.50 ∴ From ₹183, quantity of wheat can be purchased = 5/91.50x183 = 10 kg https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-12/
(b) From ₹91.50, quantity of wheat can be purchased = 5 kg
∴ From ₹1, quantity of wheat can be purchased = 5/91.50
∴ From ₹183, quantity of wheat can be purchased = 5/91.50×183
= 10 kg
https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-12/
See lessCost of 5 kg of wheat is ₹91.50. (a) What will be the cost of 8 kg of wheat? (b) What quantity of wheat can be purchased in ₹183?
(a) Cost of 5 kg of wheat = ₹91.50 ∴ Cost of 1 kg of wheat =91.50/5=₹18.30 ∴ Cost of 8 kg of wheat = ₹18.30 x 8 = ₹146.40 https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-12/
(a) Cost of 5 kg of wheat = ₹91.50
∴ Cost of 1 kg of wheat =91.50/5=₹18.30
∴ Cost of 8 kg of wheat = ₹18.30 x 8 = ₹146.40
https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-12/
See lessIf it has rained 276 mm in the last 3 days, how many cm of rain will fall in one full week (7 days)? Assume that the rain continues to fall at the same rate.
Rain in 3 days = 276 mm ∴ Rain in 1 day = 276/3 = 92 mm ∴ Rain in 7 days = 92 x 7 = 644 mm Thus, the rain in 7 days is 644 mm. https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-12/
Rain in 3 days = 276 mm
∴ Rain in 1 day = 276/3 = 92 mm
∴ Rain in 7 days = 92 x 7 = 644 mm
Thus, the rain in 7 days is 644 mm.
https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-12/
See less