Cost of a dozen pens (12 pens) = ₹180 ∴ Cost of 1 pen = 180/12=₹15 Cost of 8 ball pens = ₹56 ∴ Cost of 1 ball pen = 56/8 = ₹7 Ratio of cost of one pen to that of one ball pen = 15/7 = 15:7 https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-12/
Cost of a dozen pens (12 pens) = ₹180
∴ Cost of 1 pen = 180/12=₹15
Cost of 8 ball pens = ₹56
∴ Cost of 1 ball pen = 56/8 = ₹7
Ratio of cost of one pen to that of one ball pen = 15/7 = 15:7
Total number of students = 1800, Number of students opted basketball = 750 Number of students opted cricket = 800 Therefore, number of students opted tennis = 1800 – (750 + 800) = 250 (a)Ratio of students opted basketball to that of opted table tennis=750/250=3/1=3:1 (b)Ratio of students opted crickRead more
Total number of students = 1800, Number of students opted basketball = 750
Number of students opted cricket = 800
Therefore, number of students opted tennis = 1800 – (750 + 800) = 250
(a)Ratio of students opted basketball to that of opted table tennis=750/250=3/1=3:1
(b)Ratio of students opted cricket to students opted basketball= 800/750=16/15=16:15
(c)Ratio of students opted basketball to total no. of students= 750/1800=5/12=5:12
Total number of students in school = 4320 Number of girls = 2300 Therefore, number of boys = 4320 – 2300 = 2020 (a) Ratio of girls to total number of students = 2300/4320 = 115/216 = 115:216 (b) Ratio of boys to that of girls = 2020/2300 = 101/115 = 101 : 115 (c) Ratio of boys to total number of stuRead more
Total number of students in school = 4320
Number of girls = 2300
Therefore, number of boys = 4320 – 2300 = 2020
(a) Ratio of girls to total number of students = 2300/4320 = 115/216 = 115:216
(b) Ratio of boys to that of girls = 2020/2300 = 101/115 = 101 : 115
(c) Ratio of boys to total number of students = 2020/4320 = 101/216=101 : 216
(a) 30 minutes to 1.5 hour 1.5 hours = 1.5 x 60 = 90 minutes [∵ 1 hour = 60 minutes] Now, ratio of 30 minutes to 1.5 hour = 30 minutes : 1.5 hour ⇒ 30 minutes : 90 minutes = 30/90 = 1/3 1:3 (b) 40 cm to 1.5 m 1.5 m = 1.5 x 100 cm = 150 cm [∵ 1 m = 100 cm] Now, ratio of 40 cm to 1.5 m = 40 cm : 1.5 mRead more
(a) 30 minutes to 1.5 hour
1.5 hours = 1.5 x 60 = 90 minutes [∵ 1 hour = 60 minutes]
Now, ratio of 30 minutes to 1.5 hour = 30 minutes : 1.5 hour
⇒ 30 minutes : 90 minutes = 30/90 = 1/3 1:3
(b) 40 cm to 1.5 m
1.5 m = 1.5 x 100 cm = 150 cm [∵ 1 m = 100 cm]
Now, ratio of 40 cm to 1.5 m = 40 cm : 1.5 m
⇒ 40 cm : 150 cm = 40/150 = 4/15 = 4:15
(c) 55 paise to Re. 1
₹ 1 = 100 paise
Now, ratio of 55 paise to ₹1 = 55 paise : 100 paise
⇒ 55/100 = 11:20
(d) 500 ml to 2 litters
2 litres = 2 x 1000 ml = 2000 ml [∵1 litre = 1000 ml]
Now, ratio of 500 ml to 2 litres = 500 ml : 2 litres
⇒ 500 ml : 2000 ml = 500/2000 = 1/4 = 1:4
(a) Ratio of 81 to 108 = 81/108 = 3/4 = 3:4 (b) Ratio of 98 to 63 = 98/63 = 14/9 = 14:9 (c) Ratio of 33 km to 121 km = 33/121 = 3:11 (d) Ratio of 30 minutes to 45 minutes = 30/45 = 2/3 =2:3 https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-12/
(a) Ratio of 81 to 108 = 81/108 = 3/4 = 3:4
(b) Ratio of 98 to 63 = 98/63 = 14/9 = 14:9
(c) Ratio of 33 km to 121 km = 33/121 = 3:11
(d) Ratio of 30 minutes to 45 minutes = 30/45 = 2/3 =2:3
We know that, Speed = Distance/Time Speed of Hamid = 9m/1h= 9 km/h and Speed of Akhtar = 12m/1h- 12km/h Ratio of speed of Hamid to that of speed of Akhtar = 9/12 = 3/4 = 3:4 https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-12/
We know that, Speed = Distance/Time
Speed of Hamid = 9m/1h= 9 km/h and Speed of Akhtar = 12m/1h- 12km/h
Ratio of speed of Hamid to that of speed of Akhtar = 9/12 = 3/4 = 3:4
(a) Ratio of number of triangle to that of circles = 3/2 = 3:2 (b) Ratio of number of squares to all figures = 2/7 = 2:7 (c) Ratio of number of circles to all figures = 2/7 = 2:7 https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-12/
(a) Ratio of number of triangle to that of circles = 3/2 = 3:2
(b) Ratio of number of squares to all figures = 2/7 = 2:7
(c) Ratio of number of circles to all figures = 2/7 = 2:7
Total number of students = 30 Number of students like football = 6 Number of students like cricket = 12 Thus number of students like tennis = 30 – 6 – 12 = 12 (a) The ratio of students like football that of tennis = 6/12 = 1/2 =1:2 (b) The ratio of students like cricket to that of total students = 1Read more
Total number of students = 30
Number of students like football = 6
Number of students like cricket = 12
Thus number of students like tennis = 30 – 6 – 12 = 12
(a) The ratio of students like football that of tennis = 6/12 = 1/2 =1:2
(b) The ratio of students like cricket to that of total students = 12/30 = 2/5 = 2:5
Cost of a dozen pens is ₹180 and cost of 8 ball pens is ₹56. Find the ratio of the cost of a pen to the cost of a ball pen.
Cost of a dozen pens (12 pens) = ₹180 ∴ Cost of 1 pen = 180/12=₹15 Cost of 8 ball pens = ₹56 ∴ Cost of 1 ball pen = 56/8 = ₹7 Ratio of cost of one pen to that of one ball pen = 15/7 = 15:7 https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-12/
Cost of a dozen pens (12 pens) = ₹180
∴ Cost of 1 pen = 180/12=₹15
Cost of 8 ball pens = ₹56
∴ Cost of 1 ball pen = 56/8 = ₹7
Ratio of cost of one pen to that of one ball pen = 15/7 = 15:7
https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-12/
See lessOut of 1800 students in a school, 750 opted basketball, 800 opted cricket and remaining opted table tennis. If a student can opt only one game, find the ratio of: (a) Number of students who opted basketball to the number of students who opted table tennis. (b) Number of students who opted cricket to the number of students opting basketball. (c) Number of students who opted basketball to the total number of students.
Total number of students = 1800, Number of students opted basketball = 750 Number of students opted cricket = 800 Therefore, number of students opted tennis = 1800 – (750 + 800) = 250 (a)Ratio of students opted basketball to that of opted table tennis=750/250=3/1=3:1 (b)Ratio of students opted crickRead more
Total number of students = 1800, Number of students opted basketball = 750
Number of students opted cricket = 800
Therefore, number of students opted tennis = 1800 – (750 + 800) = 250
(a)Ratio of students opted basketball to that of opted table tennis=750/250=3/1=3:1
(b)Ratio of students opted cricket to students opted basketball= 800/750=16/15=16:15
(c)Ratio of students opted basketball to total no. of students= 750/1800=5/12=5:12
https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-12/
See lessIn a college out of 4320 students, 2300 are girls. Find the ratio of: (a) Number of girls to the total number of students. (b) Number of boys to the number of girls. (c) Number of boys to the total number of students.
Total number of students in school = 4320 Number of girls = 2300 Therefore, number of boys = 4320 – 2300 = 2020 (a) Ratio of girls to total number of students = 2300/4320 = 115/216 = 115:216 (b) Ratio of boys to that of girls = 2020/2300 = 101/115 = 101 : 115 (c) Ratio of boys to total number of stuRead more
Total number of students in school = 4320
Number of girls = 2300
Therefore, number of boys = 4320 – 2300 = 2020
(a) Ratio of girls to total number of students = 2300/4320 = 115/216 = 115:216
(b) Ratio of boys to that of girls = 2020/2300 = 101/115 = 101 : 115
(c) Ratio of boys to total number of students = 2020/4320 = 101/216=101 : 216
https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-12/
See lessThere are 102 teachers in a school of 3300 students. Find the ratio of the number of teachers to the number of students.
Ratio of number of teachers to that of students = 102/3300 = 17/550 = 17:550 https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-12/
Ratio of number of teachers to that of students = 102/3300 = 17/550 = 17:550
https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-12/
See lessIn a year, Seema earns ₹1,50,000 and saves ₹50,000. Find the ratio of: (a) Money that Seema earns to the money she saves. (b) Money that she saves to the money she spends.
Total earning = ₹1,50,000 and Saving = ₹50,000 ∴ Money spent = ₹1,50,000 - ₹50,000 = ₹1,00,000 (a) Ratio of money earned to money saved = 150000/50000 = 3/1 =3:1 (b) Ratio of money saved to money spend = 50000/100000 = 1/2 =1:2 https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-12/
Total earning = ₹1,50,000 and Saving = ₹50,000
∴ Money spent = ₹1,50,000 – ₹50,000 = ₹1,00,000
(a) Ratio of money earned to money saved = 150000/50000 = 3/1 =3:1
(b) Ratio of money saved to money spend = 50000/100000 = 1/2 =1:2
https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-12/
See lessFind the ratio of the following: (a) 30 minutes to 1 hour (b) 40 cm to 1.5 m (c) 55 paise to ₹ 1 (d) 500 ml to 2 litres
(a) 30 minutes to 1.5 hour 1.5 hours = 1.5 x 60 = 90 minutes [∵ 1 hour = 60 minutes] Now, ratio of 30 minutes to 1.5 hour = 30 minutes : 1.5 hour ⇒ 30 minutes : 90 minutes = 30/90 = 1/3 1:3 (b) 40 cm to 1.5 m 1.5 m = 1.5 x 100 cm = 150 cm [∵ 1 m = 100 cm] Now, ratio of 40 cm to 1.5 m = 40 cm : 1.5 mRead more
(a) 30 minutes to 1.5 hour
1.5 hours = 1.5 x 60 = 90 minutes [∵ 1 hour = 60 minutes]
Now, ratio of 30 minutes to 1.5 hour = 30 minutes : 1.5 hour
⇒ 30 minutes : 90 minutes = 30/90 = 1/3 1:3
(b) 40 cm to 1.5 m
1.5 m = 1.5 x 100 cm = 150 cm [∵ 1 m = 100 cm]
Now, ratio of 40 cm to 1.5 m = 40 cm : 1.5 m
⇒ 40 cm : 150 cm = 40/150 = 4/15 = 4:15
(c) 55 paise to Re. 1
₹ 1 = 100 paise
Now, ratio of 55 paise to ₹1 = 55 paise : 100 paise
⇒ 55/100 = 11:20
(d) 500 ml to 2 litters
2 litres = 2 x 1000 ml = 2000 ml [∵1 litre = 1000 ml]
Now, ratio of 500 ml to 2 litres = 500 ml : 2 litres
⇒ 500 ml : 2000 ml = 500/2000 = 1/4 = 1:4
https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-12/
See lessFind the ratio of the following: (a) 81 to 108 (b) 98 to 63 (c) 33 km to 121 km (d) 30 minutes to 45 minutes
(a) Ratio of 81 to 108 = 81/108 = 3/4 = 3:4 (b) Ratio of 98 to 63 = 98/63 = 14/9 = 14:9 (c) Ratio of 33 km to 121 km = 33/121 = 3:11 (d) Ratio of 30 minutes to 45 minutes = 30/45 = 2/3 =2:3 https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-12/
(a) Ratio of 81 to 108 = 81/108 = 3/4 = 3:4
(b) Ratio of 98 to 63 = 98/63 = 14/9 = 14:9
(c) Ratio of 33 km to 121 km = 33/121 = 3:11
(d) Ratio of 30 minutes to 45 minutes = 30/45 = 2/3 =2:3
https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-12/
See lessDistances travelled by Hamid and Akhtar in an hour are 9 km and 12 km. Find the ratio of speed of Hamid to the speed of Akhtar.
We know that, Speed = Distance/Time Speed of Hamid = 9m/1h= 9 km/h and Speed of Akhtar = 12m/1h- 12km/h Ratio of speed of Hamid to that of speed of Akhtar = 9/12 = 3/4 = 3:4 https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-12/
We know that, Speed = Distance/Time
Speed of Hamid = 9m/1h= 9 km/h and Speed of Akhtar = 12m/1h- 12km/h
Ratio of speed of Hamid to that of speed of Akhtar = 9/12 = 3/4 = 3:4
https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-12/
See lessSee the figure and find the ratio of: (a) Number of triangles to the number of circles inside the rectangle. (b) Number of squares to all the figures inside the rectangle. (c) Number of circles to all the figures inside the rectangle.
(a) Ratio of number of triangle to that of circles = 3/2 = 3:2 (b) Ratio of number of squares to all figures = 2/7 = 2:7 (c) Ratio of number of circles to all figures = 2/7 = 2:7 https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-12/
(a) Ratio of number of triangle to that of circles = 3/2 = 3:2
(b) Ratio of number of squares to all figures = 2/7 = 2:7
(c) Ratio of number of circles to all figures = 2/7 = 2:7
https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-12/
See lessOut of 30 students in a class, like football, 12 like cricket and remaining like tennis. Find the ratio of: (a) Number of students liking football to number of students liking tennis. (b) Number of students liking cricket to total number of students.
Total number of students = 30 Number of students like football = 6 Number of students like cricket = 12 Thus number of students like tennis = 30 – 6 – 12 = 12 (a) The ratio of students like football that of tennis = 6/12 = 1/2 =1:2 (b) The ratio of students like cricket to that of total students = 1Read more
Total number of students = 30
Number of students like football = 6
Number of students like cricket = 12
Thus number of students like tennis = 30 – 6 – 12 = 12
(a) The ratio of students like football that of tennis = 6/12 = 1/2 =1:2
(b) The ratio of students like cricket to that of total students = 12/30 = 2/5 = 2:5
https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-12/
See less