Earning of 10 days = ₹3000 ∴ Earning of 1 day = 3000/10 ∴ Earning of 30 days = ₹300 x 30 = ₹9,000 Thus, the earning of 30 days is ₹9,000. https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-12/
Earning of 10 days = ₹3000
∴ Earning of 1 day = 3000/10
∴ Earning of 30 days = ₹300 x 30 = ₹9,000
Thus, the earning of 30 days is ₹9,000.
Cost of 7 m of cloth = ₹1470 ∴Cost of 1 m of cloth = 1470/7=₹210 ∴ Cost of 5 m of cloth = ₹210 x 5 = ₹1050 Thus, the cost of 5 m of cloth is ₹1050. https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-12/
Cost of 7 m of cloth = ₹1470
∴Cost of 1 m of cloth = 1470/7=₹210
∴ Cost of 5 m of cloth = ₹210 x 5 = ₹1050
Thus, the cost of 5 m of cloth is ₹1050.
(a) 25 cm : 1 m = 25 cm : (1 x 100) cm = 25 cm : 100 cm = 25/100 = 1/4 = 1 : 4 ₹40 : ₹160 = 40/160 = 1/4 = 1 : 4 Since the ratios are equal, therefore these are in proportion. Middle terms = 1 m, ₹40 and Extreme terms = 25 cm, ₹160 (b) 39 litres : 65 litres = 39/65=3/5 6 bottles : 10 bottles = 6/10Read more
(a) 25 cm : 1 m = 25 cm : (1 x 100) cm = 25 cm : 100 cm = 25/100 = 1/4 = 1 : 4
₹40 : ₹160 = 40/160 = 1/4 = 1 : 4
Since the ratios are equal, therefore these are in proportion.
Middle terms = 1 m, ₹40 and Extreme terms = 25 cm, ₹160
(b) 39 litres : 65 litres = 39/65=3/5
6 bottles : 10 bottles = 6/10 = 3/5 = 3:5
Since the ratios are equal, therefore these are in proportion.
Middle terms = 65 litres, 6 bottles and Extreme terms = 39 litres, 10 bottles
(c) 2 kg : 80 kg = 2/80=1/40= 1 : 40
25 g : 625 g = 25/625=1/25=1:25
Since the ratios are not equal, therefore these are not in proportion.
(d) 200 ml :2.5 litres =200 ml:(25000)litres=200 ml : 2500 ml=200/2500=2/25=2:25
₹4:₹50= 4/50=2/25=2:25
Since the ratios are equal, therefore these are in proportion.
Middle terms = 2.5 litres, ₹4 and Extreme terms = 200 ml, ₹50
(a) Ratio of father’s present age to that of son = 42/14 = 3/1 = 3 : 1 (b) When son was 12 years, i.e., 2 years ago, then father was (42 – 2) = 40 years Therefore, the ratio of their ages = 40/12 = 10/3 = 10:3 (c) Age of father after 10 years = 42 + 10 = 52 years Age of son after 10 years = 14 + 10Read more
(a) Ratio of father’s present age to that of son = 42/14 = 3/1 = 3 : 1
(b) When son was 12 years, i.e., 2 years ago, then father was (42 – 2) = 40 years
Therefore, the ratio of their ages = 40/12 = 10/3 = 10:3
(c) Age of father after 10 years = 42 + 10 = 52 years
Age of son after 10 years = 14 + 10 = 24 years
Therefore, ratio of their ages = 52/24 = 13/6 = 16:6
(d) When father was 30 years old,
i.e., 12 years ago, then son was (14 – 12) = 2 years old
Therefore, the ratio of their ages = 30/2 = 15/1 = 15:1
Ratio of the age of Shreya to that of Bhoomika = 15/12 = 5/4 =5 : 4 Thus, ₹36 divide between Shreya and Bhoomika in the ratio of 5 : 4. Shreya gets = 5/9 of ₹36 = 5/9x36=₹20 Bhoomika gets = 4/9 of ₹36 = 4/9x36=₹16 https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-12/
Ratio of the age of Shreya to that of Bhoomika = 15/12 = 5/4 =5 : 4
Thus, ₹36 divide between Shreya and Bhoomika in the ratio of 5 : 4.
Shreya gets = 5/9 of ₹36 = 5/9×36=₹20
Bhoomika gets = 4/9 of ₹36 = 4/9×36=₹16
Ratio between Sheela and Sangeeta = 3 : 2 Total these terms = 3 + 2 = 5 Therefore, the part of Sheela = 3/5 of the total pens and the part of Sangeeta = 2/5 of total pens Thus, Sheela gets = 3/5x20=12pens and Sangeeta gets = 2/5x20=8 pens https://www.tiwariacademy.com/ncert-solutions/class-6/maths/cRead more
Ratio between Sheela and Sangeeta = 3 : 2
Total these terms = 3 + 2 = 5
Therefore, the part of Sheela = 3/5 of the total pens
and the part of Sangeeta = 2/5 of total pens
Thus, Sheela gets = 3/5×20=12pens
and Sangeeta gets = 2/5×20=8 pens
Ekta earns ₹3000 in 10 days. How much will she earn in 30 days?
Earning of 10 days = ₹3000 ∴ Earning of 1 day = 3000/10 ∴ Earning of 30 days = ₹300 x 30 = ₹9,000 Thus, the earning of 30 days is ₹9,000. https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-12/
Earning of 10 days = ₹3000
∴ Earning of 1 day = 3000/10
∴ Earning of 30 days = ₹300 x 30 = ₹9,000
Thus, the earning of 30 days is ₹9,000.
https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-12/
See lessIf the cost of 7 m of cloth is ₹1470, find the cost of 5 m of cloth.
Cost of 7 m of cloth = ₹1470 ∴Cost of 1 m of cloth = 1470/7=₹210 ∴ Cost of 5 m of cloth = ₹210 x 5 = ₹1050 Thus, the cost of 5 m of cloth is ₹1050. https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-12/
Cost of 7 m of cloth = ₹1470
∴Cost of 1 m of cloth = 1470/7=₹210
∴ Cost of 5 m of cloth = ₹210 x 5 = ₹1050
Thus, the cost of 5 m of cloth is ₹1050.
https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-12/
See lessDetermine if the following ratios form a proportion. Also, write the middle terms and extreme terms where the ratios form a proportion: (a) 25 cm : 1 m and ₹40 : ₹160 (b) 39 litres : 65 litres and 6 bottles : 10 bottles (c) 2 kg : 80 kg and 25 g : 625 g (d) 200 ml : 2.5 ml and ₹4 : ₹50
(a) 25 cm : 1 m = 25 cm : (1 x 100) cm = 25 cm : 100 cm = 25/100 = 1/4 = 1 : 4 ₹40 : ₹160 = 40/160 = 1/4 = 1 : 4 Since the ratios are equal, therefore these are in proportion. Middle terms = 1 m, ₹40 and Extreme terms = 25 cm, ₹160 (b) 39 litres : 65 litres = 39/65=3/5 6 bottles : 10 bottles = 6/10Read more
(a) 25 cm : 1 m = 25 cm : (1 x 100) cm = 25 cm : 100 cm = 25/100 = 1/4 = 1 : 4
₹40 : ₹160 = 40/160 = 1/4 = 1 : 4
Since the ratios are equal, therefore these are in proportion.
Middle terms = 1 m, ₹40 and Extreme terms = 25 cm, ₹160
(b) 39 litres : 65 litres = 39/65=3/5
6 bottles : 10 bottles = 6/10 = 3/5 = 3:5
Since the ratios are equal, therefore these are in proportion.
Middle terms = 65 litres, 6 bottles and Extreme terms = 39 litres, 10 bottles
(c) 2 kg : 80 kg = 2/80=1/40= 1 : 40
25 g : 625 g = 25/625=1/25=1:25
Since the ratios are not equal, therefore these are not in proportion.
(d) 200 ml :2.5 litres =200 ml:(25000)litres=200 ml : 2500 ml=200/2500=2/25=2:25
₹4:₹50= 4/50=2/25=2:25
Since the ratios are equal, therefore these are in proportion.
Middle terms = 2.5 litres, ₹4 and Extreme terms = 200 ml, ₹50
https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-12/
See lessAre the following statements true: (a) 40 persons : 200 persons = ₹15 : ₹75 (b) 7.5 litres : 15 litres = 5 kg : 10 kg (c) 99 kg : 45 kg = ₹44 : ₹20 (d) 32 m : 64 m = 6 sec. : 12 sec. (e) 45 km : 60 km = 12 hours : 15 hours
(a) 40 persons : 200 persons = 40/200 = 1/5 = 1:5 ₹15 : ₹75 = 15/75 = 1/5 = 1:5 Since, 40 persons : 200 persons = ₹15 : ₹75 Hence, the statement is true. (b) 7.5 litres : 15 litres = 7.5/15=75/150=1/2=1:2 5 kg : 10 kg = 5/10 = 1/2 = 1 : 2 Since, 7.5 litres : 15 litres = 5 kg : 10 kg Hence, the stateRead more
(a) 40 persons : 200 persons = 40/200 = 1/5 = 1:5
₹15 : ₹75 = 15/75 = 1/5 = 1:5
Since, 40 persons : 200 persons = ₹15 : ₹75
Hence, the statement is true.
(b) 7.5 litres : 15 litres = 7.5/15=75/150=1/2=1:2
5 kg : 10 kg = 5/10 = 1/2 = 1 : 2
Since, 7.5 litres : 15 litres = 5 kg : 10 kg
Hence, the statement is true.
(c) 99 kg : 45 kg = 99/45=11/5=11:5
₹44 : ₹20 = 44/20=11/5 = 11 : 5
Since, 99 kg : 45 kg = ₹44 : ₹20
Hence, the statement is true.
(d) 32 m : 64 m = 32/64 = 1/2 = 1:2
6 sec : 12 sec = 6/12 = 1/2 = 1:2
Since, 32 m : 64 m = 6 sec : 12 sec
Hence, the statement is true.
(e) 45 km : 60 km = 45/60=3/4=3:4
12 hours : 15 hours = 12/15=4/5=4:5
Since, 45 km : 60 km ≠ 12 hours : 15 hours
Hence, the statement is not true.
https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-12/
See lessWrite True (T) or False (F) against each of the following statements: (a) 16 : 24 : : 20 : 30 (b) 21 : 6 : : 35 : 10 (c) 12 : 18 : : 28 : 12 (d) 8 : 9 : : 24 : 27 (e) 5.2 : 3.9 : : 3 : 4 (f) 0.9 : 0.36 : : 10 : 4
(a) 16 : 24 :: 20 : 30 ⇒ 16/24 = 20/30 ⇒ 2/3=2/3 Hence, it is True. (b) 21 : 6 :: 35 : 10 ⇒ 21/6=35/10 ⇒ 2/3=3/7 Hence, it is False. (d) 8 : 9 :: 24 : 27 ⇒ 8/9=24/27 ⇒ 8/9=8/9 Hence, it is True. (e) 5.2 : 3.9 :: 3 : 4 ⇒ 5.2/3.9 = 3/4 ⇒ 4/3 = 3/4 Hence, it is False. (f) 0.9 : 0.36 :: 10 : 4 ⇒ 0.9/0.3Read more
(a) 16 : 24 :: 20 : 30
⇒ 16/24 = 20/30
⇒ 2/3=2/3
Hence, it is True.
(b) 21 : 6 :: 35 : 10
⇒ 21/6=35/10
⇒ 2/3=3/7
Hence, it is False.
(d) 8 : 9 :: 24 : 27
⇒ 8/9=24/27
⇒ 8/9=8/9
Hence, it is True.
(e) 5.2 : 3.9 :: 3 : 4
⇒ 5.2/3.9 = 3/4
⇒ 4/3 = 3/4
Hence, it is False.
(f) 0.9 : 0.36 :: 10 : 4
⇒ 0.9/0.36=10/4
⇒ 5/2=5/2
Hence, it is True.
https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-12/
See lessDetermine the following are in proportion: (a) 15, 45, 40, 120 (b) 33, 121, 9, 96 (c) 24, 28, 36, 48 (d) 32, 48, 70, 210 (e) 4, 6, 8, 12 (f) 33, 44, 75, 100
(f) 33 : 44 = 33/44 = 3/4 75 : 100 = 75/100 = 3/4=3:4 Since 33 : 44 = 75 : 100 Therefore, 33, 44, 75, 100 are in ratio. https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-12/
(f) 33 : 44 = 33/44 = 3/4
75 : 100 = 75/100 = 3/4=3:4
Since 33 : 44 = 75 : 100
Therefore, 33, 44, 75, 100 are in ratio.
https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-12/
See lessDetermine the following are in proportion: (a) 15, 45, 40, 120 (b) 33, 121, 9, 96 (c) 24, 28, 36, 48 (d) 32, 48, 70, 210 (e) 4, 6, 8, 12 (f) 33, 44, 75, 100
(a) 15:45 = 15/45=1/3=1:3 40 : 120 = 40/120=1/3=1:3 Since 15 : 45 = 40 : 120 Therefore, 15, 45, 40, 120 are in proportion. (b) 33 : 121 = 33/121=3/11=3:11 9 : 96 = 9/96=3/32=3:11 Since 33 : 121 ≠ 9 : 96 Therefore, 33, 121, 9, 96 are not in proportion. (c) 24 : 28 = 24/28 = 6/7 =6:7 36 : 48 = 36/48 =Read more
(a) 15:45 = 15/45=1/3=1:3
40 : 120 = 40/120=1/3=1:3
Since 15 : 45 = 40 : 120
Therefore, 15, 45, 40, 120 are in proportion.
(b) 33 : 121 = 33/121=3/11=3:11
9 : 96 = 9/96=3/32=3:11
Since 33 : 121 ≠ 9 : 96
Therefore, 33, 121, 9, 96 are not in proportion.
(c) 24 : 28 = 24/28 = 6/7 =6:7
36 : 48 = 36/48 = 3/4=3:4
Since 24 : 28 ≠ 36 : 48
Therefore, 24, 28, 36, 48 are not in proportion.
(d) 32 : 48 = 32/48 = 2/3 = 2 : 3
70 : 210 = 70/120 = 1/3 = 1:3
Since 32 : 48 ≠ 70 : 210
Therefore, 32, 48, 70, 210 are not in proportion.
(e) 4 : 6 = 4/6= 2/3- 2:3
8 : 12 = 8/12 = 2/3 = 2:3
Since 4 : 6 = 8 : 12
Therefore, 4, 6, 8, 12 are in proportion.
https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-12/
See lessPresent age of father is 42 years and that of his son is 14 years. Find the ratio of: (a) Present age of father to the present age of son. (b) Age of the father to the age of the son, when son was 12 years old. (c) Age of father after 10 years to the age of son after 10 years. (d) Age of father to the age of son when father was 30 years old.
(a) Ratio of father’s present age to that of son = 42/14 = 3/1 = 3 : 1 (b) When son was 12 years, i.e., 2 years ago, then father was (42 – 2) = 40 years Therefore, the ratio of their ages = 40/12 = 10/3 = 10:3 (c) Age of father after 10 years = 42 + 10 = 52 years Age of son after 10 years = 14 + 10Read more
(a) Ratio of father’s present age to that of son = 42/14 = 3/1 = 3 : 1
(b) When son was 12 years, i.e., 2 years ago, then father was (42 – 2) = 40 years
Therefore, the ratio of their ages = 40/12 = 10/3 = 10:3
(c) Age of father after 10 years = 42 + 10 = 52 years
Age of son after 10 years = 14 + 10 = 24 years
Therefore, ratio of their ages = 52/24 = 13/6 = 16:6
(d) When father was 30 years old,
i.e., 12 years ago, then son was (14 – 12) = 2 years old
Therefore, the ratio of their ages = 30/2 = 15/1 = 15:1
https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-12/
See lessMother wants to divide ₹36 between her daughters Shreya and Bhoomika in the ratio of their ages. If the age of Shreya is 15 years and age of Bhoomika is 12 years, find how much Shreya and Bhoomika will get.
Ratio of the age of Shreya to that of Bhoomika = 15/12 = 5/4 =5 : 4 Thus, ₹36 divide between Shreya and Bhoomika in the ratio of 5 : 4. Shreya gets = 5/9 of ₹36 = 5/9x36=₹20 Bhoomika gets = 4/9 of ₹36 = 4/9x36=₹16 https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-12/
Ratio of the age of Shreya to that of Bhoomika = 15/12 = 5/4 =5 : 4
Thus, ₹36 divide between Shreya and Bhoomika in the ratio of 5 : 4.
Shreya gets = 5/9 of ₹36 = 5/9×36=₹20
Bhoomika gets = 4/9 of ₹36 = 4/9×36=₹16
https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-12/
See lessDivide 20 pens between Sheela and Sangeeta in the ratio 3 : 2.
Ratio between Sheela and Sangeeta = 3 : 2 Total these terms = 3 + 2 = 5 Therefore, the part of Sheela = 3/5 of the total pens and the part of Sangeeta = 2/5 of total pens Thus, Sheela gets = 3/5x20=12pens and Sangeeta gets = 2/5x20=8 pens https://www.tiwariacademy.com/ncert-solutions/class-6/maths/cRead more
Ratio between Sheela and Sangeeta = 3 : 2
Total these terms = 3 + 2 = 5
Therefore, the part of Sheela = 3/5 of the total pens
and the part of Sangeeta = 2/5 of total pens
Thus, Sheela gets = 3/5×20=12pens
and Sangeeta gets = 2/5×20=8 pens
https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-12/
See less