From 2:a to 3:b is 15 minutes, so (60 + b) − a = 15, giving a − b = 45. Given a = 6b, we get 5b = 45, so b = 9. The second time was 3:09. Class 9 ...
Discussion Forum Latest Questions
Robot 1 follows the line y = (4/3)x, while Robot 2 follows y = 2(x − 10). Equating them gives 2x − 20 = (4/3)x, which solves to x = 30 and y = 40. Their paths intersect at (30, ...
Robot 1 follows the line y = (4/3)x, while Robot 2 follows y = 2(x − 10). Equating them gives 2x − 20 = (4/3)x, which solves to x = 30 and y = 40. Their paths intersect at (30, ...
Coincident lines require 1/(k − 1) = 2/(k + 1) = 3/(k + 3). Cross-multiplying the first pair gives k + 1 = 2k − 2, which solves to k = 3. This value satisfies all ratios equally. NCERT Solution for ...
Infinitely many solutions require (a + b)/3 = −2b/(−1) = (5a + 2b + 1)/14. Equating gives a = 5b and 5a − 26b = −1. Substituting a = 5b yields b = 1, which gives a = 5. Class 9 ...