The amount of pressure in water vapor contained in a container is solely dependent on the temperature and not on the quantity of water, as long as it is in sufficient amount to keep the liquid and vapor phase in equilibrium. Since containers B and E are at the same temperatures, then the two containRead more
The amount of pressure in water vapor contained in a container is solely dependent on the temperature and not on the quantity of water, as long as it is in sufficient amount to keep the liquid and vapor phase in equilibrium. Since containers B and E are at the same temperatures, then the two containers will have the same water vapor pressure, ignoring the contents’ differences in terms of water.
Hence, the ratio of the vapor pressures will be 1:1.
Thermally, an average human body is always losing thermal radiation for it is slightly above 37°C. What radiates is dominantly in the infrared region. Infrared waves are not detected by the eyes and can only be seen with specially designed sensors and some cameras. No matter the month or time, thisRead more
Thermally, an average human body is always losing thermal radiation for it is slightly above 37°C. What radiates is dominantly in the infrared region. Infrared waves are not detected by the eyes and can only be seen with specially designed sensors and some cameras. No matter the month or time, this emission remains constant because these depend on how hot the bodies are, hence not on nature.
The energy radiated by a body is given by Stefan-Boltzmann Law: E ∝ T⁴ Where: - E is the energy radiated, - T is the temperature in kelvins. If the temperature of the sun is doubled, i.e., T → 2T: E' ∝ (2T)⁴ = 16T⁴ This means that the energy hitting the Earth will be increased by a factor of 16. CliRead more
The energy radiated by a body is given by Stefan-Boltzmann Law: E ∝ T⁴ Where: – E is the energy radiated, – T is the temperature in kelvins. If the temperature of the sun is doubled, i.e., T → 2T: E’ ∝ (2T)⁴ = 16T⁴
This means that the energy hitting the Earth will be increased by a factor of 16.
To determine the radiating power of a black body according to the Stefan-Boltzmann law: P = σ A (T⁴ - Tₛ⁴) Where, - P is the radiating power - σ is the Stefan-Boltzmann constant. - A is the surface area. - T is the temperature of the body. - Tₛ is the temperature of the surroundings. Given: The tempRead more
To determine the radiating power of a black body according to the Stefan-Boltzmann law:
P = σ A (T⁴ – Tₛ⁴)
Where,
– P is the radiating power
– σ is the Stefan-Boltzmann constant.
– A is the surface area.
– T is the temperature of the body.
– Tₛ is the temperature of the surroundings.
Given:
The temperature of the black body, T = 727°C = 727 + 273 = 1000 K,
– Temperature of environment, Tᵣ = 227°C = 227 + 273 = 500 K,
Radiation intensity at 727°C is 60 W.
The change in radiation power at 727°C is as follows using power ratio due to temperature difference as follows:
The radiated energy by a black body follows the Stefan-Boltzmann law, according to which the energy radiated is proportional to the fourth power of the absolute temperature T (in Kelvin). Given temperature is 727°C. First convert the temperature from degree Celsius to Kelvin by just adding 273°. T =Read more
The radiated energy by a black body follows the Stefan-Boltzmann law, according to which the energy radiated is proportional to the fourth power of the absolute temperature T (in Kelvin).
Given temperature is 727°C. First convert the temperature from degree Celsius to Kelvin by just adding 273°.
T = 727°C + 273 = 1000 K
Since the radiated energy is proportional to T⁴, the energy in this case is proportional to (1000)⁴.
B and it contains half the amount of water in E. If both are at the same temperature, the water vapour in the containers will have pressure in the ratio of
The amount of pressure in water vapor contained in a container is solely dependent on the temperature and not on the quantity of water, as long as it is in sufficient amount to keep the liquid and vapor phase in equilibrium. Since containers B and E are at the same temperatures, then the two containRead more
The amount of pressure in water vapor contained in a container is solely dependent on the temperature and not on the quantity of water, as long as it is in sufficient amount to keep the liquid and vapor phase in equilibrium. Since containers B and E are at the same temperatures, then the two containers will have the same water vapor pressure, ignoring the contents’ differences in terms of water.
Hence, the ratio of the vapor pressures will be 1:1.
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Which of the following statement is true about the radiation emitted by human body?
Thermally, an average human body is always losing thermal radiation for it is slightly above 37°C. What radiates is dominantly in the infrared region. Infrared waves are not detected by the eyes and can only be seen with specially designed sensors and some cameras. No matter the month or time, thisRead more
Thermally, an average human body is always losing thermal radiation for it is slightly above 37°C. What radiates is dominantly in the infrared region. Infrared waves are not detected by the eyes and can only be seen with specially designed sensors and some cameras. No matter the month or time, this emission remains constant because these depend on how hot the bodies are, hence not on nature.
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See lesshttps://www.tiwariacademy.com/ncert-solutions/class-11/physics/chapter-10/
If the temperature of the sun is doubled, the rate of energy received on earth will be increased by a factor of
The energy radiated by a body is given by Stefan-Boltzmann Law: E ∝ T⁴ Where: - E is the energy radiated, - T is the temperature in kelvins. If the temperature of the sun is doubled, i.e., T → 2T: E' ∝ (2T)⁴ = 16T⁴ This means that the energy hitting the Earth will be increased by a factor of 16. CliRead more
The energy radiated by a body is given by Stefan-Boltzmann Law: E ∝ T⁴ Where: – E is the energy radiated, – T is the temperature in kelvins. If the temperature of the sun is doubled, i.e., T → 2T: E’ ∝ (2T)⁴ = 16T⁴
This means that the energy hitting the Earth will be increased by a factor of 16.
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See lesshttps://www.tiwariacademy.com/ncert-solutions/class-11/physics/chapter-10/
For a black body at temperature of 727°C, its radiating power is 60 W and temperature of surroundings is 227°C, then its radiating power will be
To determine the radiating power of a black body according to the Stefan-Boltzmann law: P = σ A (T⁴ - Tₛ⁴) Where, - P is the radiating power - σ is the Stefan-Boltzmann constant. - A is the surface area. - T is the temperature of the body. - Tₛ is the temperature of the surroundings. Given: The tempRead more
To determine the radiating power of a black body according to the Stefan-Boltzmann law:
P = σ A (T⁴ – Tₛ⁴)
Where,
– P is the radiating power
– σ is the Stefan-Boltzmann constant.
– A is the surface area.
– T is the temperature of the body.
– Tₛ is the temperature of the surroundings.
Given:
The temperature of the black body, T = 727°C = 727 + 273 = 1000 K,
– Temperature of environment, Tᵣ = 227°C = 227 + 273 = 500 K,
Radiation intensity at 727°C is 60 W.
The change in radiation power at 727°C is as follows using power ratio due to temperature difference as follows:
(P₂ / P₁) = (T₂ / T₁)⁴
Substitute values:
(P₂ / 60) = (1000 / 500)⁴
(P₂ / 60) = 16
P₂ = 60 × 16 = 960 W
So the correct value for the new radiating power is 240 W.
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A black body is at 727° C. It emits energy at a rate, which is proportional to
The radiated energy by a black body follows the Stefan-Boltzmann law, according to which the energy radiated is proportional to the fourth power of the absolute temperature T (in Kelvin). Given temperature is 727°C. First convert the temperature from degree Celsius to Kelvin by just adding 273°. T =Read more
The radiated energy by a black body follows the Stefan-Boltzmann law, according to which the energy radiated is proportional to the fourth power of the absolute temperature T (in Kelvin).
Given temperature is 727°C. First convert the temperature from degree Celsius to Kelvin by just adding 273°.
T = 727°C + 273 = 1000 K
Since the radiated energy is proportional to T⁴, the energy in this case is proportional to (1000)⁴.
click for more:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-11/physics/chapter-10/