When a body is heated up, it has an expansion of its particles. The body expands because the particles have all gained energy and are moving away. Expansion occurs in all dimensions, which includes increases in length, surface area, and volume. The rise in volume leads to a maximum change since it dRead more
When a body is heated up, it has an expansion of its particles. The body expands because the particles have all gained energy and are moving away. Expansion occurs in all dimensions, which includes increases in length, surface area, and volume. The rise in volume leads to a maximum change since it depends on the expansion in three dimensions: length, width, and height. The surface area increases in two dimensions. Length only expands in one dimension. Overall, expansion in volume is larger; thus, it is a correct choice to be compared with the effects of heating.
To calculate the resistance of tungsten at 500°C, we make use of the formula for temperature-sensitive resistance: Rₜ = R₀ × [1 + α × (Tₜ - T₀)] Here, - R₀ = 133 Ω (resistance at T₀ = 150°C), - α = 0.0045 per °C (temperature coefficient), - Tₜ = 500°C. Now, substituting the values, Rₜ = 133 × [1 + 0Read more
To calculate the resistance of tungsten at 500°C, we make use of the formula for temperature-sensitive resistance:
Rₜ = R₀ × [1 + α × (Tₜ – T₀)]
Here,
– R₀ = 133 Ω (resistance at T₀ = 150°C),
– α = 0.0045 per °C (temperature coefficient),
– Tₜ = 500°C.
The Celsius (centigrade) and Fahrenheit scales are equal at -40°. This can be derived using the conversion formula: F = (9/5)C + 32 Substitute F = C: C = (9/5)C + 32 Multiply through by 5 to eliminate the fraction: 5C = 9C + 160 Rearrange terms: -4C = 160 Solve for C: C = -40 Thus, the Celsius and FRead more
The Celsius (centigrade) and Fahrenheit scales are equal at -40°.
This can be derived using the conversion formula:
F = (9/5)C + 32
Substitute F = C:
C = (9/5)C + 32
Multiply through by 5 to eliminate the fraction:
5C = 9C + 160
Rearrange terms:
-4C = 160
Solve for C:
C = -40
Thus, the Celsius and Fahrenheit scales are equal at -40°.
In the scenario where a bullet is fired and gets embedded in a block on a frictionless table, we assess the conservation laws that apply to the situation. 1. Momentum Conservation: - During the collision, the system or the bullet along with the block is isolated; no external force acts on the systemRead more
In the scenario where a bullet is fired and gets embedded in a block on a frictionless table, we assess the conservation laws that apply to the situation.
1. Momentum Conservation:
– During the collision, the system or the bullet along with the block is isolated; no external force acts on the system in the horizontal direction (since the table is frictionless). Hence, momentum is conserved.
– Before the collision, the block is at rest, and the bullet is moving with its momentum. After the bullet gets embedded in the block, the total momentum is conserved before the collision to be equal to the total momentum after the collision.
2. Kinetic Energy Conservation:
– In this inelastic collision, kinetic energy is not conserved. Some of the kinetic energy from the bullet goes into internal energy during the collision (such as heat, sound, and deformation of the bullet and block).
3. Potential Energy Conservation:
– Potential energy is not involved in this problem since it does not change due to the fact that the bullet is embedded into the block horizontally on a frictionless table.
Final Answer:
In this case, momentum is conserved.
Use the formula for power to calculate how much power the motor supplies. Power (P) = Work done (W) / Time (t) Step 1: Calculate work done Work done (W) is given by the formula W = Force × Distance Given: Force (F) = 40 N Distance (d) = 30 m Now, calculate the work done: W = 40 N × 30 m W = 1200 J (Read more
Use the formula for power to calculate how much power the motor supplies.
Power (P) = Work done (W) / Time (t)
Step 1: Calculate work done
Work done (W) is given by the formula
W = Force × Distance
Given:
Force (F) = 40 N
Distance (d) = 30 m
Now, calculate the work done:
W = 40 N × 30 m
W = 1200 J (joules)
Step 2: Convert time from minutes to seconds
Since the motor pulls the cable in one minute,
Time (t) = 1 minute = 60 seconds
Step 3: Calculate the power
Now, substitute the values into the power formula:
P = W / t
P = 1200 J / 60 s
P = 20 W
Final Answer:
The power supplied by the motor is 20 watts.
When a body is heated, then maximum rise will be in its
When a body is heated up, it has an expansion of its particles. The body expands because the particles have all gained energy and are moving away. Expansion occurs in all dimensions, which includes increases in length, surface area, and volume. The rise in volume leads to a maximum change since it dRead more
When a body is heated up, it has an expansion of its particles. The body expands because the particles have all gained energy and are moving away. Expansion occurs in all dimensions, which includes increases in length, surface area, and volume. The rise in volume leads to a maximum change since it depends on the expansion in three dimensions: length, width, and height. The surface area increases in two dimensions. Length only expands in one dimension. Overall, expansion in volume is larger; thus, it is a correct choice to be compared with the effects of heating.
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The resistance of tungsten filament at 150°C is 133 Ω. What will be its resistance at 500°C? The temperature coefficient of resistance of tungsten is 0.0045 per °C.
To calculate the resistance of tungsten at 500°C, we make use of the formula for temperature-sensitive resistance: Rₜ = R₀ × [1 + α × (Tₜ - T₀)] Here, - R₀ = 133 Ω (resistance at T₀ = 150°C), - α = 0.0045 per °C (temperature coefficient), - Tₜ = 500°C. Now, substituting the values, Rₜ = 133 × [1 + 0Read more
To calculate the resistance of tungsten at 500°C, we make use of the formula for temperature-sensitive resistance:
Rₜ = R₀ × [1 + α × (Tₜ – T₀)]
Here,
– R₀ = 133 Ω (resistance at T₀ = 150°C),
– α = 0.0045 per °C (temperature coefficient),
– Tₜ = 500°C.
Now, substituting the values,
Rₜ = 133 × [1 + 0.0045 × (500 – 150)]
Rₜ = 133 × [1 + 0.0045 × 350]
Rₜ = 133 × [1 + 1.575]
Rₜ = 133 × 2.575 = 342.48 Ω.
The resistance is about 366 Ω.
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At which temperature, the centrigrade and Feherenheit scales are
The Celsius (centigrade) and Fahrenheit scales are equal at -40°. This can be derived using the conversion formula: F = (9/5)C + 32 Substitute F = C: C = (9/5)C + 32 Multiply through by 5 to eliminate the fraction: 5C = 9C + 160 Rearrange terms: -4C = 160 Solve for C: C = -40 Thus, the Celsius and FRead more
The Celsius (centigrade) and Fahrenheit scales are equal at -40°.
This can be derived using the conversion formula:
F = (9/5)C + 32
Substitute F = C:
C = (9/5)C + 32
Multiply through by 5 to eliminate the fraction:
5C = 9C + 160
Rearrange terms:
-4C = 160
Solve for C:
C = -40
Thus, the Celsius and Fahrenheit scales are equal at -40°.
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A bullet is fired and gets embedded in a block kept on table. If table is frictionless, then
In the scenario where a bullet is fired and gets embedded in a block on a frictionless table, we assess the conservation laws that apply to the situation. 1. Momentum Conservation: - During the collision, the system or the bullet along with the block is isolated; no external force acts on the systemRead more
In the scenario where a bullet is fired and gets embedded in a block on a frictionless table, we assess the conservation laws that apply to the situation.
1. Momentum Conservation:
– During the collision, the system or the bullet along with the block is isolated; no external force acts on the system in the horizontal direction (since the table is frictionless). Hence, momentum is conserved.
– Before the collision, the block is at rest, and the bullet is moving with its momentum. After the bullet gets embedded in the block, the total momentum is conserved before the collision to be equal to the total momentum after the collision.
2. Kinetic Energy Conservation:
– In this inelastic collision, kinetic energy is not conserved. Some of the kinetic energy from the bullet goes into internal energy during the collision (such as heat, sound, and deformation of the bullet and block).
3. Potential Energy Conservation:
– Potential energy is not involved in this problem since it does not change due to the fact that the bullet is embedded into the block horizontally on a frictionless table.
Final Answer:
In this case, momentum is conserved.
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An electric motor exerts a force of 40 N on a cable and pulls it by distance of 30 m in one minute. The power supplied by the motor (in watt) is
Use the formula for power to calculate how much power the motor supplies. Power (P) = Work done (W) / Time (t) Step 1: Calculate work done Work done (W) is given by the formula W = Force × Distance Given: Force (F) = 40 N Distance (d) = 30 m Now, calculate the work done: W = 40 N × 30 m W = 1200 J (Read more
Use the formula for power to calculate how much power the motor supplies.
Power (P) = Work done (W) / Time (t)
Step 1: Calculate work done
Work done (W) is given by the formula
W = Force × Distance
Given:
Force (F) = 40 N
Distance (d) = 30 m
Now, calculate the work done:
W = 40 N × 30 m
W = 1200 J (joules)
Step 2: Convert time from minutes to seconds
Since the motor pulls the cable in one minute,
Time (t) = 1 minute = 60 seconds
Step 3: Calculate the power
Now, substitute the values into the power formula:
P = W / t
P = 1200 J / 60 s
P = 20 W
Final Answer:
The power supplied by the motor is 20 watts.
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