Power of the electric motor is given by P = VI Where, V = 220 V and I = 5 A So, Power P = 220 × 5 = 1100 W Now, the energy consumed = Power × time Where, P = 1100 W t = 2 hours = 2 × 60 × 60 seconds = 7200 seconds So, the energy consumed E = 1100 × 7200 J = 7920000 J For more answers visit to websitRead more
Power of the electric motor is given by
P = VI
Where, V = 220 V and I = 5 A
So, Power P = 220 × 5 = 1100 W
Now, the energy consumed = Power × time
Where, P = 1100 W
t = 2 hours = 2 × 60 × 60 seconds = 7200 seconds
So, the energy consumed E = 1100 × 7200 J = 7920000 J
The rate of consumption of electric energy in an electric appliance is called electric power. Hence, the rate at which energy is delivered by a current is the power of the appliance. For more answers visit to website: https://www.tiwariacademy.com/ncert-solutions/class-10/science/chapter-12/
The rate of consumption of electric energy in an electric appliance is called electric power. Hence, the rate at which energy is delivered by a current is the power of the appliance.
According to Joule’s law of heating, the amount of heat produced is given by H = VIt Where, V = IR = 5A × 20 Ω = 100 V I = 5 A and t = 30 seconds So, 𝐻=100×5×30 𝐽 =15000 𝐽 =1.5×10⁴ 𝐽 For more answers visit to website: https://www.tiwariacademy.com/ncert-solutions/class-10/science/chapter-12/
According to Joule’s law of heating, the amount of heat produced is given by
H = VIt
Where,
V = IR = 5A × 20 Ω = 100 V
I = 5 A
and t = 30 seconds
So, 𝐻=100×5×30 𝐽
=15000 𝐽
=1.5×10⁴ 𝐽
According to Joule’s law of heating, the amount of heat produced is given by H = VIt Where, V = 50 V 𝐼= 𝐶ℎ𝑎𝑟𝑔𝑒/𝑡𝑖𝑚𝑒= 9600 𝑐𝑜𝑢𝑙𝑜𝑚𝑏/1 ℎ𝑟 = 9600/60×60 = 803 𝐴 and t = 1 hour = 60 × 60 seconds So, 𝐻=50×80/3×60×60 =4800000 𝐽=4.8×10⁶ 𝐽 For more answers visit to website: https://www.tiwariacademy.com/ncertRead more
According to Joule’s law of heating, the amount of heat produced is given by
H = VIt
Where,
V = 50 V
𝐼= 𝐶ℎ𝑎𝑟𝑔𝑒/𝑡𝑖𝑚𝑒= 9600 𝑐𝑜𝑢𝑙𝑜𝑚𝑏/1 ℎ𝑟 = 9600/60×60 = 803 𝐴
and t = 1 hour = 60 × 60 seconds
So,
𝐻=50×80/3×60×60
=4800000 𝐽=4.8×10⁶ 𝐽
The heating element of an electric heater is a resistor. According to Joule’s law of heating, the amount of heat produced by it is proportional to its resistance. H = I²Rt The resistance of the element of an electric heater is very high. As current flows through the heating element, it becomes too hRead more
The heating element of an electric heater is a resistor. According to Joule’s law of heating, the amount of heat produced by it is proportional to its resistance.
H = I²Rt
The resistance of the element of an electric heater is very high. As current flows through the heating element, it becomes too hot and glows red. On the other hand, the resistance of the cord is low. It does not become red when current flows through it.
An electric motor takes 5 A from a 220 V line. Determine the power of the motor and the energy consumed in 2 h.
Power of the electric motor is given by P = VI Where, V = 220 V and I = 5 A So, Power P = 220 × 5 = 1100 W Now, the energy consumed = Power × time Where, P = 1100 W t = 2 hours = 2 × 60 × 60 seconds = 7200 seconds So, the energy consumed E = 1100 × 7200 J = 7920000 J For more answers visit to websitRead more
Power of the electric motor is given by
P = VI
Where, V = 220 V and I = 5 A
So, Power P = 220 × 5 = 1100 W
Now, the energy consumed = Power × time
Where, P = 1100 W
t = 2 hours = 2 × 60 × 60 seconds = 7200 seconds
So, the energy consumed E = 1100 × 7200 J = 7920000 J
For more answers visit to website:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-10/science/chapter-12/
What determines the rate at which energy is delivered by a current?
The rate of consumption of electric energy in an electric appliance is called electric power. Hence, the rate at which energy is delivered by a current is the power of the appliance. For more answers visit to website: https://www.tiwariacademy.com/ncert-solutions/class-10/science/chapter-12/
The rate of consumption of electric energy in an electric appliance is called electric power. Hence, the rate at which energy is delivered by a current is the power of the appliance.
For more answers visit to website:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-10/science/chapter-12/
An electric iron of resistance 20 ohm takes a current of 5 A. Calculate the heat developed in 30 s.
According to Joule’s law of heating, the amount of heat produced is given by H = VIt Where, V = IR = 5A × 20 Ω = 100 V I = 5 A and t = 30 seconds So, 𝐻=100×5×30 𝐽 =15000 𝐽 =1.5×10⁴ 𝐽 For more answers visit to website: https://www.tiwariacademy.com/ncert-solutions/class-10/science/chapter-12/
According to Joule’s law of heating, the amount of heat produced is given by
H = VIt
Where,
V = IR = 5A × 20 Ω = 100 V
I = 5 A
and t = 30 seconds
So, 𝐻=100×5×30 𝐽
=15000 𝐽
=1.5×10⁴ 𝐽
For more answers visit to website:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-10/science/chapter-12/
Compute the heat generated while transferring 96000 coulomb of charge in one hour through a potential difference of 50 V.
According to Joule’s law of heating, the amount of heat produced is given by H = VIt Where, V = 50 V 𝐼= 𝐶ℎ𝑎𝑟𝑔𝑒/𝑡𝑖𝑚𝑒= 9600 𝑐𝑜𝑢𝑙𝑜𝑚𝑏/1 ℎ𝑟 = 9600/60×60 = 803 𝐴 and t = 1 hour = 60 × 60 seconds So, 𝐻=50×80/3×60×60 =4800000 𝐽=4.8×10⁶ 𝐽 For more answers visit to website: https://www.tiwariacademy.com/ncertRead more
According to Joule’s law of heating, the amount of heat produced is given by
H = VIt
Where,
V = 50 V
𝐼= 𝐶ℎ𝑎𝑟𝑔𝑒/𝑡𝑖𝑚𝑒= 9600 𝑐𝑜𝑢𝑙𝑜𝑚𝑏/1 ℎ𝑟 = 9600/60×60 = 803 𝐴
and t = 1 hour = 60 × 60 seconds
So,
𝐻=50×80/3×60×60
=4800000 𝐽=4.8×10⁶ 𝐽
For more answers visit to website:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-10/science/chapter-12/
Why does the cord of an electric heater not glow while the heating element does?
The heating element of an electric heater is a resistor. According to Joule’s law of heating, the amount of heat produced by it is proportional to its resistance. H = I²Rt The resistance of the element of an electric heater is very high. As current flows through the heating element, it becomes too hRead more
The heating element of an electric heater is a resistor. According to Joule’s law of heating, the amount of heat produced by it is proportional to its resistance.
H = I²Rt
The resistance of the element of an electric heater is very high. As current flows through the heating element, it becomes too hot and glows red. On the other hand, the resistance of the cord is low. It does not become red when current flows through it.
For more answers visit to website:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-10/science/chapter-12/