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Consult From physics

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  1. Asked: October 20, 2020In: Class 10

    Let the resistance of an electrical component remains constant while the potential difference across the two ends of the component decreases to half of its former value. What change will occur in the current through it?

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    Consult From physics
    Added an answer on December 6, 2020 at 8:23 am

    According to the Ohm’s law V = IR If the resistance remains constant, V is directly proportional to I. Therefore, 𝑉∝𝐼 Now, if potential difference is reduced to half of its value, the current also become half of its original value. For more answers visit to website: https://www.tiwariacademy.com/nceRead more

    According to the Ohm’s law V = IR
    If the resistance remains constant, V is directly proportional to I. Therefore, 𝑉∝𝐼
    Now, if potential difference is reduced to half of its value, the current also become half of its original value.

    For more answers visit to website:
    https://www.tiwariacademy.com/ncert-solutions/class-10/science/chapter-12/

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  2. Asked: October 20, 2020In: Class 10

    Will current flow more easily through a thick wire or a thin wire of the same material, when connected to the same source? Why?

    Consult From physics
    Added an answer on December 6, 2020 at 8:22 am

    Resistance (R) is inversely proportional to the area of cross-section (A) of the wire. So, thicker the wire, lower is the resistance of the wire and vice-versa. Therefore, current can flow more easily through a thick wire than a thin wire. 𝑅=𝜌𝐿/𝐴 ⇒𝑅 ∝1 /𝐴

    Resistance (R) is inversely proportional to the area of cross-section (A) of the wire. So, thicker the wire, lower is the resistance of the wire and vice-versa. Therefore, current can flow more easily through a thick wire than a thin wire.

    𝑅=𝜌𝐿/𝐴 ⇒𝑅 ∝1 /𝐴

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  3. Asked: October 20, 2020In: Class 10

    On what factors does the resistance of a conductor depend?

    Best Answer
    Consult From physics
    Added an answer on December 6, 2020 at 8:21 am

    The resistance of a conductor depends upon the following factors: • Length of the conductor • Cross-sectional area of the conductor • Material of the conductor • Temperature of the conductor. For more answers visit to website: https://www.tiwariacademy.com/ncert-solutions/class-10/science/chapter-12Read more

    The resistance of a conductor depends upon the following factors:
    • Length of the conductor
    • Cross-sectional area of the conductor
    • Material of the conductor
    • Temperature of the conductor.

    For more answers visit to website:
    https://www.tiwariacademy.com/ncert-solutions/class-10/science/chapter-12/

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  4. Asked: October 20, 2020In: Class 10

    How much energy is given to each coulomb of charge passing through a 6 V battery?

    Best Answer
    Consult From physics
    Added an answer on December 6, 2020 at 7:38 am

    𝑃𝑜𝑡𝑒𝑛𝑡𝑖𝑎𝑙 𝐷𝑖𝑓𝑓𝑒𝑟𝑒𝑛𝑐𝑒=𝑊𝑜𝑟𝑘 𝑑𝑜𝑛𝑒/𝐶ℎ𝑎𝑟𝑔𝑒 or Work done (or Energy) = Potential Difference × Charge So, Work done = 6 Volt × 1 Coulomb = 6 Joules For more answers visit to website: https://www.tiwariacademy.com/ncert-solutions/class-10/science/chapter-12/

    𝑃𝑜𝑡𝑒𝑛𝑡𝑖𝑎𝑙 𝐷𝑖𝑓𝑓𝑒𝑟𝑒𝑛𝑐𝑒=𝑊𝑜𝑟𝑘 𝑑𝑜𝑛𝑒/𝐶ℎ𝑎𝑟𝑔𝑒
    or Work done (or Energy) = Potential Difference × Charge
    So, Work done = 6 Volt × 1 Coulomb = 6 Joules

    For more answers visit to website:
    https://www.tiwariacademy.com/ncert-solutions/class-10/science/chapter-12/

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  5. Asked: October 20, 2020In: Class 10

    What is meant by saying that the potential difference between two points is 1 V?

    Best Answer
    Consult From physics
    Added an answer on December 6, 2020 at 7:33 am

    When 1 J of work is required to move a charge of 1 C from one point to another, then it is said that the potential difference between the two points is 1 V. V=W/Q 1 V = 1 J/1 C For more answers visit to website: https://www.tiwariacademy.com/ncert-solutions/class-10/science/chapter-12/

    When 1 J of work is required to move a charge of 1 C from one point to another, then it is said that the potential difference between the two points is 1 V.
    V=W/Q
    1 V = 1 J/1 C

    For more answers visit to website:
    https://www.tiwariacademy.com/ncert-solutions/class-10/science/chapter-12/

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