According to the Ohmβs law V = IR If the resistance remains constant, V is directly proportional to I. Therefore, πβπΌ Now, if potential difference is reduced to half of its value, the current also become half of its original value. For more answers visit to website: https://www.tiwariacademy.com/nceRead more
According to the Ohmβs law V = IR
If the resistance remains constant, V is directly proportional to I. Therefore, πβπΌ
Now, if potential difference is reduced to half of its value, the current also become half of its original value.
Resistance (R) is inversely proportional to the area of cross-section (A) of the wire. So, thicker the wire, lower is the resistance of the wire and vice-versa. Therefore, current can flow more easily through a thick wire than a thin wire. π =ππΏ/π΄ βπ β1 /π΄
Resistance (R) is inversely proportional to the area of cross-section (A) of the wire. So, thicker the wire, lower is the resistance of the wire and vice-versa. Therefore, current can flow more easily through a thick wire than a thin wire.
The resistance of a conductor depends upon the following factors: β’ Length of the conductor β’ Cross-sectional area of the conductor β’ Material of the conductor β’ Temperature of the conductor. For more answers visit to website: https://www.tiwariacademy.com/ncert-solutions/class-10/science/chapter-12Read more
The resistance of a conductor depends upon the following factors:
β’ Length of the conductor
β’ Cross-sectional area of the conductor
β’ Material of the conductor
β’ Temperature of the conductor.
πππ‘πππ‘πππ π·πππππππππ=ππππ ππππ/πΆβππππ or Work done (or Energy) = Potential Difference Γ Charge So, Work done = 6 Volt Γ 1 Coulomb = 6 Joules For more answers visit to website: https://www.tiwariacademy.com/ncert-solutions/class-10/science/chapter-12/
πππ‘πππ‘πππ π·πππππππππ=ππππ ππππ/πΆβππππ
or Work done (or Energy) = Potential Difference Γ Charge
So, Work done = 6 Volt Γ 1 Coulomb = 6 Joules
When 1 J of work is required to move a charge of 1 C from one point to another, then it is said that the potential difference between the two points is 1 V. V=W/Q 1 V = 1 J/1 C For more answers visit to website: https://www.tiwariacademy.com/ncert-solutions/class-10/science/chapter-12/
When 1 J of work is required to move a charge of 1 C from one point to another, then it is said that the potential difference between the two points is 1 V.
V=W/Q
1 V = 1 J/1 C
A cell, battery, power supply, etc. helps to maintain a potential difference across a conductor. For more answers visit to website: https://www.tiwariacademy.com/ncert-solutions/class-10/science/chapter-12/
A cell, battery, power supply, etc. helps to maintain a potential difference across a conductor.
We know that one electron possesses a charge of 1.6 Γ 10β»ΒΉβΉ C. ππ’ππππ ππ πππππ‘πππ=πππ‘ππ πβππππ/πΆβππππ ππ 1 πππππ‘πππ =1/1.6Γ10β»ΒΉβΉ=6.25Γ10ΒΉβΈ So, the number of electrons constituting one coulomb of charge is 6Γ10ΒΉβΈ. For more answers visit to website: https://www.tiwariacademy.com/ncert-solutions/class-Read more
We know that one electron possesses a charge of 1.6 Γ 10β»ΒΉβΉ C.
ππ’ππππ ππ πππππ‘πππ=πππ‘ππ πβππππ/πΆβππππ ππ 1 πππππ‘πππ
=1/1.6Γ10β»ΒΉβΉ=6.25Γ10ΒΉβΈ
So, the number of electrons constituting one coulomb of charge is 6Γ10ΒΉβΈ.
The unit of electric current is ampere (A). When 1 C of charge flows through a conductor in 1 s, it called 1 ampere (A) current. πΌ = π/π‘ For more answers visit to website: https://www.tiwariacademy.com/ncert-solutions/class-10/science/chapter-12/
The unit of electric current is ampere (A). When 1 C of charge flows through a conductor in 1 s, it called 1 ampere (A) current.
πΌ = π/π‘
An electric circuit is the pathway in which current can flow. It consists of electric devices, switching devices, source of electricity, etc. that are connected by conducting wires. For more answers visit to website: https://www.tiwariacademy.com/ncert-solutions/class-10/science/chapter-12/
An electric circuit is the pathway in which current can flow. It consists of electric devices, switching devices, source of electricity, etc. that are connected by conducting wires.
a) The melting point and resistivity of tungsten are very high. It does not burn readily at a high temperature. The electric lamps glow at very high temperatures. Hence, tungsten is mainly used as heating element of electric bulbs. b) The conductors of electric heating devices such as bread toastersRead more
a) The melting point and resistivity of tungsten are very high. It does not burn readily at a high temperature. The electric lamps glow at very high temperatures. Hence, tungsten is mainly used as heating element of electric bulbs.
b) The conductors of electric heating devices such as bread toasters and electric irons are made of alloy because resistivity of an alloy is more than that of metals. It produces large amount of heat and do not burn easily.
c) There is voltage division in series circuits. Each component of a series circuit receives a small voltage for a large supply voltage. As a result, the amount of current decreases and the device becomes hot. Hence, series arrangement is not used in domestic circuits.
d) Resistance (R) of a wire is inversely proportional to its area of cross-section (A):
π β 1/π΄
e) Copper and aluminium wires have low resistivity. They are good conductors of electricity. Hence, they are usually employed for electricity transmission.
Let the resistance of an electrical component remains constant while the potential difference across the two ends of the component decreases to half of its former value. What change will occur in the current through it?
According to the Ohmβs law V = IR If the resistance remains constant, V is directly proportional to I. Therefore, πβπΌ Now, if potential difference is reduced to half of its value, the current also become half of its original value. For more answers visit to website: https://www.tiwariacademy.com/nceRead more
According to the Ohmβs law V = IR
If the resistance remains constant, V is directly proportional to I. Therefore, πβπΌ
Now, if potential difference is reduced to half of its value, the current also become half of its original value.
For more answers visit to website:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-10/science/chapter-12/
Will current flow more easily through a thick wire or a thin wire of the same material, when connected to the same source? Why?
Resistance (R) is inversely proportional to the area of cross-section (A) of the wire. So, thicker the wire, lower is the resistance of the wire and vice-versa. Therefore, current can flow more easily through a thick wire than a thin wire. π =ππΏ/π΄ βπ β1 /π΄
Resistance (R) is inversely proportional to the area of cross-section (A) of the wire. So, thicker the wire, lower is the resistance of the wire and vice-versa. Therefore, current can flow more easily through a thick wire than a thin wire.
π =ππΏ/π΄ βπ β1 /π΄
See lessOn what factors does the resistance of a conductor depend?
The resistance of a conductor depends upon the following factors: β’ Length of the conductor β’ Cross-sectional area of the conductor β’ Material of the conductor β’ Temperature of the conductor. For more answers visit to website: https://www.tiwariacademy.com/ncert-solutions/class-10/science/chapter-12Read more
The resistance of a conductor depends upon the following factors:
β’ Length of the conductor
β’ Cross-sectional area of the conductor
β’ Material of the conductor
β’ Temperature of the conductor.
For more answers visit to website:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-10/science/chapter-12/
How much energy is given to each coulomb of charge passing through a 6 V battery?
πππ‘πππ‘πππ π·πππππππππ=ππππ ππππ/πΆβππππ or Work done (or Energy) = Potential Difference Γ Charge So, Work done = 6 Volt Γ 1 Coulomb = 6 Joules For more answers visit to website: https://www.tiwariacademy.com/ncert-solutions/class-10/science/chapter-12/
πππ‘πππ‘πππ π·πππππππππ=ππππ ππππ/πΆβππππ
or Work done (or Energy) = Potential Difference Γ Charge
So, Work done = 6 Volt Γ 1 Coulomb = 6 Joules
For more answers visit to website:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-10/science/chapter-12/
What is meant by saying that the potential difference between two points is 1 V?
When 1 J of work is required to move a charge of 1 C from one point to another, then it is said that the potential difference between the two points is 1 V. V=W/Q 1 V = 1 J/1 C For more answers visit to website: https://www.tiwariacademy.com/ncert-solutions/class-10/science/chapter-12/
When 1 J of work is required to move a charge of 1 C from one point to another, then it is said that the potential difference between the two points is 1 V.
V=W/Q
1 V = 1 J/1 C
For more answers visit to website:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-10/science/chapter-12/
Name a device that helps to maintain a potential difference across a conductor.
A cell, battery, power supply, etc. helps to maintain a potential difference across a conductor. For more answers visit to website: https://www.tiwariacademy.com/ncert-solutions/class-10/science/chapter-12/
A cell, battery, power supply, etc. helps to maintain a potential difference across a conductor.
For more answers visit to website:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-10/science/chapter-12/
Calculate the number of electrons constituting one coulomb of charge.
We know that one electron possesses a charge of 1.6 Γ 10β»ΒΉβΉ C. ππ’ππππ ππ πππππ‘πππ=πππ‘ππ πβππππ/πΆβππππ ππ 1 πππππ‘πππ =1/1.6Γ10β»ΒΉβΉ=6.25Γ10ΒΉβΈ So, the number of electrons constituting one coulomb of charge is 6Γ10ΒΉβΈ. For more answers visit to website: https://www.tiwariacademy.com/ncert-solutions/class-Read more
We know that one electron possesses a charge of 1.6 Γ 10β»ΒΉβΉ C.
ππ’ππππ ππ πππππ‘πππ=πππ‘ππ πβππππ/πΆβππππ ππ 1 πππππ‘πππ
=1/1.6Γ10β»ΒΉβΉ=6.25Γ10ΒΉβΈ
So, the number of electrons constituting one coulomb of charge is 6Γ10ΒΉβΈ.
For more answers visit to website:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-10/science/chapter-12/
Define the unit of current.
The unit of electric current is ampere (A). When 1 C of charge flows through a conductor in 1 s, it called 1 ampere (A) current. πΌ = π/π‘ For more answers visit to website: https://www.tiwariacademy.com/ncert-solutions/class-10/science/chapter-12/
The unit of electric current is ampere (A). When 1 C of charge flows through a conductor in 1 s, it called 1 ampere (A) current.
πΌ = π/π‘
For more answers visit to website:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-10/science/chapter-12/
What does an electric circuit mean?
An electric circuit is the pathway in which current can flow. It consists of electric devices, switching devices, source of electricity, etc. that are connected by conducting wires. For more answers visit to website: https://www.tiwariacademy.com/ncert-solutions/class-10/science/chapter-12/
An electric circuit is the pathway in which current can flow. It consists of electric devices, switching devices, source of electricity, etc. that are connected by conducting wires.
For more answers visit to website:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-10/science/chapter-12/
Explain the following
a) The melting point and resistivity of tungsten are very high. It does not burn readily at a high temperature. The electric lamps glow at very high temperatures. Hence, tungsten is mainly used as heating element of electric bulbs. b) The conductors of electric heating devices such as bread toastersRead more
a) The melting point and resistivity of tungsten are very high. It does not burn readily at a high temperature. The electric lamps glow at very high temperatures. Hence, tungsten is mainly used as heating element of electric bulbs.
b) The conductors of electric heating devices such as bread toasters and electric irons are made of alloy because resistivity of an alloy is more than that of metals. It produces large amount of heat and do not burn easily.
c) There is voltage division in series circuits. Each component of a series circuit receives a small voltage for a large supply voltage. As a result, the amount of current decreases and the device becomes hot. Hence, series arrangement is not used in domestic circuits.
d) Resistance (R) of a wire is inversely proportional to its area of cross-section (A):
See lessπ β 1/π΄
e) Copper and aluminium wires have low resistivity. They are good conductors of electricity. Hence, they are usually employed for electricity transmission.