It is correctly expressed as, T = 2π √(l/g). The time period (T) of a simple pendulum of length l is expressed by the formula given below: T = 2π √(l/g) where, - l is the length of the pendulum, - g is the acceleration due to gravity. This equation implies that the time period varies as the square rRead more
It is correctly expressed as, T = 2π √(l/g).
The time period (T) of a simple pendulum of length l is expressed by the formula given below:
T = 2π √(l/g)
where,
– l is the length of the pendulum,
– g is the acceleration due to gravity.
This equation implies that the time period varies as the square root of the length and is inversely proportional to the square root of gravity.
In Simple Harmonic Motion (SHM), the acceleration (a) is: a = -ω²x Here, - ω represents angular frequency, - x refers to displacement from mean position Acceleration is maximum when |x| is maximum, and this happens at the extreme positions in the motion. As x = 0 corresponds to the mean position, thRead more
In Simple Harmonic Motion (SHM), the acceleration (a) is:
a = -ω²x
Here,
– ω represents angular frequency,
– x refers to displacement from mean position
Acceleration is maximum when |x| is maximum, and this happens at the extreme positions in the motion. As x = 0 corresponds to the mean position, the acceleration is zero here.
The restoring force F in Simple Harmonic Motion (SHM) obeys Hooke's Law, which is represented by the expression: F = -kx Here, the meanings of the parameters are as follows: - k is the force constant (spring constant), - x is the displacement from the equilibrium position. The negative sign shows thRead more
The restoring force F in Simple Harmonic Motion (SHM) obeys Hooke’s Law, which is represented by the expression:
F = -kx
Here, the meanings of the parameters are as follows:
– k is the force constant (spring constant),
– x is the displacement from the equilibrium position.
The negative sign shows that it always acts against the displacement in an attempt to bring the particle back to its equilibrium position.
The total energy (E) in Simple Harmonic Motion (SHM) is expressed as: E = (1/2) k A² where: - k is the force constant, - A is the amplitude. Because energy is proportional to A², if the amplitude A is doubled (2A), the total energy becomes: E' = (1/2) k (2A)² = 4 × (1/2) k A² = 4E So, the total enerRead more
The total energy (E) in Simple Harmonic Motion (SHM) is expressed as:
E = (1/2) k A²
where:
– k is the force constant,
– A is the amplitude.
Because energy is proportional to A², if the amplitude A is doubled (2A), the total energy becomes:
E’ = (1/2) k (2A)² = 4 × (1/2) k A² = 4E
So, the total energy becomes four times its initial value.
In Simple Harmonic Motion (SHM), the displacement x and velocity v are related as: x = A sin(ωt) v = dx/dt = Aω cos(ωt) Because sin(ωt) and cos(ωt) differ by a phase of π/2 rad, the phase difference between displacement and velocity is π/2 rad. Click here for more: https://www.tiwariacademy.com/ncerRead more
In Simple Harmonic Motion (SHM), the displacement x and velocity v are related as:
x = A sin(ωt)
v = dx/dt = Aω cos(ωt)
Because sin(ωt) and cos(ωt) differ by a phase of π/2 rad, the phase difference between displacement and velocity is π/2 rad.
The time period of a simple pendulum of length l is given by
It is correctly expressed as, T = 2π √(l/g). The time period (T) of a simple pendulum of length l is expressed by the formula given below: T = 2π √(l/g) where, - l is the length of the pendulum, - g is the acceleration due to gravity. This equation implies that the time period varies as the square rRead more
It is correctly expressed as, T = 2π √(l/g).
The time period (T) of a simple pendulum of length l is expressed by the formula given below:
T = 2π √(l/g)
where,
– l is the length of the pendulum,
– g is the acceleration due to gravity.
This equation implies that the time period varies as the square root of the length and is inversely proportional to the square root of gravity.
Click here for more:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-11/physics/chapter-13/
The acceleration of a particle executing SHM is maximum
In Simple Harmonic Motion (SHM), the acceleration (a) is: a = -ω²x Here, - ω represents angular frequency, - x refers to displacement from mean position Acceleration is maximum when |x| is maximum, and this happens at the extreme positions in the motion. As x = 0 corresponds to the mean position, thRead more
In Simple Harmonic Motion (SHM), the acceleration (a) is:
a = -ω²x
Here,
– ω represents angular frequency,
– x refers to displacement from mean position
Acceleration is maximum when |x| is maximum, and this happens at the extreme positions in the motion. As x = 0 corresponds to the mean position, the acceleration is zero here.
Click here for more:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-11/physics/chapter-13/
The restoring force in SHM is given by
The restoring force F in Simple Harmonic Motion (SHM) obeys Hooke's Law, which is represented by the expression: F = -kx Here, the meanings of the parameters are as follows: - k is the force constant (spring constant), - x is the displacement from the equilibrium position. The negative sign shows thRead more
The restoring force F in Simple Harmonic Motion (SHM) obeys Hooke’s Law, which is represented by the expression:
F = -kx
Here, the meanings of the parameters are as follows:
– k is the force constant (spring constant),
– x is the displacement from the equilibrium position.
The negative sign shows that it always acts against the displacement in an attempt to bring the particle back to its equilibrium position.
Click here for more:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-11/physics/chapter-13/
If the amplitude of a simple harmonic motion is doubled, the total energy becomes
The total energy (E) in Simple Harmonic Motion (SHM) is expressed as: E = (1/2) k A² where: - k is the force constant, - A is the amplitude. Because energy is proportional to A², if the amplitude A is doubled (2A), the total energy becomes: E' = (1/2) k (2A)² = 4 × (1/2) k A² = 4E So, the total enerRead more
The total energy (E) in Simple Harmonic Motion (SHM) is expressed as:
E = (1/2) k A²
where:
– k is the force constant,
– A is the amplitude.
Because energy is proportional to A², if the amplitude A is doubled (2A), the total energy becomes:
E’ = (1/2) k (2A)² = 4 × (1/2) k A² = 4E
So, the total energy becomes four times its initial value.
Click here for more:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-11/physics/chapter-13/
The phase difference between displacement and velocity in SHM is
In Simple Harmonic Motion (SHM), the displacement x and velocity v are related as: x = A sin(ωt) v = dx/dt = Aω cos(ωt) Because sin(ωt) and cos(ωt) differ by a phase of π/2 rad, the phase difference between displacement and velocity is π/2 rad. Click here for more: https://www.tiwariacademy.com/ncerRead more
In Simple Harmonic Motion (SHM), the displacement x and velocity v are related as:
x = A sin(ωt)
v = dx/dt = Aω cos(ωt)
Because sin(ωt) and cos(ωt) differ by a phase of π/2 rad, the phase difference between displacement and velocity is π/2 rad.
Click here for more:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-11/physics/chapter-13/