A regular hexagon has 6 equal sides. The perimeter (P) of a hexagon is given by: P = 6 × side length Given that P = 24 cm, we solve for the side length: side length = 24 cm / 6 = 4 cm Thus, each side of the hexagon is 4 cm. Click here for more: https://www.tiwariacademy.com/ncert-solutions/class-11/Read more
A regular hexagon has 6 equal sides. The perimeter (P) of a hexagon is given by:
P = 6 × side length
Given that P = 24 cm, we solve for the side length:
side length = 24 cm / 6 = 4 cm
Thus, each side of the hexagon is 4 cm.
The area (A) of a rectangle is given by the formula: A = l × b where: - l = 10 m (length), - b = 5 m (breadth). Substituting the values: A = 10 × 5 = 50 sq. m Thus, the area of the rectangle is 50 square meters. Click here for more: https://www.tiwariacademy.com/ncert-solutions/class-11/physics/chapRead more
The area (A) of a rectangle is given by the formula:
A = l × b
where:
– l = 10 m (length),
– b = 5 m (breadth).
Substituting the values:
A = 10 × 5 = 50 sq. m
Thus, the area of the rectangle is 50 square meters.
The perimeter (P) of a square is given by: P = 4 × side length Given that P = 36 cm, we solve for the side length: side length = 36 cm / 4 = 9 cm Thus, each side of the square will be 9 cm Click here for more: https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-6/
The perimeter (P) of a square is given by:
P = 4 × side length
Given that P = 36 cm, we solve for the side length:
side length = 36 cm / 4 = 9 cm
To find the interval for which the function y = x³ + 6x² + 6 is increasing, we will look at its derivative. Compute the derivative of the function: y'(x) = d/dx(x³ + 6x² + 6) = 3x² + 12x Determine where the derivative is positive, so the function is increasing: y'(x) > 0 3x² + 12x > 0 Factor tRead more
To find the interval for which the function y = x³ + 6x² + 6 is increasing, we will look at its derivative.
Compute the derivative of the function:
y'(x) = d/dx(x³ + 6x² + 6) = 3x² + 12x
Determine where the derivative is positive, so the function is increasing:
y'(x) > 0
3x² + 12x > 0
Factor the expression:
3x(x + 4) > 0
This inequality holds when x 0. Thus, the function is increasing in the intervals (-∞, -4) and (0, ∞).
Conclusion:
The correct intervals where the function is increasing are (-∞, 0) U (4, ∞).
We are given: cos⁻¹ α + cos⁻¹ β + cos⁻¹ γ = 3π Step 1: Using the property of inverse cosine The principal value range of cos⁻¹ x is [0, π]. For the sum of three inverse cosine terms to equal 3π, each term must be equal to π. This means: cos⁻¹ α = π, cos⁻¹ β = π, cos⁻¹ γ = π Step 2: Find the values oRead more
We are given:
cos⁻¹ α + cos⁻¹ β + cos⁻¹ γ = 3π
Step 1: Using the property of inverse cosine
The principal value range of cos⁻¹ x is [0, π].
For the sum of three inverse cosine terms to equal 3π, each term must be equal to π. This means:
cos⁻¹ α = π, cos⁻¹ β = π, cos⁻¹ γ = π
Step 2: Find the values of α, β, and γ
When cos⁻¹ α = π, then cos π = -1, so:
α = -1, β = -1, γ = -1
Step 3: Substitute into the expression
We are given to calculate:
α(β + γ) + β(γ + α) + γ(α + β)
A hexagon with a total perimeter of 24 cm has each side equal to:
A regular hexagon has 6 equal sides. The perimeter (P) of a hexagon is given by: P = 6 × side length Given that P = 24 cm, we solve for the side length: side length = 24 cm / 6 = 4 cm Thus, each side of the hexagon is 4 cm. Click here for more: https://www.tiwariacademy.com/ncert-solutions/class-11/Read more
A regular hexagon has 6 equal sides. The perimeter (P) of a hexagon is given by:
P = 6 × side length
Given that P = 24 cm, we solve for the side length:
side length = 24 cm / 6 = 4 cm
Thus, each side of the hexagon is 4 cm.
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The area of a rectangle with 𝑙 = 10𝑚 and b=5m is:
The area (A) of a rectangle is given by the formula: A = l × b where: - l = 10 m (length), - b = 5 m (breadth). Substituting the values: A = 10 × 5 = 50 sq. m Thus, the area of the rectangle is 50 square meters. Click here for more: https://www.tiwariacademy.com/ncert-solutions/class-11/physics/chapRead more
The area (A) of a rectangle is given by the formula:
A = l × b
where:
– l = 10 m (length),
– b = 5 m (breadth).
Substituting the values:
A = 10 × 5 = 50 sq. m
Thus, the area of the rectangle is 50 square meters.
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See lesshttps://www.tiwariacademy.com/ncert-solutions/class-11/physics/chapter-13/
A piece of string is 36 cm long. Forming a square, each side will be:
The perimeter (P) of a square is given by: P = 4 × side length Given that P = 36 cm, we solve for the side length: side length = 36 cm / 4 = 9 cm Thus, each side of the square will be 9 cm Click here for more: https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-6/
The perimeter (P) of a square is given by:
P = 4 × side length
Given that P = 36 cm, we solve for the side length:
side length = 36 cm / 4 = 9 cm
Thus, each side of the square will be 9 cm
Click here for more:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-6/
The interval, in which function y = x³ + 6x² + 6 is increasing is
To find the interval for which the function y = x³ + 6x² + 6 is increasing, we will look at its derivative. Compute the derivative of the function: y'(x) = d/dx(x³ + 6x² + 6) = 3x² + 12x Determine where the derivative is positive, so the function is increasing: y'(x) > 0 3x² + 12x > 0 Factor tRead more
To find the interval for which the function y = x³ + 6x² + 6 is increasing, we will look at its derivative.
Compute the derivative of the function:
y'(x) = d/dx(x³ + 6x² + 6) = 3x² + 12x
Determine where the derivative is positive, so the function is increasing:
y'(x) > 0
3x² + 12x > 0
Factor the expression:
3x(x + 4) > 0
This inequality holds when x 0. Thus, the function is increasing in the intervals (-∞, -4) and (0, ∞).
Conclusion:
The correct intervals where the function is increasing are (-∞, 0) U (4, ∞).
Click here for more:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-12/maths/#chapter-6
If cos⁻¹ α + cos⁻¹ β + cos⁻¹ γ = 3π, then α(β + γ) + β(γ + α) + γ(α + β) is equal to
We are given: cos⁻¹ α + cos⁻¹ β + cos⁻¹ γ = 3π Step 1: Using the property of inverse cosine The principal value range of cos⁻¹ x is [0, π]. For the sum of three inverse cosine terms to equal 3π, each term must be equal to π. This means: cos⁻¹ α = π, cos⁻¹ β = π, cos⁻¹ γ = π Step 2: Find the values oRead more
We are given:
cos⁻¹ α + cos⁻¹ β + cos⁻¹ γ = 3π
Step 1: Using the property of inverse cosine
The principal value range of cos⁻¹ x is [0, π].
For the sum of three inverse cosine terms to equal 3π, each term must be equal to π. This means:
cos⁻¹ α = π, cos⁻¹ β = π, cos⁻¹ γ = π
Step 2: Find the values of α, β, and γ
When cos⁻¹ α = π, then cos π = -1, so:
α = -1, β = -1, γ = -1
Step 3: Substitute into the expression
We are given to calculate:
α(β + γ) + β(γ + α) + γ(α + β)
Replace α = -1, β = -1, and γ = -1:
(-1)((-1) + (-1)) + (-1)((-1) + (-1)) + (-1)((-1) + (-1))
Simplify each term:
(-1)(-2) + (-1)(-2) + (-1)(-2) = 2 + 2 + 2 = 6
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