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(a) 25⁰C = 25 + 273 = 298 K (b) 373⁰C = 373 + 273 = 646 K For more answers visit to website: https://www.tiwariacademy.com/ncert-solutions/class-9/science/chapter-1/
(a) 25⁰C = 25 + 273 = 298 K (b) 373⁰C = 373 + 273 = 646 K
For more answers visit to website: https://www.tiwariacademy.com/ncert-solutions/class-9/science/chapter-1/
(a) 300 K = 300 – 273 = 27 ⁰C (b) 573 K = 573 – 273 = 300 ⁰C For more answers visit to website: https://www.tiwariacademy.com/ncert-solutions/class-9/science/chapter-1/
(a) 300 K = 300 – 273 = 27 ⁰C (b) 573 K = 573 – 273 = 300 ⁰C
Convert the following temperatures to the Kelvin scale.
(a) 25⁰C = 25 + 273 = 298 K (b) 373⁰C = 373 + 273 = 646 K For more answers visit to website: https://www.tiwariacademy.com/ncert-solutions/class-9/science/chapter-1/
(a) 25⁰C = 25 + 273 = 298 K
(b) 373⁰C = 373 + 273 = 646 K
For more answers visit to website:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-9/science/chapter-1/
Convert the following temperatures to the Celsius scale.
(a) 300 K = 300 – 273 = 27 ⁰C (b) 573 K = 573 – 273 = 300 ⁰C For more answers visit to website: https://www.tiwariacademy.com/ncert-solutions/class-9/science/chapter-1/
(a) 300 K = 300 – 273 = 27 ⁰C
(b) 573 K = 573 – 273 = 300 ⁰C
For more answers visit to website:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-9/science/chapter-1/