Atomic mass of Na = 23u (Given) Then, gram atomic mass of Na = 23g Now, 23g of Na contains = 6.022×10²³ number of atoms Thus, 100g of Na contains = 6.022×10²³ ×100/23 number of atoms = 2.6182 × 10²⁴ number of atoms Again, atomic mass of Fe = 56u (Given) Then, gram atomic mass of Fe = 56g Now, 56 g oRead more
Atomic mass of Na = 23u (Given)
Then, gram atomic mass of Na = 23g
Now, 23g of Na contains = 6.022×10²³ number of atoms
Thus, 100g of Na contains = 6.022×10²³ ×100/23 number of atoms
= 2.6182 × 10²⁴ number of atoms
Again, atomic mass of Fe = 56u (Given)
Then, gram atomic mass of Fe = 56g
Now, 56 g of Fe contains = 6.022×10²³ number of atoms
Thus, 100 g of Fe
6.022×10²³ ×100/56 number of atoms
= 1.0753 × 10²⁴number of atoms
Therefore, 100 grams of sodium contain more number of atoms than 100 grams of iron.
One mole of carbon atoms weighs 12g (Given) i.e., mass of 1 mole of carbon atoms = 12g Then, mass of 6.022× 10²³ number of carbon atoms = 12g Therefore, mass of 1 atom of carbon = 12/6.022×10²³ g = 1.9926 × 10⁻²³ g For more answers visit to website: https://www.tiwariacademy.com/ncert-solutions/clasRead more
One mole of carbon atoms weighs 12g (Given)
i.e., mass of 1 mole of carbon atoms = 12g
Then, mass of 6.022× 10²³ number of carbon atoms = 12g
Therefore, mass of 1 atom of carbon = 12/6.022×10²³ g
= 1.9926 × 10⁻²³ g
Formula unit mass of ZnO = Atomic mass of Zn + Atomic mass of O = 65 + 16 = 81u Formula unit mass of Na₂O = 2 × Atomic mass of Na + Atomic mass of O = 2 × 23 + 16 = 62u Formula unit mass of K₂CO₃ = 2 × Atomic mass of K + Atomic mass of C + 3 × Atomic mass of O = 2 × 39 + 12 + 3 × 16 = 138u For moreRead more
Formula unit mass of ZnO = Atomic mass of Zn + Atomic mass of O
= 65 + 16 = 81u
Formula unit mass of Na₂O = 2 × Atomic mass of Na + Atomic mass of O
= 2 × 23 + 16 = 62u
Formula unit mass of K₂CO₃
= 2 × Atomic mass of K + Atomic mass of C + 3 × Atomic mass of O
= 2 × 39 + 12 + 3 × 16 = 138u
Molecular mass of H₂ = 2 × Atomic mass of H = 2 × 1 = 2u Molecular mass of O₂ = 2 × Atomic mass of O = 2 × 16 = 32u Molecular mass of Cl₂ = 2 × Atomic mass of Cl = 2 × 35.5 = 71u Molecular mass of CO₂ = Atomic mass of C + 2 × Atomic mass of O = 12 + 2 × 16 = 44u Molecular mass of CH₄ = Atomic mass oRead more
Molecular mass of H₂ = 2 × Atomic mass of H
= 2 × 1 = 2u
Molecular mass of O₂ = 2 × Atomic mass of O
= 2 × 16 = 32u
Molecular mass of Cl₂ = 2 × Atomic mass of Cl
= 2 × 35.5 = 71u
Molecular mass of CO₂ = Atomic mass of C + 2 × Atomic mass of O
= 12 + 2 × 16 = 44u
Molecular mass of CH₄ = Atomic mass of C + 4 × Atomic mass of H
= 12 + 4 × 1 = 16u
Molecular mass of C₂H₆ = 2 × Atomic mass of C + 6 × Atomic mass of H
= 2 × 12 + 6 × 1 = 30u
Molecular mass of C₂H₄ = 2 × Atomic mass of C + 4 × Atomic mass of H
= 2 × 12 + 4 × 1 = 28u
Molecular mass of NH₃ = Atomic mass of N + 3 × Atomic mass of H
= 14 + 3 × 1 =17u
Molecular mass of CH₃OH Atomic mass of C+4 ×Atomic mass of H+Atomic mass of O
= 12 + 4 × 1 + 16 = 32u
(i) In an H₂S molecule, three atoms are present; two of hydrogen and one of sulphur. (ii) In a PO₄₃- ion, five atoms are present; one of phosphorus and four of oxygen. For more answers visit to website: https://www.tiwariacademy.com/ncert-solutions/class-9/science/chapter-3/
(i) In an H₂S molecule, three atoms are present; two of hydrogen and one of sulphur.
(ii) In a PO₄₃- ion, five atoms are present; one of phosphorus and four of oxygen.
Which has more number of atoms, 100 grams of sodium or 100 grams of iron (given, atomic mass of Na = 23 u, Fe = 56 u)?
Atomic mass of Na = 23u (Given) Then, gram atomic mass of Na = 23g Now, 23g of Na contains = 6.022×10²³ number of atoms Thus, 100g of Na contains = 6.022×10²³ ×100/23 number of atoms = 2.6182 × 10²⁴ number of atoms Again, atomic mass of Fe = 56u (Given) Then, gram atomic mass of Fe = 56g Now, 56 g oRead more
Atomic mass of Na = 23u (Given)
Then, gram atomic mass of Na = 23g
Now, 23g of Na contains = 6.022×10²³ number of atoms
Thus, 100g of Na contains = 6.022×10²³ ×100/23 number of atoms
= 2.6182 × 10²⁴ number of atoms
Again, atomic mass of Fe = 56u (Given)
Then, gram atomic mass of Fe = 56g
Now, 56 g of Fe contains = 6.022×10²³ number of atoms
Thus, 100 g of Fe
6.022×10²³ ×100/56 number of atoms
= 1.0753 × 10²⁴number of atoms
Therefore, 100 grams of sodium contain more number of atoms than 100 grams of iron.
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If one mole of carbon atoms weighs 12 grams, what is the mass (in gram) of 1 atom of carbon?
One mole of carbon atoms weighs 12g (Given) i.e., mass of 1 mole of carbon atoms = 12g Then, mass of 6.022× 10²³ number of carbon atoms = 12g Therefore, mass of 1 atom of carbon = 12/6.022×10²³ g = 1.9926 × 10⁻²³ g For more answers visit to website: https://www.tiwariacademy.com/ncert-solutions/clasRead more
One mole of carbon atoms weighs 12g (Given)
i.e., mass of 1 mole of carbon atoms = 12g
Then, mass of 6.022× 10²³ number of carbon atoms = 12g
Therefore, mass of 1 atom of carbon = 12/6.022×10²³ g
= 1.9926 × 10⁻²³ g
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Calculate the formula unit masses of ZnO, Na₂O, K₂CO₃, given atomic masses of Zn = 65 u, Na = 23 u, K = 39 u, C = 12 u, and O = 16 u.
Formula unit mass of ZnO = Atomic mass of Zn + Atomic mass of O = 65 + 16 = 81u Formula unit mass of Na₂O = 2 × Atomic mass of Na + Atomic mass of O = 2 × 23 + 16 = 62u Formula unit mass of K₂CO₃ = 2 × Atomic mass of K + Atomic mass of C + 3 × Atomic mass of O = 2 × 39 + 12 + 3 × 16 = 138u For moreRead more
Formula unit mass of ZnO = Atomic mass of Zn + Atomic mass of O
= 65 + 16 = 81u
Formula unit mass of Na₂O = 2 × Atomic mass of Na + Atomic mass of O
= 2 × 23 + 16 = 62u
Formula unit mass of K₂CO₃
= 2 × Atomic mass of K + Atomic mass of C + 3 × Atomic mass of O
= 2 × 39 + 12 + 3 × 16 = 138u
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Calculate the molecular masses of : H₂, O₂, Cl₂, CO₂, CH₄, C₂H₆, C₂H₄, NH₃, CH₃OH.
Molecular mass of H₂ = 2 × Atomic mass of H = 2 × 1 = 2u Molecular mass of O₂ = 2 × Atomic mass of O = 2 × 16 = 32u Molecular mass of Cl₂ = 2 × Atomic mass of Cl = 2 × 35.5 = 71u Molecular mass of CO₂ = Atomic mass of C + 2 × Atomic mass of O = 12 + 2 × 16 = 44u Molecular mass of CH₄ = Atomic mass oRead more
Molecular mass of H₂ = 2 × Atomic mass of H
= 2 × 1 = 2u
Molecular mass of O₂ = 2 × Atomic mass of O
= 2 × 16 = 32u
Molecular mass of Cl₂ = 2 × Atomic mass of Cl
= 2 × 35.5 = 71u
Molecular mass of CO₂ = Atomic mass of C + 2 × Atomic mass of O
= 12 + 2 × 16 = 44u
Molecular mass of CH₄ = Atomic mass of C + 4 × Atomic mass of H
= 12 + 4 × 1 = 16u
Molecular mass of C₂H₆ = 2 × Atomic mass of C + 6 × Atomic mass of H
= 2 × 12 + 6 × 1 = 30u
Molecular mass of C₂H₄ = 2 × Atomic mass of C + 4 × Atomic mass of H
= 2 × 12 + 4 × 1 = 28u
Molecular mass of NH₃ = Atomic mass of N + 3 × Atomic mass of H
= 14 + 3 × 1 =17u
Molecular mass of CH₃OH Atomic mass of C+4 ×Atomic mass of H+Atomic mass of O
= 12 + 4 × 1 + 16 = 32u
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How many atoms are present in a (i) H₂S molecule and (ii) PO₄³⁻ ion?
(i) In an H₂S molecule, three atoms are present; two of hydrogen and one of sulphur. (ii) In a PO₄₃- ion, five atoms are present; one of phosphorus and four of oxygen. For more answers visit to website: https://www.tiwariacademy.com/ncert-solutions/class-9/science/chapter-3/
(i) In an H₂S molecule, three atoms are present; two of hydrogen and one of sulphur.
(ii) In a PO₄₃- ion, five atoms are present; one of phosphorus and four of oxygen.
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