The correct sequence is 1, 3, 2. Step 1 uses sublimation to separate naphthalene because it changes directly into vapour on heating. The remaining sand and common salt are treated with water to dissolve the salt. Step 3 uses filtration to separate the insoluble sand. Finally, step 2 uses evaporationRead more
The correct sequence is 1, 3, 2. Step 1 uses sublimation to separate naphthalene because it changes directly into vapour on heating. The remaining sand and common salt are treated with water to dissolve the salt. Step 3 uses filtration to separate the insoluble sand. Finally, step 2 uses evaporation to remove water and obtain common salt as the remaining solid.
For more NCERT Solutions of Class 9 Science Exploration Chapter 5 Exploring Mixtures and their Separation Question Answer (2026-27)
For the motorbike, initial velocity u = 28 m s⁻¹, final velocity v = 0 and distance s = 98 m. Using v² = u² + 2as: 0 = 28² + 2(a)(98), giving a = −4 m s⁻². Using v = u + at: 0 = 28 − 4t, so t = 7 s. Thus, acceleration is −4 m s⁻² and stopping time is 7 s. For more NCERT Solutions of Class 9 SRead more
For the motorbike, initial velocity u = 28 m s⁻¹, final velocity v = 0 and distance s = 98 m. Using v² = u² + 2as:
0 = 28² + 2(a)(98), giving a = −4 m s⁻².
Using v = u + at: 0 = 28 − 4t, so t = 7 s. Thus, acceleration is −4 m s⁻² and stopping time is 7 s.
For more NCERT Solutions of Class 9 Science Exploration Chapter 4 Describing Motion Around Us Question Answer (2026-27)
The initial velocity of the car is u = 0 m s⁻¹, final velocity is v = 24 m s⁻¹ and time is t = 6 s. Average acceleration = (v − u)/t = (24 − 0)/6 = 4 m s⁻². Distance travelled = average velocity × time = [(u + v)/2] × t = [(0 + 24)/2] × 6 = 72 m. For more NCERT Solutions of Class 9 Science ExRead more
The initial velocity of the car is u = 0 m s⁻¹, final velocity is v = 24 m s⁻¹ and time is t = 6 s.
Average acceleration = (v − u)/t = (24 − 0)/6 = 4 m s⁻².
Distance travelled = average velocity × time = [(u + v)/2] × t = [(0 + 24)/2] × 6 = 72 m.
For more NCERT Solutions of Class 9 Science Exploration Chapter 4 Describing Motion Around Us Question Answer (2026-27)
Yes, it is possible for the scooter to be accelerating even when its speedometer reading remains constant. Acceleration is the rate of change of velocity and velocity depends on both speed and direction. Therefore, if the scooter moves with constant speed but continuously changes its direction, itsRead more
Yes, it is possible for the scooter to be accelerating even when its speedometer reading remains constant. Acceleration is the rate of change of velocity and velocity depends on both speed and direction. Therefore, if the scooter moves with constant speed but continuously changes its direction, its velocity changes and the scooter is accelerating. For example, this occurs when the scooter moves along a circular path.
For more NCERT Solutions of Class 9 Science Exploration Chapter 4 Describing Motion Around Us Question Answer (2026-27)
(i) The magnitude of average velocity is equal to average speed when an object travels along a straight-line path without changing its direction, so distance travelled equals the magnitude of displacement. (ii) The magnitude of average velocity can be zero when the object returns to its starting poiRead more
(i) The magnitude of average velocity is equal to average speed when an object travels along a straight-line path without changing its direction, so distance travelled equals the magnitude of displacement. (ii) The magnitude of average velocity can be zero when the object returns to its starting point. Its displacement is then zero, but its total distance travelled is not zero, so its average speed remains non-zero.
For more NCERT Solutions of Class 9 Science Exploration Chapter 4 Describing Motion Around Us Question Answer (2026-27)
You are given a mixture of sand, common salt and naphthalene (Fig. 5.25a). The Fig. 5.25b depicts various steps used to separate the components of this mixture. Identify and write down the correct sequence of separation techniques.
The correct sequence is 1, 3, 2. Step 1 uses sublimation to separate naphthalene because it changes directly into vapour on heating. The remaining sand and common salt are treated with water to dissolve the salt. Step 3 uses filtration to separate the insoluble sand. Finally, step 2 uses evaporationRead more
The correct sequence is 1, 3, 2. Step 1 uses sublimation to separate naphthalene because it changes directly into vapour on heating. The remaining sand and common salt are treated with water to dissolve the salt. Step 3 uses filtration to separate the insoluble sand. Finally, step 2 uses evaporation to remove water and obtain common salt as the remaining solid.
For more NCERT Solutions of Class 9 Science Exploration Chapter 5 Exploring Mixtures and their Separation Question Answer (2026-27)
https://www.tiwariacademy.com/ncert-solutions/class-9/science/exploration-chapter-5/
See lessA motorbike moving with initial velocity 28 m s⁻¹ and constant acceleration stops after travelling 98 m. Find the acceleration of the motorbike and the time taken to come to a stop.
For the motorbike, initial velocity u = 28 m s⁻¹, final velocity v = 0 and distance s = 98 m. Using v² = u² + 2as: 0 = 28² + 2(a)(98), giving a = −4 m s⁻². Using v = u + at: 0 = 28 − 4t, so t = 7 s. Thus, acceleration is −4 m s⁻² and stopping time is 7 s. For more NCERT Solutions of Class 9 SRead more
For the motorbike, initial velocity u = 28 m s⁻¹, final velocity v = 0 and distance s = 98 m. Using v² = u² + 2as:
0 = 28² + 2(a)(98), giving a = −4 m s⁻².
Using v = u + at: 0 = 28 − 4t, so t = 7 s. Thus, acceleration is −4 m s⁻² and stopping time is 7 s.
For more NCERT Solutions of Class 9 Science Exploration Chapter 4 Describing Motion Around Us Question Answer (2026-27)
https://www.tiwariacademy.com/ncert-solutions/class-9/science/exploration-chapter-4/
See lessA car starts from rest and its velocity reaches 24 m s⁻¹ in 6 s. Find the average acceleration and the distance travelled in these 6 s.
The initial velocity of the car is u = 0 m s⁻¹, final velocity is v = 24 m s⁻¹ and time is t = 6 s. Average acceleration = (v − u)/t = (24 − 0)/6 = 4 m s⁻². Distance travelled = average velocity × time = [(u + v)/2] × t = [(0 + 24)/2] × 6 = 72 m. For more NCERT Solutions of Class 9 Science ExRead more
The initial velocity of the car is u = 0 m s⁻¹, final velocity is v = 24 m s⁻¹ and time is t = 6 s.
Average acceleration = (v − u)/t = (24 − 0)/6 = 4 m s⁻².
Distance travelled = average velocity × time = [(u + v)/2] × t = [(0 + 24)/2] × 6 = 72 m.
For more NCERT Solutions of Class 9 Science Exploration Chapter 4 Describing Motion Around Us Question Answer (2026-27)
https://www.tiwariacademy.com/ncert-solutions/class-9/science/exploration-chapter-4/
See lessA girl is riding her scooter and finds that its speedometer reading is constant. Is it possible for her scooter to be accelerating and if so, how?
Yes, it is possible for the scooter to be accelerating even when its speedometer reading remains constant. Acceleration is the rate of change of velocity and velocity depends on both speed and direction. Therefore, if the scooter moves with constant speed but continuously changes its direction, itsRead more
Yes, it is possible for the scooter to be accelerating even when its speedometer reading remains constant. Acceleration is the rate of change of velocity and velocity depends on both speed and direction. Therefore, if the scooter moves with constant speed but continuously changes its direction, its velocity changes and the scooter is accelerating. For example, this occurs when the scooter moves along a circular path.
For more NCERT Solutions of Class 9 Science Exploration Chapter 4 Describing Motion Around Us Question Answer (2026-27)
https://www.tiwariacademy.com/ncert-solutions/class-9/science/exploration-chapter-4/
See lessUnder what condition(s) is the: (i) magnitude of average velocity of an object equal to its average speed? (ii) magnitude of average velocity of an object zero while its average speed is not zero?
(i) The magnitude of average velocity is equal to average speed when an object travels along a straight-line path without changing its direction, so distance travelled equals the magnitude of displacement. (ii) The magnitude of average velocity can be zero when the object returns to its starting poiRead more
(i) The magnitude of average velocity is equal to average speed when an object travels along a straight-line path without changing its direction, so distance travelled equals the magnitude of displacement.
(ii) The magnitude of average velocity can be zero when the object returns to its starting point. Its displacement is then zero, but its total distance travelled is not zero, so its average speed remains non-zero.
For more NCERT Solutions of Class 9 Science Exploration Chapter 4 Describing Motion Around Us Question Answer (2026-27)
https://www.tiwariacademy.com/ncert-solutions/class-9/science/exploration-chapter-4/
See less