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The taxi charges in a city consist of a fixed charge together with the charge for the distance covered for every km. For a distance of 10 km, the total amount paid is ₹155 and for a journey of 15 km, the total amount paid is ₹220. What is the fixed charge and the charge per km? How much does a person have to pay for travelling a distance of 25 km?

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Let fixed charge be ₹x and per km charge ₹y. Then x + 10y = 155 and x + 15y = 220. Subtracting gives 5y = 65, so y = 13 and x = 25. For 25 km, cost is 25 + 25(13) = ₹350.

class 9 maths ganita manjari part 2 chapter 13 question answer
Ganita Manjari Part 2 chapter 13 Two Variables, One Line solutions

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  1. Let the fixed charge be ₹x and running charge be ₹y per kilometre. The equations are x + 10y = 155 and x + 15y = 220. Subtracting the first equation from the second eliminates x, giving 5y = 65, which means y = 13. Substituting into the first equation yields x + 130 = 155, so x = 25. For 25 km, total fare is x + 25y = 25 + 25(13) = ₹350.

     

    For more NCERT Solutions of Class 9 Maths Ganita Manjari Part 2 Chapter 13 Two Variables, One Line Question Answer (2026-27)

    https://www.tiwariacademy.com/ncert-solutions/class-9/maths/ganita-manjari-chapter-13/

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