Emf of the battery, E = 12 V Internal resistance of the battery, r = 0.4 Ω Maximum current drawn from the battery = I According to Ohm's law, E = Ir Therefore I = E/r =12/0.4 = 30 A The maximum current drawn from the given battery is 30 A.
Emf of the battery, E = 12 V
Internal resistance of the battery, r = 0.4 Ω
Maximum current drawn from the battery = I
According to Ohm’s law, E = Ir
Therefore I = E/r =12/0.4
= 30 A
The maximum current drawn from the given battery is 30 A.
The storage battery of a car has an emf of 12 V. If the internal resistance of the battery is 0.4 Ω, what is the maximum current that can be drawn from the battery?
Emf of the battery, E = 12 V Internal resistance of the battery, r = 0.4 Ω Maximum current drawn from the battery = I According to Ohm's law, E = Ir Therefore I = E/r =12/0.4 = 30 A The maximum current drawn from the given battery is 30 A.
Emf of the battery, E = 12 V
Internal resistance of the battery, r = 0.4 Ω
Maximum current drawn from the battery = I
According to Ohm’s law, E = Ir
Therefore I = E/r =12/0.4
= 30 A
The maximum current drawn from the given battery is 30 A.
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