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A cone has a height of 15 cm. If its volume is 1570 cm³, find the radius of the base.
Given height h = 15 cm and volume V = 1570 cm³. The volume of a cone is given by V = (1/3)πr²h. Substituting the given values using π ≈ 3.14, we get 1570 = (1/3) × 3.14 × r² × 15. This simplifies to 15.7r² = 1570, giving r² = 100. Taking the square root, the base radius is r = 10 cm. For moreRead more
Given height h = 15 cm and volume V = 1570 cm³. The volume of a cone is given by V = (1/3)πr²h. Substituting the given values using π ≈ 3.14, we get 1570 = (1/3) × 3.14 × r² × 15. This simplifies to 15.7r² = 1570, giving r² = 100. Taking the square root, the base radius is r = 10 cm.
For more NCERT Solutions of Class 9 Maths Ganita Manjari Part 2 Chapter 14 Math of Space: Surface Area and Volume Question Answer (2026-27)
https://www.tiwariacademy.com/ncert-solutions/class-9/maths/ganita-manjari-chapter-14/
See lessThe height of a cone is 16 cm and its base radius is 12 cm. Find the curved surface area and the total surface area of the cone.
With height h = 16 cm and radius r = 12 cm, the slant height is l = √(h² + r²) = √(256 + 144) = √400 = 20 cm. Using π ≈ 3.14, curved surface area is CSA = πrl = 3.14 × 12 × 20 = 753.6 cm². The total surface area is TSA = πr(l + r) = 3.14 × 12 × (20 + 12) = 37.68 × 32 = 1205.76 cm². For more NRead more
With height h = 16 cm and radius r = 12 cm, the slant height is l = √(h² + r²) = √(256 + 144) = √400 = 20 cm. Using π ≈ 3.14, curved surface area is CSA = πrl = 3.14 × 12 × 20 = 753.6 cm². The total surface area is TSA = πr(l + r) = 3.14 × 12 × (20 + 12) = 37.68 × 32 = 1205.76 cm².
For more NCERT Solutions of Class 9 Maths Ganita Manjari Part 2 Chapter 14 Math of Space: Surface Area and Volume Question Answer (2026-27)
https://www.tiwariacademy.com/ncert-solutions/class-9/maths/ganita-manjari-chapter-14/
See lessFind the curved surface area of a right circular cone whose slant height is 10 cm and base radius is 7 cm.
The base radius of the right circular cone is given as r = 7 cm and its slant height is l = 10 cm. The curved surface area is given by the formula CSA = πrl. Substituting the given values using π ≈ 22/7, we calculate CSA = (22/7) × 7 × 10 = 220 cm². For more NCERT Solutions of Class 9 Maths GRead more
The base radius of the right circular cone is given as r = 7 cm and its slant height is l = 10 cm. The curved surface area is given by the formula CSA = πrl. Substituting the given values using π ≈ 22/7, we calculate CSA = (22/7) × 7 × 10 = 220 cm².
For more NCERT Solutions of Class 9 Maths Ganita Manjari Part 2 Chapter 14 Math of Space: Surface Area and Volume Question Answer (2026-27)
https://www.tiwariacademy.com/ncert-solutions/class-9/maths/ganita-manjari-chapter-14/
See lessFind the total surface area of a cone, if its slant height is 21 m and diameter of its base is 24 m.
Given the diameter is 24 m, the base radius r = 12 m and slant height l = 21 m. The formula for total surface area of a cone is TSA = πr(l + r). Substituting the given values with π ≈ 22/7, we get TSA = (22/7) × 12 × (21 + 12) = (22/7) × 12 × 33 = 8712/7 ≈ 1244.57 m². For more NCERT SolutionsRead more
Given the diameter is 24 m, the base radius r = 12 m and slant height l = 21 m. The formula for total surface area of a cone is TSA = πr(l + r). Substituting the given values with π ≈ 22/7, we get TSA = (22/7) × 12 × (21 + 12) = (22/7) × 12 × 33 = 8712/7 ≈ 1244.57 m².
For more NCERT Solutions of Class 9 Maths Ganita Manjari Part 2 Chapter 14 Math of Space: Surface Area and Volume Question Answer (2026-27)
https://www.tiwariacademy.com/ncert-solutions/class-9/maths/ganita-manjari-chapter-14/
See lessA solid metallic cube of side 12 cm is melted and recast into solid cylindrical rods, each having radius 2 cm and height 12 cm. Find: (i) The volume of the cube. (ii) The volume of one cylindrical rod. (iii) The approximate number of complete cylindrical rods that can be formed.
(i) Volume of the cube is a³ = 12³ = 1728 cm³. (ii) Volume of one cylindrical rod is πr²h = (22/7) × 2² × 12 = (22/7) × 48 = 1056/7 ≈ 150.86 cm³. (iii) Number of complete rods is obtained by dividing total cube volume by one rod's volume: 1728 ÷ (1056/7) = (1728 × 7) / 1056 = 12096 / 1056 ≈ 11.45, wRead more
(i) Volume of the cube is a³ = 12³ = 1728 cm³.
(ii) Volume of one cylindrical rod is πr²h = (22/7) × 2² × 12 = (22/7) × 48 = 1056/7 ≈ 150.86 cm³.
(iii) Number of complete rods is obtained by dividing total cube volume by one rod’s volume: 1728 ÷ (1056/7) = (1728 × 7) / 1056 = 12096 / 1056 ≈ 11.45, which gives 11 complete rods.
For more NCERT Solutions of Class 9 Maths Ganita Manjari Part 2 Chapter 14 Math of Space: Surface Area and Volume Question Answer (2026-27)
https://www.tiwariacademy.com/ncert-solutions/class-9/maths/ganita-manjari-chapter-14/
See less