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  1. Let original radius and height be r and h, so initial volume is V = πr²h. The increased radius is r' = 1.1r. Since the volume remains unchanged, π(1.1r)²h' = πr²h, giving 1.21h' = h or h' = h / 1.21. The percentage decrease in height is x = [(h − h') / h] × 100 = [1 − (1 / 1.21)] × 100 = 2100/121% ≈Read more

    Let original radius and height be r and h, so initial volume is V = πr²h. The increased radius is r’ = 1.1r. Since the volume remains unchanged, π(1.1r)²h’ = πr²h, giving 1.21h’ = h or h’ = h / 1.21. The percentage decrease in height is x = [(h − h’) / h] × 100 = [1 − (1 / 1.21)] × 100 = 2100/121% ≈ 17.36%.

     

    For more NCERT Solutions of Class 9 Maths Ganita Manjari Part 2 Chapter 14 Math of Space: Surface Area and Volume Question Answer (2026-27)

    https://www.tiwariacademy.com/ncert-solutions/class-9/maths/ganita-manjari-chapter-14/

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  2. For scenario (d), evaluate hospital experience using doctor care (weight 4), cleanliness (weight 3) and wait time (weight 2). Gather 1-to-5 ratings from ten respondents and calculate each person's weighted score using formula Σ(wᵢxᵢ) / Σwᵢ. Display the proportion of star ratings across parameters usRead more

    For scenario (d), evaluate hospital experience using doctor care (weight 4), cleanliness (weight 3) and wait time (weight 2). Gather 1-to-5 ratings from ten respondents and calculate each person’s weighted score using formula Σ(wᵢxᵢ) / Σwᵢ. Display the proportion of star ratings across parameters using a 100% stacked bar chart, observing service strengths while noting that subjective individual expectations remain uncaptured.

     

    For more NCERT Solutions of Class 9 Maths Ganita Manjari Part 2 Chapter 10 How Quantities Combine Understanding Data Question Answer (2026-27)

    https://www.tiwariacademy.com/ncert-solutions/class-9/maths/ganita-manjari-chapter-10/

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    • 59
  3. A simple average of the family averages is incorrect because family sizes vary. Instead, calculate the weighted average. Each student multiplies their family's average age by their total family member count to determine total family years. Sum these total years across the entire class, then divide bRead more

    A simple average of the family averages is incorrect because family sizes vary. Instead, calculate the weighted average. Each student multiplies their family’s average age by their total family member count to determine total family years. Sum these total years across the entire class, then divide by the aggregate number of people across all families combined.

     

    For more NCERT Solutions of Class 9 Maths Ganita Manjari Part 2 Chapter 10 How Quantities Combine Understanding Data Question Answer (2026-27)

    https://www.tiwariacademy.com/ncert-solutions/class-9/maths/ganita-manjari-chapter-10/

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    • 54
  4. The weighted average shifts toward the unweighted arithmetic mean. Algebraically, the new mean is Σ(wᵢ + 1)xᵢ / Σ(wᵢ + 1) = [Σwᵢxᵢ + Σxᵢ] / [Σwᵢ + n]. This expression represents a blend of the original weighted mean and the unweighted sum of values. Adding a constant flattens the relative ratio betwRead more

    The weighted average shifts toward the unweighted arithmetic mean. Algebraically, the new mean is Σ(wᵢ + 1)xᵢ / Σ(wᵢ + 1) = [Σwᵢxᵢ + Σxᵢ] / [Σwᵢ + n]. This expression represents a blend of the original weighted mean and the unweighted sum of values. Adding a constant flattens the relative ratio between weights, pulling the final average closer to the simple mean.

     

    For more NCERT Solutions of Class 9 Maths Ganita Manjari Part 2 Chapter 10 How Quantities Combine Understanding Data Question Answer (2026-27)

    https://www.tiwariacademy.com/ncert-solutions/class-9/maths/ganita-manjari-chapter-10/

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    • 52
  5. The valid possibilities are (iii), (iv) and (v). Since individual shares must sum to 100%, they cannot all decrease (i) or all increase (ii) simultaneously. If all three populations drop by the same proportion, their shares remain unchanged (iii). If they decrease at different rates, some percentageRead more

    The valid possibilities are (iii), (iv) and (v). Since individual shares must sum to 100%, they cannot all decrease (i) or all increase (ii) simultaneously. If all three populations drop by the same proportion, their shares remain unchanged (iii). If they decrease at different rates, some percentage shares will rise while others fall, making statements (iv) and (v) fully attainable.

     

    For more NCERT Solutions of Class 9 Maths Ganita Manjari Part 2 Chapter 10 How Quantities Combine Understanding Data Question Answer (2026-27)

    https://www.tiwariacademy.com/ncert-solutions/class-9/maths/ganita-manjari-chapter-10/

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    • 51