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Piyush365
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Asked: 2026-10-05T09:31:29+00:00 In:

A solid metallic cube of side 12 cm is melted and recast into solid cylindrical rods, each having radius 2 cm and height 12 cm. Find: (i) The volume of the cube. (ii) The volume of one cylindrical rod. (iii) The approximate number of complete cylindrical rods that can be formed.

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(i) Cube volume is 12³ = 1728 cm³.
(ii) Rod volume is (22/7) × 2² × 12 = 1056/7 ≈ 150.86 cm³.
(iii) Number of complete rods is 1728 ÷ (1056/7) = 11.45, giving 11 complete rods.

Class 9 Chapter 14 Math of Space Surface Area and Volume solutions
Class 9 Ganita Manjari Part 2 book questions with solutions

approximate number of complete cylindrical rods that can be formedcbse released class 9 ganita manjari part 2 bookchapter 14 math of space surface area and volume (ganita manjari 2) solutionsganita manjari part 2 solutions available!having radius 2 cm and height 12 cmsolid metallic cube of side 12 cm is melted
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    1 Answer

    1. (i) Volume of the cube is a³ = 12³ = 1728 cm³.

      (ii) Volume of one cylindrical rod is πr²h = (22/7) × 2² × 12 = (22/7) × 48 = 1056/7 ≈ 150.86 cm³.

      (iii) Number of complete rods is obtained by dividing total cube volume by one rod’s volume: 1728 ÷ (1056/7) = (1728 × 7) / 1056 = 12096 / 1056 ≈ 11.45, which gives 11 complete rods.

       

      For more NCERT Solutions of Class 9 Maths Ganita Manjari Part 2 Chapter 14 Math of Space: Surface Area and Volume Question Answer (2026-27)

      https://www.tiwariacademy.com/ncert-solutions/class-9/maths/ganita-manjari-chapter-14/

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