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The floor of a room is 5 m long and 4 m wide. A square carpet whose sides are 3 m in length is laid on the floor. Find the area that is not carpeted.
First, calculate the area of the room: Area of room = 5 × 4 = 20 square meters. Next, calculate the area of the square carpet: Area of carpet = 3 × 3 = 9 square meters. The area that is not carpeted is: Uncovered area = Area of room − Area of carpet Uncovered area = 20 − 9 = 11 square meters. Thus,Read more
First, calculate the area of the room:
Area of room = 5 × 4 = 20 square meters.
Next, calculate the area of the square carpet:
Area of carpet = 3 × 3 = 9 square meters.
The area that is not carpeted is:
Uncovered area = Area of room − Area of carpet
Uncovered area = 20 − 9 = 11 square meters.
Thus, 11 square meters of the floor remains uncovered.
For more NCERT Solutions for Class 6 Math Chapter 6 Perimeter and Area Extra Questions and Answer:
See lesshttps://www.tiwariacademy.com/ncert-solutions-class-6-maths-ganita-prakash-chapter-6/
Four flower beds having sides 2 m long and 1 m wide are dug at the four corners of a garden that is 15 m long and 12 m wide. How much area is now available for laying down a lawn?
First, calculate the total area of the garden: Garden area = 15 × 12 = 180 square meters. Next, calculate the area of one flower bed: Area of one flower bed = 2 × 1 = 2 square meters. For four flower beds: Total flower bed area = 4 × 2 = 8 square meters. The area available for laying a lawn is: RemaRead more
First, calculate the total area of the garden:
Garden area = 15 × 12 = 180 square meters.
Next, calculate the area of one flower bed:
Area of one flower bed = 2 × 1 = 2 square meters.
For four flower beds:
Total flower bed area = 4 × 2 = 8 square meters.
The area available for laying a lawn is:
Remaining area = Garden area − Flower bed area
Remaining area = 180 − 8 = 172 square meters.
For more NCERT Solutions for Class 6 Math Chapter 6 Perimeter and Area Extra Questions and Answer:
See lesshttps://www.tiwariacademy.com/ncert-solutions-class-6-maths-ganita-prakash-chapter-6/
Shape A has an area of 18 square units and Shape B has an area of 20 square units. Shape A has a longer perimeter than Shape B. Draw two such shapes satisfying the given conditions.
For Shape A: Dimensions = 1 unit × 18 units Area = 1 × 18 = 18 square units Perimeter = 2 × (1 + 18) = 38 units. For Shape B: Dimensions = 4 units × 5 units Area = 4 × 5 = 20 square units Perimeter = 2 × (4 + 5) = 18 units. Thus, Shape A with a longer perimeter and Shape B with a smaller perimeter sRead more
For Shape A:
Dimensions = 1 unit × 18 units
Area = 1 × 18 = 18 square units
Perimeter = 2 × (1 + 18) = 38 units.
For Shape B:
Dimensions = 4 units × 5 units
Area = 4 × 5 = 20 square units
Perimeter = 2 × (4 + 5) = 18 units.
Thus, Shape A with a longer perimeter and Shape B with a smaller perimeter satisfy the given conditions.
For more NCERT Solutions for Class 6 Math Chapter 6 Perimeter and Area Extra Questions and Answer:
See lesshttps://www.tiwariacademy.com/ncert-solutions-class-6-maths-ganita-prakash-chapter-6/
On a page in your book, draw a rectangular border that is 1 cm from the top and bottom and 1.5 cm from the left and right sides. What is the perimeter of the border?
Let the original dimensions of the page be Length (L) and Width (W). Reduced dimensions: Reduced Length = L − 2 (1 cm from top and bottom = 2 cm) Reduced Width = W − 3 (1.5 cm from left and right = 3 cm) Perimeter of the border: Perimeter = 2 × (Reduced Length + Reduced Width) Substitute the given vRead more
Let the original dimensions of the page be Length (L) and Width (W).
Reduced dimensions:
Reduced Length = L − 2 (1 cm from top and bottom = 2 cm)
Reduced Width = W − 3 (1.5 cm from left and right = 3 cm)
Perimeter of the border:
Perimeter = 2 × (Reduced Length + Reduced Width)
Substitute the given values of Length and Width to find the final perimeter.
For more NCERT Solutions for Class 6 Math Chapter 6 Perimeter and Area Extra Questions and Answer:
See lesshttps://www.tiwariacademy.com/ncert-solutions-class-6-maths-ganita-prakash-chapter-6/
Draw a rectangle of size 12 units × 8 units. Draw another rectangle inside it, without touching the outer rectangle that occupies exactly half the area.
The area of the outer rectangle is calculated as: Area = Length × Width = 12 × 8 = 96 square units. Half the area is: Half Area = 96 ÷ 2 = 48 square units. For the inner rectangle to have this area, one possible set of dimensions is: Length = 8 units, Width = 6 units. Verification: Area of inner recRead more
The area of the outer rectangle is calculated as:
Area = Length × Width = 12 × 8 = 96 square units.
Half the area is:
Half Area = 96 ÷ 2 = 48 square units.
For the inner rectangle to have this area, one possible set of dimensions is:
Length = 8 units, Width = 6 units.
Verification:
Area of inner rectangle = 8 × 6 = 48 square units, which is exactly half of 96.
Thus, the inner rectangle can be 8 units × 6 units.
For more NCERT Solutions for Class 6 Math Chapter 6 Perimeter and Area Extra Questions and Answer:
See lesshttps://www.tiwariacademy.com/ncert-solutions-class-6-maths-ganita-prakash-chapter-6/