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Use your understanding from previous grades to calculate the area of any closed figure using grid paper and— 2. Find the area of red triangle ABE.
To find the area of triangle ABE, divide it into two smaller triangles, AEF and BEF. Each of these smaller triangles is half the area of their respective rectangles (AFED and BFEC). By adding these two areas, you get the total area of triangle ABE. Since these smaller triangles together represent haRead more
To find the area of triangle ABE, divide it into two smaller triangles, AEF and BEF. Each of these smaller triangles is half the area of their respective rectangles (AFED and BFEC). By adding these two areas, you get the total area of triangle ABE. Since these smaller triangles together represent half of the rectangle ABCD, the total area of triangle ABE equals half the area of rectangle ABCD. This calculation is verified using grid paper.
For more NCERT Solutions for Class 6 Math Chapter 6 Perimeter and Area Extra Questions and Answer:
See lesshttps://www.tiwariacademy.com/ncert-solutions-class-6-maths-ganita-prakash-chapter-6/
What is the conclusion based on the relationship between areas of triangles and rectangles?
The conclusion is that the diagonal of a rectangle divides it into two triangles of equal area, with each triangle's area being half the total area of the rectangle. When additional triangles are formed by further divisions within the rectangle, their areas can also be calculated as fractions of smaRead more
The conclusion is that the diagonal of a rectangle divides it into two triangles of equal area, with each triangle’s area being half the total area of the rectangle. When additional triangles are formed by further divisions within the rectangle, their areas can also be calculated as fractions of smaller rectangles. This relationship between triangles and rectangles remains consistent regardless of the rectangle’s size or the dimensions of the divided sections.
For more NCERT Solutions for Class 6 Math Chapter 6 Perimeter and Area Extra Questions and Answer:
See lesshttps://www.tiwariacademy.com/ncert-solutions-class-6-maths-ganita-prakash-chapter-6/
Find the areas of the figures below by dividing them into rectangles and triangles.
To calculate the area of each figure, divide the irregular shapes into smaller rectangles and triangles. Use the formula for the area of a rectangle (length multiplied by width) for the rectangular sections. For the triangular sections, apply the formula (base multiplied by height divided by 2). SumRead more
To calculate the area of each figure, divide the irregular shapes into smaller rectangles and triangles. Use the formula for the area of a rectangle (length multiplied by width) for the rectangular sections. For the triangular sections, apply the formula (base multiplied by height divided by 2). Sum the areas of all the sections to determine the total area of the figure. Using grid paper can simplify this process by counting squares and dividing accordingly.
For more NCERT Solutions for Class 6 Math Chapter 6 Perimeter and Area Extra Questions and Answer:
See lesshttps://www.tiwariacademy.com/ncert-solutions-class-6-maths-ganita-prakash-chapter-6/
Give the dimensions of a rectangle whose area is the sum of the areas of these two rectangles having measurements: 5 m × 10 m and 2 m × 7 m.
Calculate the areas of both rectangles: Area 1 = 5 × 10 = 50 square meters Area 2 = 2 × 7 = 14 square meters Add them together to get the total area: Total Area = 50 + 14 = 64 square meters. A square with dimensions 8 meters × 8 meters satisfies this, as: Area = 8 × 8 = 64 square meters. Thus, the dRead more
Calculate the areas of both rectangles:
Area 1 = 5 × 10 = 50 square meters
Area 2 = 2 × 7 = 14 square meters
Add them together to get the total area:
Total Area = 50 + 14 = 64 square meters.
A square with dimensions 8 meters × 8 meters satisfies this, as:
Area = 8 × 8 = 64 square meters.
Thus, the dimensions of the required rectangle are 8 m × 8 m.
For more NCERT Solutions for Class 6 Math Chapter 6 Perimeter and Area Extra Questions and Answer:
See lesshttps://www.tiwariacademy.com/ncert-solutions-class-6-maths-ganita-prakash-chapter-6/
The area of a rectangular garden that is 50 m long is 1000 sq m. Find the width of the garden.
Use the formula for the area of a rectangle: Area = Length × Width. Here, Area = 1000 square meters, and Length = 50 meters. Rearrange to find the width: Width = Area ÷ Length Width = 1000 ÷ 50 = 20 meters. Thus, the width of the garden is 20 meters. For more NCERT Solutions for Class 6 Math ChapterRead more
Use the formula for the area of a rectangle:
Area = Length × Width.
Here, Area = 1000 square meters, and Length = 50 meters. Rearrange to find the width:
Width = Area ÷ Length
Width = 1000 ÷ 50 = 20 meters.
Thus, the width of the garden is 20 meters.
For more NCERT Solutions for Class 6 Math Chapter 6 Perimeter and Area Extra Questions and Answer:
See lesshttps://www.tiwariacademy.com/ncert-solutions-class-6-maths-ganita-prakash-chapter-6/