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Give the dimensions of a rectangle whose area is the sum of the areas of these two rectangles having measurements: 5 m × 10 m and 2 m × 7 m.
Calculate the areas of both rectangles: Area 1 = 5 × 10 = 50 square meters Area 2 = 2 × 7 = 14 square meters Add them together to get the total area: Total Area = 50 + 14 = 64 square meters. A square with dimensions 8 meters × 8 meters satisfies this, as: Area = 8 × 8 = 64 square meters. Thus, the dRead more
Calculate the areas of both rectangles:
Area 1 = 5 × 10 = 50 square meters
Area 2 = 2 × 7 = 14 square meters
Add them together to get the total area:
Total Area = 50 + 14 = 64 square meters.
A square with dimensions 8 meters × 8 meters satisfies this, as:
Area = 8 × 8 = 64 square meters.
Thus, the dimensions of the required rectangle are 8 m × 8 m.
For more NCERT Solutions for Class 6 Math Chapter 6 Perimeter and Area Extra Questions and Answer:
See lesshttps://www.tiwariacademy.com/ncert-solutions-class-6-maths-ganita-prakash-chapter-6/
The area of a rectangular garden that is 50 m long is 1000 sq m. Find the width of the garden.
Use the formula for the area of a rectangle: Area = Length × Width. Here, Area = 1000 square meters, and Length = 50 meters. Rearrange to find the width: Width = Area ÷ Length Width = 1000 ÷ 50 = 20 meters. Thus, the width of the garden is 20 meters. For more NCERT Solutions for Class 6 Math ChapterRead more
Use the formula for the area of a rectangle:
Area = Length × Width.
Here, Area = 1000 square meters, and Length = 50 meters. Rearrange to find the width:
Width = Area ÷ Length
Width = 1000 ÷ 50 = 20 meters.
Thus, the width of the garden is 20 meters.
For more NCERT Solutions for Class 6 Math Chapter 6 Perimeter and Area Extra Questions and Answer:
See lesshttps://www.tiwariacademy.com/ncert-solutions-class-6-maths-ganita-prakash-chapter-6/
The floor of a room is 5 m long and 4 m wide. A square carpet whose sides are 3 m in length is laid on the floor. Find the area that is not carpeted.
First, calculate the area of the room: Area of room = 5 × 4 = 20 square meters. Next, calculate the area of the square carpet: Area of carpet = 3 × 3 = 9 square meters. The area that is not carpeted is: Uncovered area = Area of room − Area of carpet Uncovered area = 20 − 9 = 11 square meters. Thus,Read more
First, calculate the area of the room:
Area of room = 5 × 4 = 20 square meters.
Next, calculate the area of the square carpet:
Area of carpet = 3 × 3 = 9 square meters.
The area that is not carpeted is:
Uncovered area = Area of room − Area of carpet
Uncovered area = 20 − 9 = 11 square meters.
Thus, 11 square meters of the floor remains uncovered.
For more NCERT Solutions for Class 6 Math Chapter 6 Perimeter and Area Extra Questions and Answer:
See lesshttps://www.tiwariacademy.com/ncert-solutions-class-6-maths-ganita-prakash-chapter-6/
Four flower beds having sides 2 m long and 1 m wide are dug at the four corners of a garden that is 15 m long and 12 m wide. How much area is now available for laying down a lawn?
First, calculate the total area of the garden: Garden area = 15 × 12 = 180 square meters. Next, calculate the area of one flower bed: Area of one flower bed = 2 × 1 = 2 square meters. For four flower beds: Total flower bed area = 4 × 2 = 8 square meters. The area available for laying a lawn is: RemaRead more
First, calculate the total area of the garden:
Garden area = 15 × 12 = 180 square meters.
Next, calculate the area of one flower bed:
Area of one flower bed = 2 × 1 = 2 square meters.
For four flower beds:
Total flower bed area = 4 × 2 = 8 square meters.
The area available for laying a lawn is:
Remaining area = Garden area − Flower bed area
Remaining area = 180 − 8 = 172 square meters.
For more NCERT Solutions for Class 6 Math Chapter 6 Perimeter and Area Extra Questions and Answer:
See lesshttps://www.tiwariacademy.com/ncert-solutions-class-6-maths-ganita-prakash-chapter-6/
Shape A has an area of 18 square units and Shape B has an area of 20 square units. Shape A has a longer perimeter than Shape B. Draw two such shapes satisfying the given conditions.
For Shape A: Dimensions = 1 unit × 18 units Area = 1 × 18 = 18 square units Perimeter = 2 × (1 + 18) = 38 units. For Shape B: Dimensions = 4 units × 5 units Area = 4 × 5 = 20 square units Perimeter = 2 × (4 + 5) = 18 units. Thus, Shape A with a longer perimeter and Shape B with a smaller perimeter sRead more
For Shape A:
Dimensions = 1 unit × 18 units
Area = 1 × 18 = 18 square units
Perimeter = 2 × (1 + 18) = 38 units.
For Shape B:
Dimensions = 4 units × 5 units
Area = 4 × 5 = 20 square units
Perimeter = 2 × (4 + 5) = 18 units.
Thus, Shape A with a longer perimeter and Shape B with a smaller perimeter satisfy the given conditions.
For more NCERT Solutions for Class 6 Math Chapter 6 Perimeter and Area Extra Questions and Answer:
See lesshttps://www.tiwariacademy.com/ncert-solutions-class-6-maths-ganita-prakash-chapter-6/